# Definition for a binary tree node.
class TreeNode:
def __init__(self, val=0, left=None, right=None):
self.val = val
self.left = left
self.right = right
class Solution:
def findTarget(self, root: TreeNode, k: int) -> bool:
mystack = []
def find(root: TreeNode, k: int, mystack: list):
if root is None:
return False
if (k - root.val) in mystack:
return True
mystack.append(root.val)
return find(root.left, k, mystack) or find(root.right, k, mystack)
return find(root, k, mystack)
root = [5, 3, 6, 2, 4, "null", 7]
k = 9
# root = [5, 3, 6, 2, 4, "null", 7]; k = 28
t = MyTree()
root1 = t.maketree(root)
s = Solution()
print(s.findTarget(root1, k))
if t1:
res = t1
elif t2:
res = t2
else:
return []
traversal(t1, t2)
return res
def mergeTrees2(self, t1: TreeNode, t2: TreeNode) -> TreeNode:
if t1 and t2:
node = TreeNode(t1.val + t2.val)
node.left = self.mergeTrees(t1.left, t2.left)
node.right = self.mergeTrees(t1.right, t2.right)
return node
return t1 or t2
tt1 = [1, 3, 2, 5]
tt2 = [2, 1, 3, "null", 4, "null", 7]
tt1 = []
tt2 = [1]
t = MyTree()
t1 = t.maketree(tt1)
t2 = t.maketree(tt2)
s = Solution()
res = s.mergeTrees(t1, t2)
print(t.print_tree(res))
self.right = right
class Solution:
def minDepth(self, root: TreeNode) -> int:
if not root:
return 0
mindepth = 10 ** 5
def traversal(node: TreeNode, depth, mindepth):
if node:
depth += 1
if not node.left and not node.right:
if mindepth > depth:
mindepth = depth
return mindepth
if node.left:
mindepth = min(traversal(node.left, depth, mindepth), mindepth)
if node.right:
mindepth = min(traversal(node.right, depth, mindepth), mindepth)
return mindepth
return traversal(root, 0, mindepth)
root = [3,9,20,"null","null",15,7]
root = [2,"null",3,"null",4,"null",5,"null",6]
t = MyTree()
rr = t.maketree(root)
s = Solution()
print(s.minDepth(rr))
class TreeNode:
def __init__(self, val=0, left=None, right=None):
self.val = val
self.left = left
self.right = right
class Solution:
def searchBST(self, root: TreeNode, val: int) -> TreeNode:
def traverse(root: TreeNode, val: int):
if not root:
return None
if root.val == val:
return root
elif root.val > val:
return traverse(root.left, val)
else:
return traverse(root.right, val)
return traverse(root, val)
root = [4, 2, 7, 1, 3]
val = 2
root = [4, 2, 7, 1, 3]
val = 5
m = MyTree()
mt = m.maketree(root)
s = Solution()
print(s.searchBST(mt, val))
class TreeNode:
def __init__(self, val=0, left=None, right=None):
self.val = val
self.left = left
self.right = right
class Solution:
def isSameTree(self, p: TreeNode, q: TreeNode) -> bool:
if p is None and q is None:
return True
if not p or not q:
return False
if p.val != q.val:
return False
return self.isSameTree(p.left, q.left) and \
self.isSameTree(p.right, q.right)
p = [1, 2, 3]
q = [1, 2, 3]
p = [1, 2]
q = [1, "null", 2]
p = [1, 2, 1]
q = [1, 1, 2]
t = MyTree()
pp = t.maketree(p)
qq = t.maketree(q)
s = Solution()
print(s.isSameTree(pp, qq))
from iv.Binarytree.mytree import MyTree arr = [100, 98, 102, 96, 99, "null", "null", "null", 97] m = MyTree() root = m.maketree(arr) res = m.print_tree(root) print(res)
# print(res[i].val, res[i+1].val)
if res[i].val > res[i + 1].val:
node1 = res[i]
notfound = False
else:
if res[i].val < res[i - 1].val:
ind.append(i)
# print(ind)
node2 = res[max(ind)]
# print(node1.val, node2.val)
node1.val, node2.val = node2.val, node1.val
t = TreeNode(3)
t.left = TreeNode(1)
t.right = TreeNode(4)
t.right.left = TreeNode(2)
t = TreeNode(1)
t.left = TreeNode(3)
t.left.right = TreeNode(2)
obj = MyTree()
root = [1, 3, "null", "null", 2]
# root = [3,1,4,"null","null",2]
t = obj.maketree(root)
s = Solution()
s.recoverTree(t)
print(obj.print_tree(t))
traverse(root1)
res1 = [i for i in res]
res = []
traverse(root2)
res2 = [i for i in res]
# print(res1)
# print(res2)
if res1 == res2:
return True
else:
return False
root1 = [3, 5, 1, 6, 2, 9, 8, "null", "null", 7, 4]
root2 = [
3, 5, 1, 6, 7, 4, 2, "null", "null", "null", "null", "null", "null", 9, 8
]
root1 = [1]
root2 = [2]
root1 = [1, 2]
root2 = [2, 2]
root1 = [1, 2, 3]
root2 = [1, 3, 2]
t = MyTree()
rr1 = t.maketree(root1)
rr2 = t.maketree(root2)
s = Solution()
print(s.leafSimilar(rr1, rr2))
print(s.leafSimilar2(rr1, rr2))
# Definition for a binary tree node.
class TreeNode:
def __init__(self, val=0, left=None, right=None):
self.val = val
self.left = left
self.right = right
class Solution:
def pruneTree(self, root: TreeNode) -> TreeNode:
def isvalid(node: TreeNode):
if not node:
return False
a1 = isvalid(node.left)
a2 = isvalid(node.right)
if not a1: node.left = None
if not a2: node.right = None
return node.val == 1 or a1 or a2
return root if isvalid(root) else None
t = MyTree()
mytt = [1, "null", 0, 0, 1]
root = t.maketree(mytt)
s = Solution()
print(s.pruneTree(root))
res = t.print_tree(s.pruneTree(root))
print(res)
self.right = right
class Solution:
def minDiffInBST(self, root: TreeNode) -> int:
mylist = []
def traverse(root):
if root:
if root.left:
traverse(root.left)
mylist.append(root.val)
if root.right:
traverse(root.right)
traverse(root)
min_dist = max(mylist)
for i in range(len(mylist) - 1):
if abs(mylist[i] - mylist[i + 1]) < min_dist:
min_dist = abs(mylist[i] - mylist[i + 1])
return min_dist
root = [4, 2, 6, 1, 3]
root = []
root = [1, 0, 48, "null", "null", 12, 49]
mt = MyTree()
root_bst = mt.maketree(root)
s = Solution()
print(s.minDiffInBST(root_bst))
