Пример #1
0
 def get_bow_points(self):
     bow_obj = bpy.data.objects["bow"]
     #only do this once, for efficency
     vertex_groups = utils.getVertGroups(bow_obj)
     frog = utils.mean_of_vertex_group(bow_obj, vertex_groups, "hair-frog")
     tip = utils.mean_of_vertex_group(bow_obj, vertex_groups, "hair-point")
     wind = utils.mean_of_vertex_group(bow_obj, vertex_groups, "wrapping")
     return frog, tip, wind
Пример #2
0
 def get_bow_points(self):
     bow_obj = bpy.data.objects["bow"]
     #only do this once, for efficency
     vertex_groups = utils.getVertGroups(bow_obj)
     frog = utils.mean_of_vertex_group(bow_obj, vertex_groups, "hair-frog")
     tip  = utils.mean_of_vertex_group(bow_obj, vertex_groups, "hair-point")
     wind = utils.mean_of_vertex_group(bow_obj, vertex_groups, "wrapping")
     return frog, tip, wind
Пример #3
0
 def get_string_coords(self):
     """ gets the coordinates of the strings at bridge and nut,
         using relative coordinates to the violin body. """
     string_coords = []
     for i, st in enumerate(STRINGS):
         string_object = self.get_string_obj(i)
         # only do this once per string, for efficency
         vertex_groups = utils.getVertGroups(string_object)
         # support two naming schemes
         if "bridge-mark" in string_object.vertex_groups:
             bridge = utils.mean_of_vertex_group(string_object,vertex_groups,
                 "bridge-mark")
             nut    = utils.mean_of_vertex_group(string_object,vertex_groups,
                 "nut-mark")
         else:
             bridge = utils.mean_of_vertex_group(string_object,vertex_groups,
                 st+"-bridge-mark")
             nut    = utils.mean_of_vertex_group(string_object,vertex_groups,
                 st+"-nut-mark")
         bridge = string_object.matrix_local * bridge
         nut    = string_object.matrix_local * nut
         string_coords.append( StringEnds(bridge, nut) )
     return string_coords