Python Splitter._is_circular_necessary示例

示例#1

文件： test_splitter.py 项目： yehancha/chomp-decomposition

 def test_is_circular_necessary_case_true(self):
     self.week_demand = [[1, 1, 0, 4], [1, 2, 1, 0], [1, 1, 1, 1]]
     s = Splitter(self.week_demand, self.min_length, self.max_length)
     assert s._is_circular_necessary() is True

示例#2

文件： test_splitter.py 项目： partnerhero/chomp-decomposition

 def test_is_circular_necessary_case_true(self):
     self.week_demand = [[1, 1, 0, 4], [1, 2, 1, 0], [1, 1, 1, 1]]
     s = Splitter(self.week_demand, self.min_length, self.max_length)
     assert s._is_circular_necessary() is True

示例#3

文件： test_splitter.py 项目： yehancha/chomp-decomposition

 def test_is_circular_necessary_case_false(self):
     s = Splitter(self.week_demand, self.min_length, self.max_length)
     assert s._is_circular_necessary() is False

示例#4

文件： test_splitter.py 项目： partnerhero/chomp-decomposition

 def test_is_circular_necessary_case_false(self):
     s = Splitter(self.week_demand, self.min_length, self.max_length)
     assert s._is_circular_necessary() is False