Пример #1
0
        :rtype: int
        """
        self.queue = [[], []]
        self.count = []
        self.queue[0].append(root)
        self.bfs(0)
        return self.count.index(max(self.count)) + 1

    def bfs(self, i):
        self.count.append(0)
        currentQ = self.queue[i % 2]
        nextQ = self.queue[(i+1) % 2]
        nextQ.clear()
        while currentQ:
            item = currentQ.pop()
            self.count[i] += item.val
            if item.left:
                nextQ.append(item.left)
            if item.right:
                nextQ.append(item.right)
        if nextQ:
            self.bfs(i+1)


if __name__ == "__main__":
    s = Solution()
    l = [1, 7, 0, 7, -8, None, None]
    l = [1, 7, 0, 7, -8, None, None, 4, None, None, None, 11]
    root = initial_tree(l)
    print(s.maxLevelSum(root))
Пример #2
0
                    elif op == 'left':
                        parent.left = node.left
                    else:
                        parent.right = node.left
                else:
                    p = node.right
                    while p.left:
                        p = p.left
                    p.left = node.left
                    if not op:
                        root = node.right
                    else:
                        if op == 'left':
                            parent.left = node.right
                        else:
                            parent.right = node.right
                node = None
        return root


if __name__ == "__main__":
    s = Solution2()
    root = [5, 3, 6, 2, 4, None, 7]
    # root = []
    # root = [3]
    root = [1, None, 2]
    root = initial_tree(root)
    key = 3
    key = 2
    print(s.deleteNode(root, key))
Пример #3
0
思路:
深度遍歷 廣度遍歷
"""
from tree_util import initial_tree, TreeNode
from typing import List


class Solution:
    def rightSideView(self, root: TreeNode) -> List[int]:
        if not root:
            return []
        queue = [(root, 0)]
        result = []
        layout = -1
        while queue:
            item = queue.pop(0)  # 出隊
            if item[1] != layout:
                layout = item[1]
                result.append(item[0].val)
            if item[0].right:
                queue.append((item[0].right, item[1] + 1))
            if item[0].left:
                queue.append((item[0].left, item[1] + 1))
        return result


if __name__ == "__main__":
    s = Solution()
    l = [1, 2, 3, None, 5, None, 4]  # [1, 3, 4]
    print(s.rightSideView(initial_tree(l)))
Пример #4
0
   -3   9
   /   /
 -10  5
"""
from typing import List
from tree_util import TreeNode, initial_tree


class Solution:
    def sortedArrayToBST(self, nums: List[int]) -> TreeNode:
        def helper(left, right):
            if left > right:
                return None

            # 总是选择中间位置左边的数字作为根节点
            mid = (left + right) // 2

            root = TreeNode(nums[mid])
            root.left = helper(left, mid - 1)
            root.right = helper(mid + 1, right)
            return root

        return helper(0, len(nums) - 1)


if __name__ == "__main__":
    s = Solution()
    nums = [-10, -3, 0, 5, 9]
    r = s.sortedArrayToBST(nums)
    assert r == initial_tree([0, -3, 9, -10, None, 5]), f"case 1 neq"
Пример #5
0
            rightGain = maxGain(node.right)
            # 需要返回的该节点最大贡献度 (为单一子树)
            nodeGain = node.val + max(0, leftGain, rightGain)
            # 计算该节点的最大路径和要把两个子树都算上
            nodeSum = node.val + max(0, leftGain) + max(0, rightGain)
            maxSum = max(maxSum, nodeSum)
            return nodeGain

        maxGain(root)

        return maxSum


if __name__ == "__main__":
    s = Solution()
    # _list = [1, 2, 3]
    # root = initial_tree(_list)
    # assert s.maxPathSum(root) == 6, 'case 1'
    # _list = [-10, 9, 20, None, None, 15, 7]
    # root = initial_tree(_list)
    # assert s.maxPathSum(root) == 42, 'case 2'
    # _list = [1]
    # root = initial_tree(_list)
    # assert s.maxPathSum(root) == 1, 'case 3'
    _list = [5, 4, 8, 11, None, 13, 4, 7, 2, None, None, None, 1]
    root = initial_tree(_list)
    assert s.maxPathSum(root) == 48, f'case 4: {s.maxPathSum(root)} neq 48'
    _list = [9, 6, -3, None, None, -6, 2, None, None, 2, None, -6, -6, -6]
    root = initial_tree(_list)
    assert s.maxPathSum(root) == 16, f'case 5: {s.maxPathSum(root)} neq 16'
Пример #6
0
        self.result = list()

    def findTilt(self, root):
        """
        :type root: TreeNode
        :rtype: int
        """
        self.walkTree(root)
        return sum(self.result)

    def walkTree(self, s):
        """
        迭代实现
        :type s: TreeNode
        """
        if s is None:
            return 0
        left_sum = self.walkTree(s.left)
        right_sum = self.walkTree(s.right)
        s_node_value = abs(left_sum - right_sum)
        self.result.append(s_node_value)
        return s.val + left_sum + right_sum


if __name__ == '__main__':
    # l = [-8, 3, 0, -8, None, None, None, None, -1, None, 8]
    l = [1, 2, 3]
    tree = initial_tree(l)
    s = Solution()
    print(s.findTilt(tree))