def _uploadfile(self, fn, data=None):
"""Uploads a file to Amazon S3.
Arguments:
fn -- file name to upload
data -- contents of file to upload, if not stored in file at fn
Returns the URL of the now-uploaded file.
"""
key = Key(self.bucket, fn)
if data:
key.path = fn
key.set_contents_from_string(data, policy='public-read')
else:
key.set_contents_from_filename(fn, policy='public-read')
url = key.generate_url(86400, force_http=True, query_auth=False).replace(':433', '')
return url
