def intersectionOfSortedLists(a, b):
    result = LinkedList()
    while a and b:
        if a.data == b.data:
            result.append(a.data)
            a, b = a.next, b.next
        elif a.data > b.data:
            b = b.next
        else:
            a = a.next
    return result
def isPalindrome(node):
    s = []
    current = node
    while current:
        s.append(current.data)
        current = current.next
    current = node
    while current:
        if current.data != s.pop():
            return False
        current = current.next
    return True


a = LinkedList()
a.printList()
print isPalindrome(a.head)
a.append(1)
a.printList()
print isPalindrome(a.head)
a.append(2)
a.append(1)
a.printList()
print isPalindrome(a.head)
a.append(2)
a.append(1)
a.printList()
print isPalindrome(a.head)
a.append(5)
a.printList()
print isPalindrome(a.head)
    prevI, prevJ = None, None
    while j and k > 1:
        prevJ, j = j, j.next
        k -= 1
    if j is None:
        return newHead
    kthFromBegin, kthFromEnd = j, i
    while j.next:
        prevI, kthFromEnd = kthFromEnd, kthFromEnd.next
        j = j.next
    if kthFromBegin == kthFromEnd:
        return newHead
    if prevI is None:
        newHead = kthFromBegin
        prevJ.next = kthFromEnd
    elif prevJ is None:
        newHead = kthFromEnd
        prevI.next = kthFromBegin
    else:
        prevI.next = kthFromBegin
        prevJ.next = kthFromEnd
    kthFromBegin.next, kthFromEnd.next = kthFromEnd.next, kthFromBegin.next
    return newHead


a = LinkedList()
for i in range(1, 9):
    a.append(i)
a.printList()
a.head = swap(a.head, 1)
a.printList()
        if (a.data > b.data):
            a.data, b.data = b.data, a.data
            temp = b
            while b.next and b.data > b.next.data:
                b = b.next
                prev, ptr = None, b
                while ptr and ptr.data < temp.data:
                    prev, ptr = ptr, ptr.next
                prev.next = temp
                temp.next = ptr
        if a.next is None:
            break
        a = a.next
    while a.next:
        a = a.next
    a.next = b

a = LinkedList()
a.append(2)
a.append(4)
a.append(7)
a.append(8)
a.append(10)

b = LinkedList()
b.append(1)
b.append(3)
b.append(12)

merge(a.head, b.head)
a.printList()
示例#5
0

def reverse(node, k, i):
    current, next, prev, count = node, None, None, 0
    if i == 0:
        while current and count < k:
            next = current.next
            current.next = prev
            prev = current
            current = next
            count += 1
    else:
        while current and count < k:
            prev, current, next = current, current.next, current.next
            count += 1
    if next:
        if i == 0:
            node.next = reverse(next, k, 1)
        else:
            prev.next = reverse(next, k, 0)
    return prev if i == 0 else node


l = LinkedList()
for i in range(1, 9):
    l.append(i)

l.printList()
l.head = reverse(l.head, 3, 0)
l.printList()
示例#6
0
from list import Node
from list import LinkedList


def isLoop(node):
    fast, slow = node, node
    while fast and fast.next:
        fast = fast.next.next
        slow = slow.next
        if fast == slow:
            return True
    return False


a = LinkedList()
a.push(1)
a.append(2)
a.append(3)
a.append(4)
a.append(5)

a.printList()
print isLoop(a.head)
a.head.next.next.next.next.next = a.head.next.next.next

print isLoop(a.head)
示例#7
0
def deleteMiddlePoints(node):
    while node and node.next and node.next.next:
        if node.data[0] == node.next.data[0] and node.data[
                0] == node.next.next.data[0]:
            node.next = node.next.next
            continue
        if node.data[1] == node.next.data[1] and node.data[
                1] == node.next.next.data[1]:
            node.next = node.next.next
            continue
        node = node.next


a = LinkedList()
a.append([0, 10])
a.append([1, 10])
a.append([5, 10])
a.append([7, 10])
a.append([7, 5])
a.append([20, 5])
a.append([40, 5])
a.printList()
deleteMiddlePoints(a.head)
a.printList()

b = LinkedList()
b.append([2, 3])
b.append([5, 3])
b.append([7, 3])
b.append([10, 3])
示例#8
0
        else:
            result.head = Node(sum % 10)
            lastNode = result.head
        carry = sum / 10
        a = a.next
    while b:
        sum = b.data + carry
        if lastNode:
            lastNode.next = Node(sum % 10)
            lastNode = lastNode.next
        else:
            result.head = Node(sum % 10)
            lastNode = result.head
        carry = sum / 10
        b = b.next
    if carry == 1:
        if lastNode:
            lastNode.next = Node(1)
        else:
            result.head = Node(1)
    return result


a = LinkedList()
a.append(6)
a.append(7)
a.append(5)
b = LinkedList()

add(a.head, b.head).printList()
示例#9
0
from list import LinkedList
from list import Node


def isPalindrome(node):
    s = ""
    while node:
        s += node.data
        node = node.next
    l = 0
    r = len(s) - 1
    while l < r:
        if s[l] != s[r]:
            return False
        l += 1
        r -= 1
    return True


a = LinkedList()
a.append("A")
a.append("BC")
a.append("D")
a.append("DCB")
a.append("A")

a.printList()
print isPalindrome(a.head)
示例#10
0
    even = []
    odd = []
    i = 0
    current = l.head
    while current:
        if i % 2 == 0 and current.data % 2 == 1:
            odd.append(current)
        if i % 2 == 1 and current.data % 2 == 0:
            even.append(current)
        i += 1
        current = current.next
    while len(odd) > 0 and len(even) > 0:
        a, b = odd.pop(), even.pop()
        a.data, b.data = b.data, a.data


l = LinkedList()
l.append(10)
l.append(2)
l.append(1)
l.append(5)
l.append(3)
l.append(6)
l.append(7)
l.append(8)
l.append(9)
l.append(10)
l.printList()
alternateOddEvenEfficient(l)
l.printList()
示例#11
0
            tail.next = b
            b = b.next
        tail = tail.next
    if a:
        tail.next = a
    if b:
        tail.next = b
    return head


def findMid(a):
    prevSlow, slow, fast = None, a, a
    while fast and fast.next:
        fast = fast.next.next
        prevSlow, slow = slow, slow.next
    return prevSlow


a = [4, 3, 5, 7, 11, 2, 1]
l1 = LinkedList()
for i in a:
    l1.append(i)
l1.printList()

a = [2, 3, 4, 5, 6, 8, 12]
l2 = LinkedList()
for i in a:
    l2.append(i)
l2.printList()

print countPairsWithSumX(l1.head, l2.head, 9)
示例#12
0
from list import Node
from list import LinkedList


def frequency(node, k):
    count = 0
    while node:
        if node.data == k:
            count += 1
        node = node.next
    return count


a = LinkedList()
a.append(0)
a.push(1)
a.append(1)
a.push(2)
a.append(3)
a.push(2)
a.append(4)
a.push(2)
a.append(2)
a.push(0)
a.printList()
for i in range(0, 6):
    print frequency(a.head, i)
                prev.next = current.next
                current = current.next
            else:
                maxRight = current.data
                prev = current
                current = current.next

        reverse(l)


def reverse(l):
    current, prev = l.head, None
    while current:
        next = current.next
        current.next = prev
        prev, current = current, next
    l.head = prev


l = LinkedList()
l.append(12)
l.append(15)
l.append(10)
l.append(11)
l.append(5)
l.append(6)
l.append(2)
l.append(3)
l.printList()
delete(l)
l.printList()
示例#14
0
        if current.data == key:
            prevLastOcc, lastOcc = prev, current
        prev, current = current, current.next
    if lastOcc is None:
        return
    if prevLastOcc is None:
        l.head = l.head.next
    else:
        prevLastOcc.next = lastOcc.next
    lastOcc.next = None
    lastOcc = None


l = LinkedList()
for i in range(8):
    l.append(i)
l.printList()
deleteLast(l, 6)
l.printList()
deleteLast(l, 7)
l.printList()
deleteLast(l, 7)
l.printList()
deleteLast(l, 1)
l.printList()
deleteLast(l, 2)
deleteLast(l, 3)
deleteLast(l, 4)
deleteLast(l, 0)
deleteLast(l, 5)
l.printList()
示例#15
0
from list import Node


def mergeRecursive(a, b):
    if a is None:
        return b
    if b is None:
        return a
    if a.data <= b.data:
        a.next = mergeRecursive(a.next, b)
        return a
    else:
        b.next = mergeRecursive(a, b.next)
        return b


l = LinkedList()
l.append(1)
l.append(2)
l.append(4)
l.printList()
s = LinkedList()
s.append(3)
s.append(4)
s.append(5)
s.printList()

m = LinkedList()
m.head = mergeRecursive(l.head, s.head)
m.printList()
示例#16
0
        if a.data not in s:
            s.add(a.data)
            tail.next = Node(a.data)
            tail = tail.next
        a = a.next
    while b:
        if b.data not in s:
            s.add(b.data)
            tail.next = Node(b.data)
            tail = tail.next
        b = b.next
    return head.next


a = LinkedList()
a.append(10)
a.append(15)
a.append(4)
a.append(20)
a.printList()
b = LinkedList()
b.append(8)
b.append(4)
b.append(2)
b.append(10)
b.printList()

i = LinkedList()
i.head = intersection(a.head, b.head)
i.printList()
示例#17
0
                lastNode.next = current
                lastNode = lastNode.next
                current.next = None
                current = l.head
            else:
                prev.next = current.next
                lastNode.next = current
                lastNode = lastNode.next
                current.next = None
                current = prev.next
        else:
            prev, current = current, current.next


a = LinkedList()
a.append(1)
a.append(1)
a.append(0)
a.append(2)
a.append(0)
a.append(0)
a.append(1)
a.append(2)
a.append(0)
a.append(1)
a.append(2)
a.append(2)
a.append(1)
a.append(1)
a.append(2)
a.printList()
示例#18
0
    else:
        if not firstNonNegNode:
            return reverse(firstNegNode)
        else:
            prev.next = None
            s = reverse(firstNegNode)
            firstNegNode.next = firstNonNegNode
            return s


def reverse(a):
    prev, current = None, a
    while current:
        next = current.next
        current.next = prev
        prev, current = current, next
    return prev


a = LinkedList()
a.append(0)
a.append(-2)
a.append(-3)
a.append(4)
a.append(-5)
a.append(-6)
a.append(-8)
a.printList()
a.head = sort(a.head)
a.printList()
def strCompare(a, b):
    if not a and not b:
        return 0
    if not a:
        return -1
    if not b:
        return 1
    if a.data != b.data:
        return sgn(ord(a.data), ord(b.data))
    return strCompare(a.next, b.next)


def sgn(a, b):
    if a > b:
        return 1
    elif b > a:
        return -1
    return 0


a = LinkedList()
b = LinkedList()
s1 = "Archit"
s2 = "Arpit"

for i in s1:
    a.append(i)
for i in s2:
    b.append(i)

print strCompare(a.head, b.head)
示例#20
0
def heapify(a, n, i):
    smallest = i
    l = 2 * i + 1
    r = l + 1
    if l < n and a[l] < a[smallest]:
        smallest = l
    if r < n and a[r] < a[smallest]:
        smallest = r
    if i != smallest:
        a[smallest], a[i] = a[i], a[smallest]
        heapify(a, n, smallest)


a = LinkedList()
a.append(1)
a.append(4)
a.append(5)
b = LinkedList()
b.append(1)
b.append(3)
b.append(4)
c = LinkedList()
c.append(2)
c.append(6)
a.printList()
b.printList()
c.printList()
mergedList = LinkedList()
mergedList.head = mergeKSortedLists2([a.head, b.head, c.head])
mergedList.printList()
from list import Node
from list import LinkedList

def intersectionOfSortedLists(a, b):
    result = LinkedList()
    while a and b:
        if a.data == b.data:
            result.append(a.data)
            a, b = a.next, b.next
        elif a.data > b.data:
            b = b.next
        else:
            a = a.next
    return result

a = LinkedList()
for i in range(8):
    a.append(i)
a.printList()

b = LinkedList()
for i in range(1, 6):
    b.append(i*2)
b.printList()

intersectionOfSortedLists(a.head, b.head).printList()
示例#22
0
from list import LinkedList
from list import Node


def isIdentical(a, b):
    if not a and not b:
        return True
    if not a or not b:
        return False
    return a.data == b.data and isIdentical(a.next, b.next)


a = LinkedList()
a.append(1)
b = LinkedList()
b.append(1)
b.append(2)

print isIdentical(a.head, b.head)
示例#23
0
from list import Node
from list import LinkedList

def multiply(a, b):
    n1 = n2 = 0
    while a:
        n1 = n1 * 10 + a.data
        a = a.next
    while b:
        n2 = n2 * 10 + b.data
        b = b.next
    return n1 * n2


a = LinkedList()
a.append(9)
a.append(4)
a.append(6)
a.printList()
b = LinkedList()
b.append(8)
b.append(4)
b.printList()
print multiply(a.head, b.head)
示例#24
0
from list import LinkedList
from list import Node


def makeMiddleHead(l):
    fast, slow, prev = l.head, l.head, None
    while fast and fast.next:
        fast = fast.next.next
        prev, slow = slow, slow.next
    if prev:
        prev.next = slow.next
        slow.next = l.head
        l.head = slow


a = LinkedList()
a.append(1)
a.append(2)
a.append(3)
a.append(4)
a.printList()
makeMiddleHead(a)
a.printList()
示例#25
0
from list import Node


def subListSearch(a, b):
    if b is None:
        return True
    while a:
        currentA, currentB = a, b
        while currentA and currentB:
            if currentA.data != currentB.data:
                break
            currentA, currentB = currentA.next, currentB.next
            if not currentB:
                return True
        if currentA is None:
            return False
        a = a.next
    return False


a = LinkedList()
for i in range(1, 9):
    a.append(i)
a.printList()

b = LinkedList()
b.append(4)
b.printList()

print subListSearch(a.head, b.head)
示例#26
0
    prev, node = node, node.next
    firstMovedNode = None
    while node and node != firstMovedNode:
        if (node.data % 2 == 0 and isHeadEven) or (node.data % 2 != 0
                                                   and not isHeadEven):
            prev, node = node, node.next
        else:
            if not firstMovedNode:
                firstMovedNode = node
            prev.next = node.next
            lastNode.next = node
            node.next = None
            lastNode = lastNode.next
            node = prev.next


a = LinkedList()
a.append(17)
a.append(15)
a.append(8)
a.append(12)
a.append(10)
a.append(5)
a.append(4)
a.append(1)
a.append(7)
a.append(6)

a.printList()
segregateEvenAndOdd(a.head)
a.printList()
示例#27
0
    current = node
    while current:
        a[current.data] += 1
        current = current.next
    current = node
    i = 0
    while current and i < 3:
        current.data = i
        current = current.next
        a[i] -= 1
        if a[i] == 0:
            i += 1


l = LinkedList()
l.append(1)
l.append(0)
l.append(2)
l.append(2)
l.append(1)
l.append(1)
l.append(1)
l.append(0)
l.append(0)
l.append(0)
l.append(2)
l.append(1)
l.append(1)
l.append(2)
l.append(1)
l.append(0)
示例#28
0
    s = []
    while d > 0:
        s.append([p.data, 0])
        p = p.next
        d -= 1
    while p and q:
        s.append([(p.data + q.data) % 10, (p.data + q.data) / 10])
        p = p.next
        q = q.next
    l = LinkedList()
    carry = 0
    while len(s) > 0:
        node = s.pop()
        l.push((node[0] + carry) % 10)
        carry = node[1] + (node[0] + carry) / 10
    if carry > 0:
        l.push(carry)
    return l


n1 = LinkedList()
s1 = "1999"
s2 = "1001"
for i in s1:
    n1.append(int(i))
n1.printList()
n2 = LinkedList()
for i in s2:
    n2.append(int(i))
n2.printList()
add(n1, n2).printList()
示例#29
0
    if l1 > l2:
        d = l1 - l2
        while d > 0:
            p = p.next
            d -= 1
    elif l2 < l1:
        d = l1 - l2
        while d > 0:
            q = q.next
            d -= 1
    while p != q:
        p, q = p.next, q.next
    return p.data


a = LinkedList()
b = LinkedList()

for i in range(8):
    a.append(i)

for j in range(8, 10):
    b.append(j)

b.head.next.next = a.head.next.next.next.next.next

a.printList()
b.printList()

print intersectionPoint(a, b)
示例#30
0
        b = b.next
    mergedTail = mergedHead
    while a and b:
        if a.data <= b.data:
            mergedTail.next = a
            a = a.next
        else:
            mergedTail.next = b
            b = b.next
        mergedTail = mergedTail.next
    if a:
        mergedTail.next = a
    if b:
        mergedTail.next = b
    return mergedHead


a = LinkedList()
a.append(1)
a.append(2)
a.append(3)
b = LinkedList()
b.append(4)
b.append(5)
b.append(6)
a.printList()
b.printList()
l = LinkedList()
l.head = merge(a.head, b.head)
a.printList()