Пример #1
0
    d2 = []
    # if lca exist
    if lca:
        # distance of n1 from lca
        findLevel(lca, n1, d1, 0)
        # distance of n2 from lca
        findLevel(lca, n2, d2, 0)
        return d1[0] + d2[0]
    else:
        return -1


# Driver program to test above function
root = Node(1)
root.left = Node(2)
root.right = Node(3)
root.left.left = Node(4)
root.left.right = Node(5)
root.right.left = Node(6)
root.right.right = Node(7)
root.right.left.right = Node(8)

root.display()
# root.prettyPrint()

print("Dist(4,5) = ", findDistance(root, 4, 5))
print("Dist(4,6) = ", findDistance(root, 4, 6))
print("Dist(3,4) = ", findDistance(root, 3, 4))
print("Dist(2,4) = ", findDistance(root, 2, 4))
print("Dist(8,5) = ", findDistance(root, 8, 5))