示例#1
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def main():
    from helpers.data_access import get_data

    data = get_data(day=1).split("\n")

    result = expense_check((int(entry) for entry in data))

    print(f"Expense check result is {result}")

    result_b = expense_check((int(entry) for entry in data), num_numbers=3)

    print(f"Extended xpense check result is {result_b}")
def main():
    from helpers.data_access import get_data

    data = get_data(day=2).split("\n")
    inputs = (parse_input_line(line) for line in data)

    inputs_1, inputs_2 = tee(inputs)
    count = count_valid(inputs_1)

    print(f"There are {count} valid passwords.")

    count_v2 = count_valid(inputs_2, checker=is_password_valid_v2)
    print(f"Actually there's {count_v2} valid passwords.")
示例#3
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    seen_lines = [0]
    current, acc = 0, 0
    while True:
        current, acc = run_instruction(data, current, acc)
        if current in seen_lines:
            return current, acc
        if current == len(data) - 1:
            if data[current][1] == "acc":
                acc += data[current][2]
            return current, acc
        seen_lines.append(current)


if __name__ == "__main__":

    data = get_data(day=8).split("\n")
    ### Part 1
    t0 = time()
    data = [x.split() for x in data]
    data = [[i, x[0], int(x[1])] for i, x in enumerate(data)]
    current, acc = run_data_loop(data)
    print(f"first line to repeat itself {current}, value of accumulator {acc}")
    print(f"runtime {time()-t0:.4f} seconds")

    ### Part 2
    t0 = time()
    current, acc = 0, 0
    for i, line in enumerate(data):
        if line[1] == "nop":
            data_mod = deepcopy(data)
            data_mod[line[0]][1] = "jmp"
示例#4
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def check_pid(p_dict):
    if len(p_dict["pid"]) == 9:
        try:
            int(p_dict["pid"])
            return True
        except ValueError:
            return False
    else:
        return False


if __name__ == "__main__":

    data = get_data(day=4).split("\n\n")
    ### Part 1
    valid_passports = 0
    t0 = time()
    for line in data:
        a = re.split(" |\n", line)
        p_dict = {x.split(":")[0]: x.split(":")[1] for x in a}
        keys = p_dict.keys()
        if (len(keys) == 8) or (len(keys) == 7 and "cid" not in keys):
            valid_passports += 1
    print(f"valid passports: {valid_passports}")
    print(f"runtime {time()-t0:.4f} seconds")

    ### Part 2
    t0 = time()
    valid_passports = 0
示例#5
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from time import time
import numpy as np
from collections import Counter


def get_cluster_sizes(diff):
    cluster_size = 0
    cluster_sizes = {}
    for i in diff:
        if i == 3:
            cluster_sizes[cluster_size] += 1


if __name__ == "__main__":

    data = list(map(int, get_data(day=10).split("\n")))
    ### Part 1
    t0 = time()
    sorted_data = [0] + sorted(data) + [max(data) + 3]
    diff = np.diff(sorted_data)
    counts = Counter(diff)
    print(f"1-jolt diffs: {counts[1]}, 3-jolt diffs: {counts[3]}," +
          f" prod = {counts[1]*counts[3]}")
    print(f"runtime {time()-t0:.4f} seconds")

    ### Part 2
    t0 = time()
    # based on the size of a cluster of 1s (say 311113 is size 4), number of independent
    # solutions. Total possible solutions are the product of the number of independent
    # solutions per cluster
    sols_per_cluster_size = {2: 2, 3: 4, 4: 7}