def width(self):
if not self.root:
return 0
q = Queue()
q.enqueue((0, self.root))
curr_level = 0
curr_level_nodes = 0
max_width = 0
while q.length() != 0:
level, node = q.dequeue()
q.enqueue((level + 1, node.left)) if node.left else None
q.enqueue((level + 1, node.right)) if node.right else None
# Start of a new level
# Check if number of nodes at previous level > mqx nodes at any level
if level != curr_level:
if curr_level_nodes > max_width:
max_width = curr_level_nodes
# start counting nodes for the current level
curr_level_nodes = 0
curr_level_nodes += 1
curr_level = level
# Check last level
if curr_level_nodes > max_width:
max_width = curr_level_nodes
return max_width
def top_view(self, aggregate_fn=_default_printfn, **kwargs):
if not self.root:
return
q = Queue()
min_width = 0
max_width = 0
q.enqueue((0, self.root))
# Top-view begins with the root node
aggregate_fn(kwargs, self.root.value)
while q.length() != 0:
width, node = q.dequeue()
if width < min_width:
min_width = width
aggregate_fn(kwargs, node.value)
elif width > max_width:
max_width = width
aggregate_fn(kwargs, node.value)
# NOTE: width 0, is root, would already be filled in at root,
# and in a top-view is not going to replaced
q.enqueue((width - 1, node.left)) if node.left else None
q.enqueue((width + 1, node.right)) if node.right else None
def levelorder_traversal(self, aggregate_fn=_default_printfn, **kwargs):
if not self.root:
return
q = Queue()
q.enqueue(self.root)
while q.length() != 0:
tmp = q.dequeue()
aggregate_fn(kwargs, tmp.value)
q.enqueue(tmp.left) if tmp.left else None
q.enqueue(tmp.right) if tmp.right else None
def top_view_LR(self, aggregate_fn=_default_printfn, **kwargs):
if not self.root:
return
# Queue to help with level-order traversal
q = Queue()
# Store L/R width of a node and its value if it is visible in the top-view, in a sorted list
# ordered by the width
# at the end of the level-order traversal the list would contain
# [(-max_left_width, node value), ...., (0, root.value), ... (max_right_width, node value)]
slist = SLL()
# pairs a(w1, node_val1) vs b(w2, node_val2) are valued against each other
# depending on w1 vs w2 (where w1 and w2 are widths, so slist is kept sorted by the nodes' L/R widths)
pair_comparator = lambda (w1, node_val1), (w2, node_val2): cmp(w1, w2)
min_width = 0
max_width = 0
q.enqueue((0, self.root))
# Top-view begins with the root node
slist.place((0, self.root.value))
while q.length() != 0:
width, node = q.dequeue()
if width < min_width:
min_width = width
slist.place((width, node.value))
elif width > max_width:
max_width = width
slist.place((width, node.value))
# NOTE: width 0, is root, would already be filled in at root,
# and in a top-view is not going to replaced
q.enqueue((width - 1, node.left)) if node.left else None
q.enqueue((width + 1, node.right)) if node.right else None
# At the end of the level-order traversal,
# slist is ordered by width, so
# (-max_left_width, ..., 0, ..., max_right_width)
# Just retrieve the SLL L-R for the top view (L-R)
while slist.size != 0:
width, item = slist.pop_front()
aggregate_fn(kwargs, item)
def left_view(self, aggregate_fn=_default_printfn, **kwargs):
if not self.root:
return
q = Queue()
levels_done = None
q.enqueue((0, self.root))
while q.length() != 0:
curr_level, node = q.dequeue()
# Nothing has been printed in this level so far
# NOTE: (None < 0) in python
if curr_level > levels_done:
aggregate_fn(kwargs, node.value)
levels_done = curr_level
q.enqueue((curr_level + 1, node.left)) if node.left else None
q.enqueue((curr_level + 1, node.right)) if node.right else None
def span(self):
if not self.root:
return 0
q = Queue()
min_width = 0
max_width = 0
q.enqueue((0, self.root))
while q.length() != 0:
width, node = q.dequeue()
if width < min_width:
min_width = width
elif width > max_width:
max_width = width
q.enqueue((width - 1, node.left)) if node.left else None
q.enqueue((width + 1, node.right)) if node.right else None
return max_width - min_width
def bottom_view(self, aggregate_fn=_default_printfn, **kwargs):
if not self.root:
return
q = Queue()
# A hash table that stores a map of L/R width to a node's item
# We traverse the tree in level-order, and keep replacing slist[width] if we find a new node with the same width
# At the end of the traversal, every slist[width] from {-max_left_width, ..., 0, ..., max_right_width} will contain the
# node items that would be visible from a bottom view of the binary tree
slist = {}
min_width = 0
max_width = 0
q.enqueue((0, self.root))
# Star with placing root at width 0
slist[0] = self.root.value
while q.length() != 0:
width, node = q.dequeue()
# As we traverse level-by-level, keep replacing
# item at L/R width
slist[width] = node.value
# Track max_left_width, max_right_width
# so we don't need to sort the hash table slist,
# Just retrieve slist[{-max_left_width, ..., 0, ..., max_right_width}]
if width < min_width:
min_width = width
elif width > max_width:
max_width = width
q.enqueue((width - 1, node.left)) if node.left else None
q.enqueue((width + 1, node.right)) if node.right else None
# At the end of the level-order traversal,
# Just 'aggregate' slist[{-max_left_width, ..., 0, ..., max_right_width}]
for i in range(min_width, max_width + 1):
aggregate_fn(kwargs, slist[i])
def right_view(self, aggregate_fn=_default_printfn, **kwargs):
if not self.root:
return
q = Queue()
q.enqueue((0, self.root))
while q.length() != 0:
curr_level, node = q.dequeue()
q.enqueue((curr_level + 1, node.left)) if node.left else None
q.enqueue((curr_level + 1, node.right)) if node.right else None
# peek next node in the queue to see if this is the last node in the current level
# if yes, print it
try:
(level, next_entry) = q.front()
except UnderFlowError:
(level, next_entry) = (None, None)
# Queue is either empty, in which case this is the rightmost node in the last level
# *OR*, next entry in the queue is for the level after this one, so this is the rightmost in the current level
# In both cases, current node would be visible in a right-view.
if (not next_entry) or (level > curr_level):
aggregate_fn(kwargs, node.value)
