def graph_properties(graph, distance=2, heuristic=None):
""" Returns a list of important nodes that are property-of other nodes.
By default, dislikes is-opposite-of paths.
A "sun" node might have these direct properties: red, hot, bright, round.
The algorithm will also find: slow, healthy, dangerous, blue, mysterious,
white, exotic, organic, passionate, chaotic, intense, fast, dry.
"""
if not heuristic:
heuristic = cost({"is-opposite-of": 10})
return graph.enumerate_rules("is-property-of", distance, heuristic)
def graph_properties(graph, distance=2, heuristic=None):
""" Returns a list of important nodes that are property-of other nodes.
By default, dislikes is-opposite-of paths.
A "sun" node might have these direct properties: red, hot, bright, round.
The algorithm will also find: slow, healthy, dangerous, blue, mysterious,
white, exotic, organic, passionate, chaotic, intense, fast, dry.
"""
if not heuristic:
heuristic=cost({"is-opposite-of": 10})
return graph.enumerate_rules("is-property-of", distance, heuristic)
def graph_objects(graph, distance=2, heuristic=None):
""" Returns a list of tangible concepts.
When the root is an object, returns a list of hyponym leaves.
For example, for a "tree" cluster: beech, birch, crapabble, dogwood, linden, ...
When the root is a property, returns a list of objects.
For example, for a "wild" cluster: landscape, forest, anger, sea, rodeo, ...
"""
if not heuristic:
heuristic=cost({"is-opposite-of": 10})
if graph.root.is_property:
nodes = graph.enumerate_rules("is-property-of", distance, heuristic, reversed=True)
nodes = filter(lambda n: not n.is_property, nodes)
else:
nodes = graph.specific(proper=False)
return nodes
def graph_objects(graph, distance=2, heuristic=None):
""" Returns a list of tangible concepts.
When the root is an object, returns a list of hyponym leaves.
For example, for a "tree" cluster: beech, birch, crapabble, dogwood, linden, ...
When the root is a property, returns a list of objects.
For example, for a "wild" cluster: landscape, forest, anger, sea, rodeo, ...
"""
if not heuristic:
heuristic = cost({"is-opposite-of": 10})
if graph.root.is_property:
nodes = graph.enumerate_rules("is-property-of",
distance,
heuristic,
reversed=True)
nodes = filter(lambda n: not n.is_property, nodes)
else:
nodes = graph.specific(proper=False)
return nodes