示例#1
0
def conv_mul_mod(a, b, n, q):
    if len(a) < n:
        a = extend(a, n)
    if len(b) < n:
        b = extend(b, n)
    c = np.zeros(n)
    for i in range(n):
        for j in range(n):
            k = mod(i + j, n)
            c[k] = mod(c[k] + a[i] * b[k - i], q)
    return c
示例#2
0
def poly_egcd(a, b, q):
    a = mod(a, q)
    b = mod(b, q)
    r0 = a
    r1 = b
    x1 = y0 = np.array([0])
    y1 = x0 = np.array([1])
    while r1.any():
        k, _ = poly_divmod(r0, r1, q)
        r0, r1 = poly_update_egcd(r0, r1, k, q)
        x0, x1 = poly_update_egcd(x0, x1, k, q)
        y0, y1 = poly_update_egcd(y0, y1, k, q)
    return reduce(r0), reduce(x0), reduce(y0)
示例#3
0
def poly_divmod(a, b, q):
    n = deg(a)
    d = deg(b)
    a = mod(a, q)
    b = mod(b, q)
    b = b[:d + 1]

    r = a[:n + 1]
    e = deg(r)
    k = np.zeros(n + 1)
    while e >= d and not (e == 0 and r[0] == 0):
        temp = np.zeros(e - d + 1)
        temp[e - d] = mod(r[e] * inverse_mod(b[d], q), q)
        k = add_mod(k, temp, q)
        r = subtract_mod(r, poly_mul_mod(temp, b, q), q)
        e = deg(r)

    return k, r
示例#4
0
def poly_mul_mod(a, b, q):
    n = deg(a)
    m = deg(b)
    c = np.zeros(n + m + 1)
    ac = np.zeros(n + m + 1)
    bc = np.zeros(n + m + 1)
    ac[:n + 1] = a[:n + 1]
    bc[:m + 1] = b[:m + 1]
    for i in range(deg(a) + 1):
        c += ac[i] * bc
        c = mod(c, q)
        bc = np.roll(bc, 1)
    return c
示例#5
0
from addition import add
from subtraction import sub
from multiplication import multi
from division import div
from modulo import mod

print ("a=6, b=4")

print ("sum:", add(6, 4))
print ("difference:", sub(6, 4))
print ("product:", multi(6, 4))
print ("quotient:", div(6, 4))
print ("remainder:", mod(6, 4))
示例#6
0
def add_mod(a, b, q):
    return mod(add(a, b), q)
示例#7
0
def subtract_mod(a, b, q):
    return mod(subtract(a, b), q)
示例#8
0
文件: ntru.py 项目: D-Diaa/MathThesis
def center_lift(a, q):
    a = mod(a, q)
    a[a > q / 2] = a[a > q / 2] - q
    return np.array(a)