Пример #1
0
    def pos(self, xs, ys, ds, last=3, sort=True):
        if not sort:
            if last == 1:
                x2, x3, x1 = list(xs)
                y2, y3, y1 = list(ys)
                d2, d3, d1 = ds
            elif last == 2:
                x3, x1, x2 = list(xs)
                y3, y1, y2 = list(ys)
                d3, d1, d2 = ds
            else:
                x1, x2, x3 = list(xs)
                y1, y2, y3 = list(ys)
                d1, d2, d3 = ds
        else:
            index = np.argsort(ds)
            x1, x2, x3 = list(xs[index])
            y1, y2, y3 = list(ys[index])
            d1, d2, d3 = list(np.array(ds)[index])

        x = symbol.Symbol('x')
        y = symbol.Symbol('y')
        sol = solve([(x - x1)**2 + (y - y1)**2 - d1**2,
                     (x - x2)**2 + (y - y2)**2 - d2**2], [x, y],
                    dict=False)
        rx = 0
        ry = 0
        min_loss = 9999
        try:
            for s in sol:
                loss = abs((s[0] - x3)**2 + (s[1] - y3)**2 - d3**2)
                if loss < min_loss:
                    min_loss = loss
                    rx = s[0]
                    ry = s[1]
        except TypeError:
            return np.random.random() * self.x_range, np.random.random(
            ) * self.y_range
        return rx, ry
Пример #2
0
 def pos(self, xs, ys, ds):
     x1, x2, x3 = list(xs)
     y1, y2, y3 = list(ys)
     d1, d2, d3 = list(ds)
     x = symbol.Symbol('x')
     y = symbol.Symbol('y')
     sol = solve([(x - x1)**2 + (y - y1)**2 - d1**2,
                  (x - x2)**2 + (y - y2)**2 - d2**2], [x, y],
                 dict=False)
     rx = 0
     ry = 0
     min_loss = 9999
     try:
         for s in sol:
             loss = abs((s[0] - x3)**2 + (s[1] - y3)**2 - d3**2)
             if loss < min_loss:
                 min_loss = loss
                 rx = s[0]
                 ry = s[1]
     except TypeError:
         return np.random.random() * self.x_range, np.random.random(
         ) * self.y_range
     return rx, ry
Пример #3
0
def test_Newton():
    from sympy import symbol, diff, lambdify

    x = symbol.Symbol('x')  # определяем математический символ x
    f_expr = x**2 - 4  # символьное выражение для f(x)
    dfdx_expr = diff(f_expr, x)  # вычисляем символьно f'(x)

    # Преобразуем f_expr и dfdx_expr в обычные функции Python
    f = lambdify(
        [x],  # аргумент f
        f_expr)
    dfdx = lambdify([x], dfdx_expr)

    tol = 1e-3
    computed, no_iterations = Newton(f, dfdx, x=1, eps=tol)
    expected = 2.
    success = np.abs(computed - expected) <= tol
    msg = 'expected = {},\n computed = {}, Число итераций = {}'.format(
        expected, computed, no_iterations)
    assert success, msg
Пример #4
0
    def run(self, robots):
        if(self.isBeacon == True):
            return

        if(self.z):
        	return

        for nei1 in self.dic_neighbors:
        	for nei2 in self.dic_neighbors:
        		if nei1!=nei2 and robots[nei1].z!=None and robots[nei2].z!=None:


        			print("index: ", self.id)
        			print("Nei1: ", nei1, "Nei2: ", nei2)

        			# print("Nei1 coord: ", robots[nei1].get_coord())
        			# print("Nei2 coord: ", robots[nei2].get_coord())


        			d1, d2, d3, d4 = measure(self.id, nei1, nei2)
        			# # print(d1, d2, d3, d4)
        			
        			# self.x, self.y, self.z = np.random.normal(loc=5, scale=5, size=(3, ))
        			# # self.x = self.y = self.z = 1
        			# def solve_dis(para):
        			# 	mpara = np.copy(para)
        			# 	mpara[2] -= 2
        			# 	return [
        			# 		distance(para, robots[nei1].get_coord())-d1,
        			# 		distance(para, robots[nei2].get_coord())-d2,
        			# 		distance(mpara, robots[nei1].get_coord())-d3,
        			# 	]

        			# sol = np.real(fsolve(solve_dis, np.array([self.x, self.y, self.z]), xtol=1e-6))

        			# self.x, self.y, self.z = sol

        			t = -2
        			x1 = robots[nei1].x
        			y1 = robots[nei1].y
        			z1 = robots[nei1].z

        			x2 = robots[nei2].x
        			y2 = robots[nei2].y
        			z2 = robots[nei2].z


        			self.z = (d3**2-d1**2+2*z1*t-t**2)/(2*t)

        			x = symbol.Symbol('x')
        			y = symbol.Symbol('y')
        			# z = symbol.Symbol('z')
        			# t = symbol.Symbol('t')


        			sol = solve([
        				solve_distance([x, y, self.z], robots[nei1].get_coord())-d1,
        				2*(x1-x2)*x+x2**2-x1**2 + 2*(y1-y2)*y+y2**2-y1**2 + 2*(z1-z2)*self.z+z2**-z1**2 -d2**2+d1**2
        				# solve_distance([x, y, self.z], robots[nei2].get_coord())-d2,
        				# solve_distance([x, y, z-2], robots[nei1].get_coord())-d3,
        				# solve_distance([x, y, z-2], robots[nei2].get_coord())-d4,
        				], [x, y], dict=False)

        			self.x, self.y = sol[0]

        			# # print(sol)

        			# self.x, self.y, self.z = sol[0]
        			# print("t: ", t)

        			# for s in sol:
        			# 	self.x, self.y, self.z, t = s
        			# 	print(t)



        			return
Пример #5
0
        mcoord, n1coord), distance(mcoord, n2coord)


def solve_distance(p1, p2):
    return ((p1[0] - p2[0])**2 + (p1[1] - p2[1])**2 + (p1[2] - p2[2])**2)**0.5


# nei1 = np.array([0, 2, 6])
# nei2 = np.array([-2, 2, 7])
# p = np.array([5, 1, 9])

nei1 = np.array([1, 1, 0])
nei2 = np.array([10, 10, 0])
p = np.array([5, 1, 3])

x = symbol.Symbol('x')
y = symbol.Symbol('y')
z = symbol.Symbol('z')
t = symbol.Symbol('t')

d = measure(p, nei1, nei2)
print(d)
print(d[2]**2 - d[0]**2, d[3]**2 - d[1]**2)

# sol = solve([
# 	solve_distance([x, y, z], nei1)-d[0],
# 	solve_distance([x, y, z], nei2)-d[1],
# 	solve_distance([x, y, z-2], nei1)-d[2],
# 	# solve_distance([x, y, z-t], nei2)-d[3]
# 	], [x, y, z], dict=False)
Пример #6
0

sol, no_iterations = Newton(f, dfdx, x=1.09, eps=1.0e-6)

if no_iterations > 0:
    print("Число вызовов функций f(x) = x**2: {}".format(1 +
                                                         2 * no_iterations))
    print("Решение: {}".format(sol))
else:
    print("Решение не найдено!")

# End 1st ex
# Использование символьных вычислений
from sympy import symbol, tanh, diff, lambdify

x = symbol.Symbol('x')  # определяем математический символ x
f_expr = tanh(x)  # символьное выражение для f(x)
dfdx_expr = diff(f_expr, x)  # вычисляем символьно f'(x)

# Преобразуем f_expr и dfdx_expr в обычные функции Python
f = lambdify(
    [x],  # аргумент f
    f_expr)
dfdx = lambdify([x], dfdx_expr)

tol = 1e-1
sol, no_iterations = Newton(f, dfdx, x=1.09, eps=tol)
if no_iterations > 0:
    print("Уравнение: tanh(x) = 0. Число итераций: {}".format(no_iterations))
    print("Решение: {}, eps = {}".format(sol, tol))
else: