def Problem8_4():
d = 25 #mm
p = 5 #mm
F = 5 #Kn
fc = 0.06
ft = 0.09
dc = 45 #mm
dm = d - p / 2
l = p * 1 # Single threaded, n = 1
Tr = Screw.TorqueToRaiseWCollar(F, ft, fc, dm, dc, l)
Tl = Screw.TorqueToLowerWCollar(F, ft, fc, dm, dc, l)
e = Screw.Efficiency(F, l, Tr)
print(Tr, Tl, e)
def Problem2():
""" CORRECT
What is the torque, in pound-inches, required
to raise a 7 kip load using a square thread power
screw with a major diameter of 1.5 inches and a
pitch of 0.2 inches, and a collar with mean diameter
of 2.8 inches? Assume the screw to be single threaded
and the friction on the thread and collar to be 0.14."""
F = 7000 #lb
dc = 2.8 #in
d = 1.5 #in (Major diameter)
p = 0.2 #in
dm = d - p / 2 # (Median diameter)
ft = 0.14
l = p #Single threaded
ans = Screw.TorqueToRaiseWCollar(F, ft, ft, dm, dc, l)
print(ans)