def sortList(self, head):
"""
:type head: ListNode
:rtype: ListNode
"""
if not head:
return head
if head.next == None:
return head
listLen = 0
tempHead = head
while tempHead != None:
tempHead = tempHead.next
listLen+=1
i = 1
ans = ListNode(-1)
ans.next = head
while i < listLen:
tempHead = ans
fastNode = tempHead.next
slowNode = tempHead.next
while fastNode != None or slowNode != None:
fv = 0
sv = 0
# 较快的指针先走i个节点
while fv < i and fastNode != None:
fastNode = fastNode.next
fv +=1
fv = 0
# 和并慢的指针和快的指针
while fv < i and sv < i and fastNode != None and slowNode != None:
if fastNode.val < slowNode.val:
fv +=1
tempHead.next = fastNode
fastNode = fastNode.next
else:
sv +=1
tempHead.next = slowNode
slowNode = slowNode.next
tempHead = tempHead.next
while fv < i and fastNode != None:
tempHead.next = fastNode
tempHead = tempHead.next
fv +=1
fastNode = fastNode.next
while sv < i and slowNode != None:
tempHead.next = slowNode
sv +=1
slowNode = slowNode.next
tempHead = tempHead.next
# 这一句必须有，因为最后的时候给链表结尾用
tempHead.next = fastNode
slowNode = fastNode
i*=2
return ans.next
def sortList(self, head):
"""
:type head: ListNode
:rtype: ListNode
"""
if not head:
return head
if head.next == None:
return head
listLen = 0
tempHead = head
while tempHead != None:
tempHead = tempHead.next
listLen += 1
i = 1
ans = ListNode(-1)
ans.next = head
while i < listLen:
tempHead = ans
fastNode = tempHead.next
slowNode = tempHead.next
while fastNode != None or slowNode != None:
fv = 0
sv = 0
# 较快的指针先走i个节点
while fv < i and fastNode != None:
fastNode = fastNode.next
fv += 1
fv = 0
# 和并慢的指针和快的指针
while fv < i and sv < i and fastNode != None and slowNode != None:
if fastNode.val < slowNode.val:
fv += 1
tempHead.next = fastNode
fastNode = fastNode.next
else:
sv += 1
tempHead.next = slowNode
slowNode = slowNode.next
tempHead = tempHead.next
while fv < i and fastNode != None:
tempHead.next = fastNode
tempHead = tempHead.next
fv += 1
fastNode = fastNode.next
while sv < i and slowNode != None:
tempHead.next = slowNode
sv += 1
slowNode = slowNode.next
tempHead = tempHead.next
# 这一句必须有，因为最后的时候给链表结尾用
tempHead.next = fastNode
slowNode = fastNode
i *= 2
return ans.next
def mergeTowList(self,first,second):
if not first :
return second
if not second:
return first
head = curNode = ListNode(-1)
while first != None and second != None:
if first.val < second.val:
curNode.next = first
first = first.next
else:
curNode.next = second
second = second.next
curNode = curNode.next
if first != None:
curNode.next = first
if second != None:
curNode.next = second
return head.next
def mergeTowList(self,first,second):
if not first :
return second
if not second:
return first
head = curNode = ListNode(-1)
while first != None and second != None:
if first.val < second.val:
curNode.next = first
first = first.next
else:
curNode.next = second
second = second.next
curNode = curNode.next
if first != None:
curNode.next = first
if second != None:
curNode.next = second
return head.next
if __name__ == '__main__':
node = ListNode(-1)
so = Solution()
first= node.getOneListNode([1,3,5,7,9,10,11])
second = node.getOneListNode([2,4,6,8,1111])
third = node.getOneListNode([10,11,12])
lists = [first,second,third]
node.printOneList(so.mergeKLists(lists))
fastNode = fastNode.next
else:
sv +=1
tempHead.next = slowNode
slowNode = slowNode.next
tempHead = tempHead.next
while fv < i and fastNode != None:
tempHead.next = fastNode
tempHead = tempHead.next
fv +=1
fastNode = fastNode.next
while sv < i and slowNode != None:
tempHead.next = slowNode
sv +=1
slowNode = slowNode.next
tempHead = tempHead.next
# 这一句必须有，因为最后的时候给链表结尾用
tempHead.next = fastNode
slowNode = fastNode
i*=2
return ans.next
if __name__ == '__main__':
head = ListNode(-1)
so = Solution()
head.printOneList(so.sortList(head.getOneListNode([8,5,3,2,1])))
else:
sv += 1
tempHead.next = slowNode
slowNode = slowNode.next
tempHead = tempHead.next
while fv < i and fastNode != None:
tempHead.next = fastNode
tempHead = tempHead.next
fv += 1
fastNode = fastNode.next
while sv < i and slowNode != None:
tempHead.next = slowNode
sv += 1
slowNode = slowNode.next
tempHead = tempHead.next
# 这一句必须有，因为最后的时候给链表结尾用
tempHead.next = fastNode
slowNode = fastNode
i *= 2
return ans.next
if __name__ == '__main__':
head = ListNode(-1)
so = Solution()
head.printOneList(so.sortList(head.getOneListNode([8, 5, 3, 2, 1])))