def _shape(self):
# Get final matrix shape.
domain_dimension = sum(self._block_domain_dimensions())
range_dimension = sum(self._block_range_dimensions())
matrix_shape = tensor_shape.TensorShape([domain_dimension, range_dimension])
# Get broadcast batch shape.
# broadcast_shape checks for compatibility.
batch_shape = self.operators[0].batch_shape
for operator in self.operators[1:]:
batch_shape = common_shapes.broadcast_shape(
batch_shape, operator.batch_shape)
return batch_shape.concatenate(matrix_shape)
def _shape(self):
# Get final matrix shape.
domain_dimension = self.operators[0].domain_dimension
for operator in self.operators[1:]:
domain_dimension.assert_is_compatible_with(operator.range_dimension)
domain_dimension = operator.domain_dimension
matrix_shape = tensor_shape.TensorShape(
[self.operators[0].range_dimension,
self.operators[-1].domain_dimension])
# Get broadcast batch shape.
# broadcast_shape checks for compatibility.
batch_shape = self.operators[0].batch_shape
for operator in self.operators[1:]:
batch_shape = common_shapes.broadcast_shape(
batch_shape, operator.batch_shape)
return batch_shape.concatenate(matrix_shape)
def _solve(self, rhs, adjoint=False, adjoint_arg=False):
# Here we follow the same use of Roth's column lemma as in `matmul`, with
# the key difference that we replace all `matmul` instances with `solve`.
# This follows from the property that inv(A x B) = inv(A) x inv(B).
# Below we document the shape manipulation for adjoint=False,
# adjoint_arg=False, but the general case of different adjoints is still
# handled.
if adjoint_arg:
rhs = linalg.adjoint(rhs)
# Always add a batch dimension to enable broadcasting to work.
batch_shape = self._compute_ones_matrix_shape()
rhs = rhs + array_ops.zeros(batch_shape, dtype=rhs.dtype)
# rhs has shape [B, R, C], where B represent some number of batch
# dimensions,
# R represents the number of rows, and C represents the number of columns.
# In order to apply Roth's column lemma, we need to operate on a batch of
# column vectors, so we reshape into a batch of column vectors. We put it
# at the front to ensure that broadcasting between operators to the batch
# dimensions B still works.
output = _rotate_last_dim(rhs, rotate_right=True)
# Also expand the shape to be [A, C, B, R]. The first dimension will be
# used to accumulate dimensions from each operator matmul.
output = output[_ops.newaxis, ...]
# In this loop, A is going to refer to the value of the accumulated
# dimension. A = 1 at the start, and will end up being self.range_dimension.
# V will refer to the last dimension. V = R at the start, and will end up
# being 1 in the end.
for operator in self.operators[:-1]:
# Reshape output from [A, C, B, V] to be
# [A, C, B, V / op.domain_dimension, op.domain_dimension]
if adjoint:
operator_dimension = operator.range_dimension_tensor()
else:
operator_dimension = operator.domain_dimension_tensor()
output = _unvec_by(output, operator_dimension)
# We are computing (XA^-1^T) = (A^-1 X^T)^T.
# output has [A, C, B, V / op.domain_dimension, op.domain_dimension],
# which is being converted to:
# [A, C, B, V / op.domain_dimension, op.range_dimension]
output = _linalg.matrix_transpose(output)
output = operator.solve(output, adjoint=adjoint, adjoint_arg=False)
output = _linalg.matrix_transpose(output)
# Rearrange it to [A * op.range_dimension, C, B, V / op.domain_dimension]
output = _rotate_last_dim(output, rotate_right=False)
output = _vec(output)
output = _rotate_last_dim(output, rotate_right=True)
# After the loop, we will have
# A = self.range_dimension / op[-1].range_dimension
# V = op[-1].domain_dimension
# We convert that using matvec to get:
# [A, C, B, op[-1].range_dimension]
output = self.operators[-1].solvevec(output, adjoint=adjoint)
# Rearrange shape to be [B1, ... Bn, self.range_dimension, C]
output = _rotate_last_dim(output, rotate_right=False)
output = _vec(output)
output = _rotate_last_dim(output, rotate_right=False)
if tensor_shape.TensorShape(rhs.shape).is_fully_defined():
column_dim = tensor_shape.TensorShape(rhs.shape)[-1]
broadcast_batch_shape = common_shapes.broadcast_shape(
tensor_shape.TensorShape(rhs.shape)[:-2], self.batch_shape)
if adjoint:
matrix_dimensions = [self.domain_dimension, column_dim]
else:
matrix_dimensions = [self.range_dimension, column_dim]
tensorshape_util.set_shape(
output, broadcast_batch_shape.concatenate(matrix_dimensions))
return output
def _matmul(self, x, adjoint=False, adjoint_arg=False):
# Here we heavily rely on Roth's column Lemma [1]:
# (A x B) * vec X = vec BXA^T,
# where vec stacks all the columns of the matrix under each other. In our
# case, x represents a batch of vec X (i.e. we think of x as a batch of
# column vectors, rather than a matrix). Each member of the batch can be
# reshaped to a matrix (hence we get a batch of matrices).
# We can iteratively apply this lemma by noting that if B is a Kronecker
# product, then we can apply the lemma again.
# [1] W. E. Roth, "On direct product matrices,"
# Bulletin of the American Mathematical Society, vol. 40, pp. 461-468,
# 1934
# Efficiency
# Naively doing the Kronecker product, by calculating the dense matrix and
# applying it will can take cubic time in the size of domain_dimension
# (assuming a square matrix). The other issue is that calculating the dense
# matrix can be prohibitively expensive, in that it can take a large amount
# of memory.
#
# This implementation avoids this memory blow up by only computing matmuls
# with the factors. In this way, we don't have to realize the dense matrix.
# In terms of complexity, if we have Kronecker Factors of size:
# (n1, n1), (n2, n2), (n3, n3), ... (nJ, nJ), with N = \prod n_i, and we
# have as input a [N, M] matrix, the naive approach would take O(N^2 M).
# With this approach (ignoring reshaping of tensors and transposes for now),
# the time complexity can be O(M * (\sum n_i) * N). There is also the
# benefit of batched multiplication (In this example, the batch size is
# roughly M * N) so this can be much faster. However, not factored in are
# the costs of the several transposing of tensors, which can affect cache
# behavior.
# Below we document the shape manipulation for adjoint=False,
# adjoint_arg=False, but the general case of different adjoints is still
# handled.
if adjoint_arg:
x = linalg.adjoint(x)
# Always add a batch dimension to enable broadcasting to work.
batch_shape = self._compute_ones_matrix_shape()
x = x + array_ops.zeros(batch_shape, dtype=x.dtype)
# x has shape [B, R, C], where B represent some number of batch dimensions,
# R represents the number of rows, and C represents the number of columns.
# In order to apply Roth's column lemma, we need to operate on a batch of
# column vectors, so we reshape into a batch of column vectors. We put it
# at the front to ensure that broadcasting between operators to the batch
# dimensions B still works.
output = _rotate_last_dim(x, rotate_right=True)
# Also expand the shape to be [A, C, B, R]. The first dimension will be
# used to accumulate dimensions from each operator matmul.
output = output[_ops.newaxis, ...]
# In this loop, A is going to refer to the value of the accumulated
# dimension. A = 1 at the start, and will end up being self.range_dimension.
# V will refer to the last dimension. V = R at the start, and will end up
# being 1 in the end.
for operator in self.operators[:-1]:
# Reshape output from [A, C, B, V] to be
# [A, C, B, V / op.domain_dimension, op.domain_dimension]
if adjoint:
operator_dimension = operator.range_dimension_tensor()
else:
operator_dimension = operator.domain_dimension_tensor()
output = _unvec_by(output, operator_dimension)
# We are computing (XA^T) = (AX^T)^T.
# output has [A, C, B, V / op.domain_dimension, op.domain_dimension],
# which is being converted to:
# [A, C, B, V / op.domain_dimension, op.range_dimension]
output = _linalg.matrix_transpose(output)
output = operator.matmul(output,
adjoint=adjoint,
adjoint_arg=False)
output = _linalg.matrix_transpose(output)
# Rearrange it to [A * op.range_dimension, C, B, V / op.domain_dimension]
output = _rotate_last_dim(output, rotate_right=False)
output = _vec(output)
output = _rotate_last_dim(output, rotate_right=True)
# After the loop, we will have
# A = self.range_dimension / op[-1].range_dimension
# V = op[-1].domain_dimension
# We convert that using matvec to get:
# [A, C, B, op[-1].range_dimension]
output = self.operators[-1].matvec(output, adjoint=adjoint)
# Rearrange shape to be [B1, ... Bn, self.range_dimension, C]
output = _rotate_last_dim(output, rotate_right=False)
output = _vec(output)
output = _rotate_last_dim(output, rotate_right=False)
if tensor_shape.TensorShape(x.shape).is_fully_defined():
column_dim = tensor_shape.TensorShape(x.shape)[-1]
broadcast_batch_shape = common_shapes.broadcast_shape(
tensor_shape.TensorShape(x.shape)[:-2], self.batch_shape)
if adjoint:
matrix_dimensions = [self.domain_dimension, column_dim]
else:
matrix_dimensions = [self.range_dimension, column_dim]
tensorshape_util.set_shape(
output, broadcast_batch_shape.concatenate(matrix_dimensions))
return output
def _bcast_shape(base_shape, args):
bcast_shape = _ensure_shape_tuple(base_shape)
for arg in args:
bcast_shape = ops.broadcast_shape(bcast_shape, np.asarray(arg).shape)
return bcast_shape
def _solve_matmul_internal(self,
x,
solve_matmul_fn,
adjoint=False,
adjoint_arg=False):
# We heavily rely on Roth's column Lemma [1]:
# (A x B) * vec X = vec BXA^T
# where vec stacks all the columns of the matrix under each other.
# In our case, we use a variant of the lemma that is row-major
# friendly: (A x B) * vec' X = vec' AXB^T
# Where vec' reshapes a matrix into a vector. We can repeatedly apply this
# for a collection of kronecker products.
# Given that (A x B)^-1 = A^-1 x B^-1 and (A x B)^T = A^T x B^T, we can
# use the above to compute multiplications, solves with any composition of
# transposes.
output = x
if adjoint_arg:
if np.issubdtype(self.dtype, np.complexfloating):
output = math_ops.conj(output)
else:
output = linalg.transpose(output)
for o in reversed(self.operators):
# Statically compute the reshape.
if adjoint:
operator_dimension = o.range_dimension_tensor()
else:
operator_dimension = o.domain_dimension_tensor()
output_shape = _prefer_static_shape(output)
if ops.get_static_value(operator_dimension) is not None:
operator_dimension = ops.get_static_value(operator_dimension)
if tensor_shape.TensorShape(
output.shape
)[-2] is not None and tensor_shape.TensorShape(
output.shape)[-1] is not None:
dim = int(
tensor_shape.TensorShape(output.shape)[-2] *
output_shape[-1] // operator_dimension)
else:
dim = _ops.cast(output_shape[-2] * output_shape[-1] //
operator_dimension,
dtype=dtypes.int32)
output_shape = _prefer_static_concat_shape(
output_shape[:-2], [dim, operator_dimension])
output = array_ops.reshape(output, shape=output_shape)
# Conjugate because we are trying to compute A @ B^T, but
# `LinearOperator` only supports `adjoint_arg`.
if np.issubdtype(self.dtype, np.complexfloating):
output = math_ops.conj(output)
output = solve_matmul_fn(o,
output,
adjoint=adjoint,
adjoint_arg=True)
if adjoint_arg:
col_dim = _prefer_static_shape(x)[-2]
else:
col_dim = _prefer_static_shape(x)[-1]
if adjoint:
row_dim = self.domain_dimension_tensor()
else:
row_dim = self.range_dimension_tensor()
matrix_shape = [row_dim, col_dim]
output = array_ops.reshape(
output,
_prefer_static_concat_shape(
_prefer_static_shape(output)[:-2], matrix_shape))
if tensor_shape.TensorShape(x.shape).is_fully_defined():
if adjoint_arg:
column_dim = tensor_shape.TensorShape(x.shape)[-2]
else:
column_dim = tensor_shape.TensorShape(x.shape)[-1]
broadcast_batch_shape = common_shapes.broadcast_shape(
tensor_shape.TensorShape(x.shape)[:-2], self.batch_shape)
if adjoint:
matrix_dimensions = [self.domain_dimension, column_dim]
else:
matrix_dimensions = [self.range_dimension, column_dim]
tensorshape_util.set_shape(
output, broadcast_batch_shape.concatenate(matrix_dimensions))
return output
