while slow and fast:
            slow = slow.next
            fast = fast.next
        return slow

    def removeKthFromEnd(self, head, k):
        fast = head
        slow = head
        pre = None

        i = k
        while i > 0:
            fast = fast.next
            i = i-1
        if fast==None:
            head = slow.next
            return head

        while fast!=None:
            pre = slow
            slow = slow.next
            fast = fast.next

        pre.next = slow.next
        slow.next = None
        return head

head = construct_List_I([1, 2, 3, 4, 5])
solu = Solution()
print(solu.findKthFromEnd(head, 5).val)
print(travel_List(head))
        while cur1 and cur2:
            if cur1.val <= cur2.val:
                cur.next = cur1
                cur = cur1
                cur1 = cur1.next
            else:
                cur.next = cur2
                cur = cur2
                cur2 = cur2.next

        while cur1:
            cur.next = cur1
            cur = cur1
            cur1 = cur1.next
        while cur2:
            cur.next = cur2
            cur = cur2
            cur2 = cur2.next
        cur.next = None

        return head


from utils import construct_List_I, travel_List
l1 = construct_List_I([1, 2, 4])
l2 = construct_List_I([1, 3, 4])
solu = Solution()
l3 = solu.mergeTwoLists(l1, l2)
print(travel_List(l3))
Пример #3
0
        while i < m:
            if cur == None:
                return root
            pre_head = cur
            cur = cur.next
            i += 1

        # pre_head为第m-1个节点,cur为第m个节点,此时i=m
        reverse_start = cur
        reverse_end = cur
        cur = cur.next

        while i < n:
            next = cur.next
            cur.next = reverse_start
            reverse_start = cur
            cur = next
            i += 1
        reverse_end.next = cur
        if pre_head == None:
            return reverse_start
        else:
            pre_head.next = reverse_start
            return root


root = construct_List_I([1, 2, 3, 4, 5, 6])
solu = Solution()
root = solu.reverseList_II(root, 1, 6)
print(solu.travelList(root))

class Solution:
    def deleteNode(self, cur):
        # 题目237
        cur.val = cur.next.val
        cur.next = cur.next.next

    def removeElements(self, root, val):
        # 题目203
        cur = root
        pre = None
        while cur != None:
            if cur.val == val:
                if pre == None:
                    root = cur.next
                    cur = cur.next
                else:
                    pre.next = cur.next
                    cur = cur.next
            else:
                pre = cur
                cur = cur.next
        return root


head = construct_List_I([1, 2, 1, 4, 1])
solu = Solution()

head = solu.removeElements(head, 1)
print(travel_List(head))
            else:
                pre = cur
            cur = cur.next
        return root

    def deleteDuplicates(self, head):
        '''
        第一个重复点保留,后面的重复点都删除
        输入: 1->1->2->3->3
        输出: 1->2->3
        '''
        pre = None
        cur = head
        while cur:
            if pre and pre.val == cur.val:
                while pre and cur:
                    if pre.val == cur.val:
                        cur = cur.next
                    else:
                        break
                pre.next = cur
            else:
                pre = cur
                cur = cur.next
        return head


slou = Solution()
root = construct_List_I([2, 2, 4, 4, 4])
root = slou.deleteDuplicates(root)
print(travel_List(root))