示例#1
0
        def build(start1, end2, length):
            if not length:
                return None
            root_val = postorder[end2]
            root = TreeNode(root_val)
            if length == 1:
                return root
            root_index = inorder.index(root_val)
            left_length = root_index - start1
            right_length = length - left_length - 1

            root.left = build(start1, end2 - right_length - 1, left_length)
            root.right = build(start1 + 1 + left_length, end2 - 1,
                               right_length)

            return root
示例#2
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        def build(start1, start2, length):
            if not length:
                return None
            root_val = preorder[start1]
            root = TreeNode(root_val)
            if length == 1:
                return root
            root_index = inorder.index(root_val)
            left_length = root_index - start2
            right_length = length - left_length - 1

            root.left = build(start1 + 1, start2, left_length)
            root.right = build(start1 + 1 + left_length,
                               start2 + 1 + left_length, right_length)

            return root
 def sortedListToBST(self, head):
     """
     升序链表,转二叉搜索树
     :type head: ListNode
     :rtype: TreeNode
     """
     if not head:
         return
     if not head.next:
         return TreeNode(head.val)
     slow, fast = head, head.next.next
     while fast and fast.next:
         fast = fast.next.next
         slow = slow.next
     tmp = slow.next
     slow.next = None
     root = TreeNode(tmp.val)
     root.left = self.sortedListToBST(head)
     root.right = self.sortedListToBST(tmp.next)
     return root
示例#4
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        :rtype: bool
        """
        if not root:
            return False
        sum -= root.val
        if not root.left and not root.right and not sum:
            return True
        return self.hasPathSum(root.left, sum) or self.hasPathSum(
            root.right, sum)

    def f2(self, root, sum):
        stack = [root]
        while stack and root:
            cur = stack.pop()
            if not cur.left and not cur.right and cur.val == sum:
                return True
            if cur.right:
                cur.right.val += cur.val
                stack.append(cur.right)
            if cur.left:
                cur.left.val += cur.val
                stack.append(cur.left)
        return False


if __name__ == '__main__':
    s = Solution()
    root = TreeNode([5, 4, 8, 11, None, 13, 4, 7, 2, None, 1])
    root = TreeNode([1, 2])
    print(s.hasPathSum(root, 3))
示例#5
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        pro_val = None
        while p or stack:
            while p:
                stack.append(p)
                p = p.left

            p = stack.pop()
            if pro_val and p.val == pro_val.val:
                cur_count += 1
            else:
                cur_count = 1
                pro_val = p

            if cur_count == max_count:
                ans.append(p.val)
            elif cur_count > max_count:
                ans = [p.val]
                max_count = cur_count
            p = p.right
        return ans


if __name__ == '__main__':
    s = Solution()
    print(s.findMode(TreeNode([2, 1, 3, 1])))
    print(s.findMode(TreeNode([1, None, 2])))
    print(s.findMode(TreeNode([2, 1])))
    print(s.findMode(TreeNode([1, 2, 3])))
    print(s.findMode(TreeNode([2, 2, 3])))
    print(s.findMode(TreeNode([1, None, 2, 2])))
                    res += tmp * 10 + p.val
                    pre = p
                    p = None
                else:
                    stack.append(p)
                    tmp = tmp * 10 + p.val
                    p = p.left if p.left else p.right  # 向下
            else:
                top = stack[-1]
                if pre is top.left:  # 如果上一次是左孩子
                    if top.right:
                        p = top.right
                    else:
                        p = None
                        pre = stack.pop()
                        tmp //= 10
                else:
                    pre = stack.pop()
                    tmp //= 10
        return res


if __name__ == '__main__':
    s = Solution()
    print(s.sumNumbers(TreeNode([1, 2, 3, 4, 5, 6, 7])))
    print(s.sumNumbers(TreeNode([1, 2, 3])))
    print(s.sumNumbers(TreeNode([1])))
    # root = TreeNode([1, 2, 3, 4])
    print(s.sumNumbers(TreeNode([1, 2, 3, 4])))
    print(s.sumNumbers(TreeNode([1, 2, 3, None, 4, None, 5])))
from base.Tree import TreeNode


class Solution(object):
    def findBottomLeftValue(self, root):
        """
        :type root: TreeNode
        :rtype: int
        """
        from collections import deque
        q1 = deque()
        q2 = deque()
        q1.append(root)
        while q1:
            ans = q1[0]
            while q1:
                node = q1.popleft()
                if node.left:
                    q2.append(node.left)
                if node.right:
                    q2.append(node.right)
            q1 = q2
            q2 = deque()
        return ans.val


if __name__ == '__main__':
    s = Solution()
    print(s.findBottomLeftValue(TreeNode([3, 1, 5, 0, 2, 4, 6])))
        """
        :type root: TreeNode
        :type sum: int
        :rtype: List[List[int]]
        """
        res = []
        if not root:
            return res
        sum -= root.val
        if not root.left and not root.right:
            if sum == 0:
                return [[root.val]]
            else:
                return []
        if root.left:
            res += self.pathSum(root.left, sum)
        if root.right:
            res += self.pathSum(root.right, sum)

        return [[root.val] + i for i in res]


if __name__ == '__main__':
    s = Solution()
    root = TreeNode([5, 4, 8, 11, None, 13, 4, 7, 2, None, None, 5, 1])
    # print(root.left.left.left.left)
    # root = TreeNode(22, 0, 0)
    print(s.pathSum(root, 22))

    # print(root)
class Solution(object):
    def findFrequentTreeSum(self, root):
        """
        :type root: TreeNode
        :rtype: List[int]
        """
        from collections import defaultdict
        d = defaultdict(int)
        self.max_time = 0

        def foo(tree: TreeNode):
            if not tree:
                return 0
            l = foo(tree.left)
            r = foo(tree.right)
            val = tree.val + l + r
            d[val] += 1
            if d[val] > self.max_time:
                self.max_time = d[val]
            return val

        foo(root)

        return [i for i, j in d.items() if j == self.max_time]


if __name__ == '__main__':
    s = Solution()
    print(s.findFrequentTreeSum(TreeNode([5, 2, -3])))
示例#10
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        """
        把二叉树按照先序摊平,每个节点边做其先序前一节点的右孩子
        :type root: TreeNode
        :rtype: void Do not return anything, modify root in-place instead.
        """
        def find_last(root):
            tmp = root
            while tmp.right or tmp.left:
                if tmp.right:
                    tmp = tmp.right
                elif tmp.left:
                    tmp = tmp.left
            return tmp

        tmp = root
        while tmp:
            # print(tmp.val)
            if tmp.left:
                left_last = find_last(tmp.left)
                left_last.right = tmp.right
                tmp.right = tmp.left
                tmp.left = None
            tmp = tmp.right


if __name__ == '__main__':
    s = Solution()
    root = TreeNode([1, 2, 3, 4, 5, 6, 7])
    s.flatten(root)
    print(root)
示例#11
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        """
        if not root:
            return []
        from collections import deque
        MIN = -0xffffffff
        q1 = deque()
        q2 = deque()
        q1.append(root)
        ans = []
        while q1:
            max_val = MIN
            while q1:
                node = q1.popleft()
                if node.val > max_val:
                    max_val = node.val
                if node.left:
                    q2.append(node.left)
                if node.right:
                    q2.append(node.right)
            q1 = q2
            q2 = deque()
            ans.append(max_val)
        return ans


if __name__ == '__main__':
    s = Solution()
    print(s.largestValues(TreeNode([1, 3, 2, 5, 3, None, 9])))
    print(s.largestValues(TreeNode([1])))
    print(s.largestValues(TreeNode([])))
    def isValidBST(self, root):
        """
        判断一个树是否为二叉搜索树

        :type root: TreeNode
        :rtype: bool
        """
        if root is None:
            return True

        p = root
        stack = []
        per = float('-inf')

        while len(stack) > 0 or p is not None:
            while p is not None:
                stack.append(p)
                p = p.left
            if len(stack) > 0:
                p = stack.pop()
                if p.val <= per:
                    return False
                per = p.val
                p = p.right
        return True


if __name__ == '__main__':
    s = Solution()
    print(s.isValidBST(TreeNode([2, 1, 4, null, null, 3, 5])))
                result.append(current_level)
            else:
                current_level.append(node.val)

            if node.left:
                if flag:
                    first = node.left
                    flag = False
                lst.append(node.left)
            if node.right:
                if flag:
                    first = node.right
                    flag = False
                lst.append(node.right)
        return result

    def soluion3(self, root):
        ans, level = [], [root]
        while root and level:
            ans.append([node.val for node in level])
            level = [kid for n in level for kid in (n.left, n.right) if kid]
        return ans


if __name__ == '__main__':
    null = None
    root = TreeNode([3, 9, 20, null, null, 15, 7])
    # root = TreeNode([])
    s = Solution()
    print(s.soluion3(root))