示例#1
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def solve_day_05(input):
    regex = re.compile("-{0,1}\d+")
    f = open(input, "r")
    computer = IntCodeComputer(regex.findall(f.readline()))
    computer.write(1)
    computer.run()
    p1 = computer.read()[-1]
    computer.reset()
    computer.write(5)
    computer.run()
    p2 = computer.read()[0]
    return (p1, p2)
示例#2
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class Amplifier:

    def __init__(self, stream):
        self.computer = IntCodeComputer(stream)

    def output(self):
        return self.computer.output

    def run(self, input_queue):
        self.computer.input_queue += input_queue
        self.computer.run()

    def reset(self):
        self.computer.reset()
示例#3
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def part_1(intcode):
    p1 = 0
    computer = IntCodeComputer(intcode)
    for perm in permutations([0, 1, 2, 3, 4]):
        computer.write([perm[0], 0])
        computer.run()
        output = computer.read()[0]
        computer.reset()
        for p in perm[1:]:
            computer.write([p, output])
            computer.run()
            output = computer.read()[0]
            computer.reset()
        if p1 < output:
            p1 = output
    return p1
示例#4
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def solve_day_19(input):
    regex = re.compile("-{0,1}\d+")
    f = open(input, "r")
    computer = IntCodeComputer(regex.findall(f.readline()))
    size = 50
    p1 = 0
    for x in range(size):
        for y in range(size):
            # I have no clue why I need three inputs, but I do
            computer.write([0, x, y])
            computer.run()
            result = computer.read()[0]
            p1 += result
            computer.reset()
            print(result, end="")
        print()
    return (p1, 0)
示例#5
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def solve_day_13(input):
    regex = re.compile("-{0,1}\d+")
    f = open(input, "r")
    computer = IntCodeComputer(regex.findall(f.readline()))
    ts = play(computer, {})
    tiles = ts[0]
    score = ts[1]
    p1 = sum(value == 2 for value in tiles.values())
    print_arcade(tiles)
    computer.reset()
    computer.memory[0] = 2
    while computer.status != Status.TERMINATED:
        computer.write(get_joystick(tiles))
        ts = play(computer, tiles)
        tiles = ts[0]
        score = ts[1]
        # print_arcade(tiles)
    return (p1, score)
示例#6
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def solve_day_02(input):
    regex = re.compile("\d+")
    f = open(input, "r")
    computer = IntCodeComputer(regex.findall(f.readline()))
    computer.run()
    p1 = computer.memory[0]
    p2 = 0
    has_found = False
    for noun in range(99):
        for verb in range(99):
            computer.reset()
            computer.memory[1] = noun
            computer.memory[2] = verb
            computer.run()
            if computer.memory[0] == 19690720:
                p2 = 100 * noun + verb
                has_found = True
                break
        if has_found:
            break
    return (p1, p2)
示例#7
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import aoc_download
from intcode_computer import IntCodeComputer
YEAR = 2019
DAY = 9

puzzle_input = aoc_download.aoc.puzzle_input_file(YEAR, DAY)

computer = IntCodeComputer(puzzle_input)
computer.input_queue.append(1)
computer.run()

print("part 1:", computer.output)

computer.reset()
computer.input_queue.append(2)
computer.run()

print("part 2:", computer.output)
示例#8
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def solve_day_17(input):
    regex = re.compile("-{0,1}\d+")
    f = open(input, "r")
    computer = IntCodeComputer(regex.findall(f.readline()))
    computer.run()
    camera = computer.read()
    lst = []
    line = []
    for c in camera:
        if c == 10:
            lst.append(line)
            line = []
        else:
            line.append(c)
    p1 = 0
    for y, cy in enumerate(lst[1:-2], 1):
        for x, cx in enumerate(cy[1:-1], 1):
            if cx == 35:
                if lst[y - 1][x] == 35 and lst[y + 1][x] == 35 and lst[y][
                        x - 1] == 35 and lst[y][x + 1] == 35:
                    lst[y][x] = ord("O")
                    p1 += x * y
    # This was just for pretty printing so see how things look, but I am now using it
    # to manually solve part 2
    for cy in lst:
        for cx in cy:
            if cx == ord("."):
                print("⬛", end="")
            else:
                print("⬜", end="")
        print()
    # and after a little puzzling we get (see Scaffold.png)
    # "A"=65, "B"=66, "C"=67, ","=44, "\n"=10
    # "L"=76, "R"=82
    # "12"=49 50, "8"=56, "6"=54, "4"=52
    # "n" = 110
    # A = L12,L12,L6,L6
    # B = L12,L6,R12,R8
    # C = R8,R4,L12
    # A,C,A,B,C,A,B,C,A,B
    computer.reset()
    computer.memory[0] = 2
    instructions = [
        #A   ,   C   ,   A   ,   B   ,   C   ,   A   ,   B   ,   C   ,   A   ,   B  \n
        65,
        44,
        67,
        44,
        65,
        44,
        66,
        44,
        67,
        44,
        65,
        44,
        66,
        44,
        67,
        44,
        65,
        44,
        66,
        10,
        #L   ,   1   2   ,   L   ,   1   2   ,   L   ,   6   ,   L   ,   6  \n
        76,
        44,
        49,
        50,
        44,
        76,
        44,
        49,
        50,
        44,
        76,
        44,
        54,
        44,
        76,
        44,
        54,
        10,
        #L   ,   1   2   ,   L   ,   6   ,   R   ,   1   2   ,   R   ,   8  \n
        76,
        44,
        49,
        50,
        44,
        76,
        44,
        54,
        44,
        82,
        44,
        49,
        50,
        44,
        82,
        44,
        56,
        10,
        #R   ,   8   ,   R   ,   4   ,   L   ,   1   2  \n
        82,
        44,
        56,
        44,
        82,
        44,
        52,
        44,
        76,
        44,
        49,
        50,
        10,
        #n,  \n
        110,
        10
    ]
    computer.write(instructions)
    computer.run()
    p2 = computer.read()[-1]
    return (p1, p2)
示例#9
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 def test_reset(self):
     computer = IntCodeComputer(self.regex.findall("1,1,1,4,99,5,6,0,99"))
     computer.run()
     computer.reset()
     self.assertEqual([1, 1, 1, 4, 99, 5, 6, 0, 99], computer.memory)