def cost_calculator(start_node: Node, end_node: Node):
     if start_node.__eq__(end_node):
         return 0
     else:
         # moving horizontally or vertically
         if start_node.x == end_node.x or start_node.y == end_node.y:
             if start_node.border_node == True and end_node.border_node == True:  # if both nodes are border nodes
                 if (start_node.hits_count + end_node.hits_count
                     ) < 4 and cells[cell_index_finder_for_2_diagonal_nodes(
                         start_node, end_node)].high_risk == False:
                     return 1.3
                 else:
                     return 1000
             # if at least one of the nodes is not a border node
             else:
                 if (start_node.hits_count + end_node.hits_count) < 2:
                     return 1
                 if (start_node.hits_count + end_node.hits_count) >= 2 and (
                         start_node.hits_count + end_node.hits_count
                 ) < 6 and not (
                         cells[cells_finder_for_2_non_diagonal_nodes(
                             start_node, end_node)[0]].high_risk == True
                         and cells[cells_finder_for_2_non_diagonal_nodes(
                             start_node, end_node)[1]].high_risk == True):
                     return 1.3
                 else:
                     return 1000
         else:
             # moving diagonally
             if start_node.border_node == True or end_node.border_node == True:
                 if (start_node.hits_count + end_node.hits_count) < 4:
                     return 1.5
                 else:
                     return 10000
             else:  # moving diagonally between two non-border nodes
                 if cells[cell_index_finder_for_2_diagonal_nodes(
                         start_node, end_node)].high_risk:
                     return 10000
                 else:
                     return 1.5
示例#2
0
 def __eq__(self, other):
     return Node.__eq__(self, other) and hasattr(other, "tag") and self.tag == other.tag
示例#3
0
文件: Element.py 项目: anh2hn/thug
 def __eq__(self, other):
     return Node.__eq__(self, other) and hasattr(
         other, "tag") and self.tag == other.tag