def first_first():
nonlocal conflict_terminal
cached_first = self.firsts()
# Search for non determinism
total = OrderedSet()
for prod in self.rules[v]:
for ter in self.first_body(prod, cached_first):
if ter in total and conflict_terminal is None:
conflict_terminal = ter
break
total.add(ter)
if conflict_terminal:
has_non_determinism = True
# print("\n\nGRAMMAR Before")
# print(self)
# Expose indirect
expose_indirect_ndet(conflict_terminal)
# print("\n\nGRAMMAR After Substitutions")
# print(self)
# Direct
lcp = os.path.commonprefix([
prod for prod in self.rules[v]
if prod[0] == conflict_terminal
])
create_new_var_lcp(lcp)
# print("\n\nGRAMMAR After Eliminating Direct")
# print(self)
return True
return False
def expose_indirect_ndet(conflict_terminal):
def sub_var(prod):
to_add = OrderedSet()
for prod_var in self.rules[prod[0]]:
if prod_var == ("&", ):
if len(prod[1:]) == 0:
to_add.add(("&", ))
else:
to_add.add(prod[1:])
else:
to_add.add(prod_var + prod[1:])
return to_add
cached_first = self.firsts()
substitution_happened = True
while substitution_happened:
substitution_happened = False
new_rules_v = OrderedSet()
for prod in self.rules[v]:
if prod[0] in self.variables and conflict_terminal in self.first_body(
prod, cached_first):
new_rules_v.update(sub_var(prod))
substitution_happened = True
else:
new_rules_v.add(prod)
self.rules[v] = new_rules_v
def first_follow():
new_rules_old_v = OrderedSet()
to_discard = None
cached_firsts = self.firsts()
for prod in self.rules[v]:
lp = len(prod)
for i in range(lp - 1):
# Test if any variable Xi appearing in X1X2...Xn has a Fi/Fo conflict
# That is, ε in FIRST(Xi) AND FIRST(Xi) ∩ FIRST(Xi+1...Xn) ≠ Ø
if prod[i] in self.variables:
intersection = cached_firsts[
prod[i]] & self.first_body(prod[i + 1:],
cached_firsts)
intersection.discard("&")
if "&" in cached_firsts[
prod[i]] and len(intersection) != 0:
to_discard = prod
for prod_sub in self.rules[prod[i]]:
if prod_sub == ("&", ):
new_rules_old_v.add(prod[:i] +
prod[i + 1:])
else:
new_rules_old_v.add(prod[:i] + prod_sub +
prod[i + 1:])
break
if not to_discard is None:
break
self.rules[v].discard(to_discard)
self.rules[v].update(new_rules_old_v)
if not to_discard is None:
return True
return False
def remove_left_recursion(self): # NOT CONST
"""
Exceptions
--------------
1. self is not e-free.
2. self is not cycle-free.
Notes
-----
Be aware when Aj has no productions.
While removing direct recursion, one may end up with len(prods_i) == 0, since
there may be S => Sbeta, where beta has no productions.
"""
if self.has_e():
raise RuntimeError(
"A grammar must be &-free in order to remove left recursions.")
if self.has_cycle():
raise RuntimeError(
"A grammar must be cycle-free in order to remove left recursions."
)
# Remove indirect
for i in range(len(self.variables)):
direct = False
for j in range(i):
to_remove = set()
for production in self.rules[self.variables[i]]:
if self.variables[j] == production[0]:
alpha = production[1:]
to_remove.add(production)
for beta in self.rules[self.variables[j]]:
self.rules[self.variables[i]].add(beta + alpha)
for rem in to_remove:
self.rules[self.variables[i]].discard(rem)
for production in self.rules[self.variables[i]]:
if production[0] == self.variables[i]:
direct = True
if direct:
new_var = "❬{}'❭".format(self.variables[i])
self.variables.add(new_var)
self.rules[new_var] = OrderedSet()
new_prods_i = OrderedSet()
for production in self.rules[self.variables[i]]:
if production[0] == self.variables[i]:
self.rules[new_var].add(production[1:] + (new_var, ))
else:
new_prods_i.add(production + (new_var, ))
self.rules[self.variables[i]] = new_prods_i
self.rules[new_var].add(('&', ))
self.CHECK_GRAMMAR()
def replace_terminals(self): # NOT CONST
"""
Pre_conditions: None
"""
new_v_id = 0
# var_to_terminal checks if variable already exists or if variable has already been created
# var_to_terminal does not consider already duplicated variables
def var_to_terminal(sym):
var = None
for v in self.variables:
if len(self.rules[v]) == 1 and self.rules[v][0] == (sym, ):
var = v
return var
for v in to_add_var:
if len(self.rules[v]) == 1 and self.rules[v][0] == (sym, ):
var = v
return var
return var
# create_new_v creates new variable
def create_new_v(sym):
nonlocal new_v_id
new_v_id += 1
new_v = "❬R{}❭".format(new_v_id)
to_add_var.add(new_v)
self.rules[new_v] = OrderedSet([(sym, )])
new_rules[new_v] = OrderedSet([(sym, )])
return new_v
to_add_var = OrderedSet()
new_rules = dict()
for v in self.variables:
to_add = OrderedSet()
for prod in self.rules[v]:
old_prod = list(prod)
if (len(old_prod) >= 2):
for i in range(len(old_prod)):
symbol = old_prod[i]
if symbol in self.terminals:
new_v = var_to_terminal(symbol)
if new_v is None:
new_v = create_new_v(symbol)
for j in range(i, len(old_prod)):
if old_prod[j] == symbol:
old_prod[j] = new_v
to_add.add(tuple(old_prod))
new_rules[v] = to_add
self.rules = new_rules
for v in to_add_var:
self.variables.add(v)
self.CHECK_GRAMMAR()
def remove_epsilon(self): # NOT CONST
def power_set(i, cuts):
"""Return the all possible cuts obtained by striking out a subset
of the nullable variables in the given production.
"""
if i == len(cuts[0]):
new_ps = OrderedSet()
for c in cuts:
new_c = tuple()
for c2 in c:
if c2 != "ε":
new_c += (c2, )
if len(new_c) > 0:
new_ps.add(new_c)
return new_ps
if cuts[0][i] in nullables:
to_add = OrderedSet()
for s in cuts:
to_add.add(s[:i] + ("ε", ) + s[i + 1:])
cuts.update(to_add)
return power_set(i + 1, cuts)
nullables = OrderedSet()
nullables.add("&")
# Find nullables through Hopcroft's algorithm
changed = True
while changed:
changed = False
for var, prods in self.rules.items():
for prod in prods:
if all([p in nullables
for p in prod]) and var not in nullables:
nullables.add(var)
changed = True
# Strike out nullables
for var in self.variables:
to_add = OrderedSet()
for prod in self.rules[var]:
to_add.update(power_set(0, OrderedSet([prod])))
self.rules[var].update(to_add)
if ("&", ) in self.rules[var]:
self.rules[var].discard(("&", ))
if self.start in nullables:
self.variables.add("❬'{}❭".format(self.start))
self.rules["❬'{}❭".format(self.start)] = OrderedSet([
(self.start, ), ("&", )
])
self.start = "❬'{}❭".format(self.start)
self.CHECK_GRAMMAR()
def remove_unproductives(self): # NOT CONST
"""
Notes
-----
If the grammar generates no words (empty language), then the grammar returned will be
start_symbol -> start_symbol
and it will keep its terminals.
"""
productives = OrderedSet()
for t in self.terminals:
productives.add(t)
productives.add("&")
changed = True
while changed:
changed = False
for var, prods in self.rules.items():
for prod in prods:
if all([p in productives
for p in prod]) and var not in productives:
productives.add(var)
changed = True
new_rules = dict()
for v in self.variables:
new_production = OrderedSet()
for production in self.rules[v]:
if all([p in productives for p in production]):
new_production.add(production)
new_rules[v] = new_production
self.rules = new_rules
to_remove = OrderedSet()
for v in self.variables:
if len(self.rules[v]) == 0:
to_remove.add(v)
for rem in to_remove:
del self.rules[rem]
self.variables.discard(rem)
# if empty language S -> S
if self.start not in self.rules.keys():
self.variables = OrderedSet()
self.rules = dict()
self.variables.add(self.start)
self.rules[self.start] = OrderedSet()
self.rules[self.start].add(self.start)
self.CHECK_GRAMMAR()
def power_set(i, cuts):
"""Return the all possible cuts obtained by striking out a subset
of the nullable variables in the given production.
"""
if i == len(cuts[0]):
new_ps = OrderedSet()
for c in cuts:
new_c = tuple()
for c2 in c:
if c2 != "ε":
new_c += (c2, )
if len(new_c) > 0:
new_ps.add(new_c)
return new_ps
if cuts[0][i] in nullables:
to_add = OrderedSet()
for s in cuts:
to_add.add(s[:i] + ("ε", ) + s[i + 1:])
cuts.update(to_add)
return power_set(i + 1, cuts)
def create_new_var_lcp(lcp):
nonlocal new_var_id
new_rules_old_v = OrderedSet()
new_var_id = new_var_id + 1
if len(v) == 1:
new_var = "❬{},{}❭".format(v, new_var_id)
else:
new_var = "❬{},{}❭".format(v[1], new_var_id)
self.rules[new_var] = OrderedSet()
self.variables.add(new_var)
# Factor
ll = len(lcp)
if lcp == ("&", ):
new_rules_old_v.add((new_var, ))
else:
new_rules_old_v.add(lcp + (new_var, ))
# Add prods to factored variable
for prod in self.rules[v]:
if prod[0] == conflict_terminal:
if len(prod[ll:]) != 0:
self.rules[new_var].add(prod[ll:])
else:
self.rules[new_var].add(("&", ))
else:
new_rules_old_v.add(prod)
self.rules[v] = new_rules_old_v
def reduce_size(self): # NOT CONST
# reduce_size does not check if new_v was already in the grammar
new_rules = dict()
to_add_var = OrderedSet()
number_v = -1
new_v_id = 0
for v in self.variables:
number_v += 1
new_v_id = 0
new_rules[v] = OrderedSet()
for prod in self.rules[v]:
lp = len(prod)
if lp > 2:
new_v = "❬C({},{})❭".format(number_v, new_v_id)
to_add_var.add(new_v)
new_v_id += 1
new_rules[new_v] = OrderedSet([(prod[lp - 2], prod[lp - 1])
])
for i in range(lp - 3, 0, -1):
old_v = new_v
new_v = "❬C({},{})❭".format(number_v, new_v_id)
to_add_var.add(new_v)
new_rules[new_v] = OrderedSet([(prod[i], old_v)])
new_v_id += 1
new_rules[v].update(OrderedSet([(prod[0], new_v)]))
else:
new_rules[v].add(prod)
self.rules = new_rules
for v in to_add_var:
self.variables.add(v)
self.CHECK_GRAMMAR()
def sub_var(prod):
to_add = OrderedSet()
for prod_var in self.rules[prod[0]]:
if prod_var == ("&", ):
if len(prod[1:]) == 0:
to_add.add(("&", ))
else:
to_add.add(prod[1:])
else:
to_add.add(prod_var + prod[1:])
return to_add
class ContextFreeGrammar:
def __init__(self, filename: str):
"""
Pre-conditions
--------------
1. filename doesn't name a .cfg file inside cfgs/
2. The file is an invalid grammar according to our context-free grammar specification (see spec.cfg)
Post-conditions
---------------
1. rules is properly tokenized using the three categories: terminal,
uppercase-variable, and brackets-variable.
2. variables is an OrderedSet with len > 0, where each entry is valid var
3. terminals is an OrderedSet, where each entry is a valid term (lower-case, len = 1)
4. rules is a dict where each variable has an OrderedSet entry
5. start is in variables
6. & is not in term
Notes
-----
The first grammar that is read, spec.cfg, is assumed to be valid; to confirm this,
you may run the unit tests.
"""
filepath = os.path.join(CFGS_DIR, filename)
assert filepath[-4:] == '.cfg', "Invalid extension"
self.variables = OrderedSet()
self.terminals = OrderedSet()
self.rules = dict()
self.start = None
with open(filepath, 'r') as f:
file_read = f.read()
ContextFreeGrammar.validate_cfg_word(file_read)
lines = file_read.split("\n")
for line in lines:
if line == lines[-1]:
assert len(line) == 0
continue
items = line.split()
var = items[0]
self.rules[var] = OrderedSet()
self.variables.add(var)
# First iteration
if self.start is None:
self.start = var
k = 2
while k < len(items):
raw = items[k]
# NOTE: is not a method since the pre-conds are not worth testing
# Tokenize rule
tokenized = []
i = 0
while i < len(raw):
c = raw[i]
if c == '❬': # brackets-variable
j = i + 1
while raw[j] != '❭':
j += 1
assert len(raw[i:j + 1]) > 3
tokenized.append(raw[i:j + 1])
i = j + 1
else: # uppercase-cariable or terminal
tokenized.append(c)
if c.isupper():
pass
else:
if c != "&":
self.terminals.add(c)
i += 1
self.rules[var].add(tuple(tokenized))
k += 2
self.CHECK_GRAMMAR()
def __str__(self) -> str: # CONST
string = ""
first = True
for rule in self.rules[self.start]:
if first:
string += "{} -> {} ".format(self.start, "".join(rule))
first = False
else:
string += "| {} ".format("".join(rule))
string = string[:-1] + "\n"
for var in self.variables:
if var == self.start:
continue
first = True
string += "{} -> ".format(var)
for rule in self.rules[var]:
if first:
string += "{} ".format("".join(rule))
first = False
else:
string += "| {} ".format("".join(rule))
string = string[:-1] + "\n"
return string
def save_to_file(self, filename: str): # CONST
filepath = os.path.join(CFGS_DIR, filename)
with open(filepath, 'w') as f:
f.write(str(self))
def CHECK_GRAMMAR(self): # CONST
"""Temporary method for forcing structure into python."""
# Assert post-conditions: 2-6.
assert type(self.variables) == OrderedSet and len(self.variables) > 0 \
and all([(v.isupper() and len(v) == 1) or (v[0] == '❬' and v[-1] == '❭' and len(v) > 2) for v in self.variables])
assert type(self.terminals) == OrderedSet and all(
[(t != '&') and (len(t) == 1) and not (t.isupper())
for t in self.terminals])
assert type(self.rules) == dict and self.rules.keys(
) == self.variables and all(
[type(val) == OrderedSet for val in self.rules.values()])
assert self.start in self.variables
@staticmethod
def validate_cfg_word(word: str) -> bool:
"""Check if `word` is a valid .cfg file; the .cfg file format is specified at spec.cfg
Labels
------
b: |
e: epsilon
n: newline
s: ->
t: lowercase
u: uppercase
o: ❬
c: ❭
"""
if VERIFY_GRAMMAR:
subst = [('\n', 'n'), ('|', 'b'), ('&', 'e'), ('->', 's'),
('❬', 'o'), ('❭', 'c')]
word2 = ''
i = 0
while i < len(word):
c = word[i]
if c.isupper():
word2 += 'u'
elif c == '-' and word[i + 1] == '>':
word2 += '->'
i += 1
elif c in {'\n', '|', '&', '❬', '❭'}:
word2 += c
elif c == ' ':
pass
else:
word2 += 't'
i += 1
for k, v in subst:
word2 = word2.replace(k, v)
if not SPEC_PARSER.parse(word2):
raise RuntimeError("This Grammar is not a valid .cfg file")
def has_e(self): # CONST
"""Tests if the grammar has &-rules that are not in the start symbol."""
for v in self.variables:
for prod in self.rules[v]:
if v != self.start and prod == ("&", ):
return True
return False
def has_cycle(self): # CONST
# (A, B) is an edge iff A => B is a rule
edges = {var: OrderedSet() for var in self.variables}
for head in self.variables:
for body in self.rules[head]:
if len(body) == 1 and body[0] in self.variables:
edges[head].add(body[0])
graph = Graph(self.variables, edges)
# Check if some V appears in B = > V, where B was visited by bfs(V)
for var in self.variables:
visited = graph.bfs(var)
for contender in self.variables:
if visited[contender]:
for prod in self.rules[contender]:
if prod == (var, ):
return True
return False
def remove_left_recursion(self): # NOT CONST
"""
Exceptions
--------------
1. self is not e-free.
2. self is not cycle-free.
Notes
-----
Be aware when Aj has no productions.
While removing direct recursion, one may end up with len(prods_i) == 0, since
there may be S => Sbeta, where beta has no productions.
"""
if self.has_e():
raise RuntimeError(
"A grammar must be &-free in order to remove left recursions.")
if self.has_cycle():
raise RuntimeError(
"A grammar must be cycle-free in order to remove left recursions."
)
# Remove indirect
for i in range(len(self.variables)):
direct = False
for j in range(i):
to_remove = set()
for production in self.rules[self.variables[i]]:
if self.variables[j] == production[0]:
alpha = production[1:]
to_remove.add(production)
for beta in self.rules[self.variables[j]]:
self.rules[self.variables[i]].add(beta + alpha)
for rem in to_remove:
self.rules[self.variables[i]].discard(rem)
for production in self.rules[self.variables[i]]:
if production[0] == self.variables[i]:
direct = True
if direct:
new_var = "❬{}'❭".format(self.variables[i])
self.variables.add(new_var)
self.rules[new_var] = OrderedSet()
new_prods_i = OrderedSet()
for production in self.rules[self.variables[i]]:
if production[0] == self.variables[i]:
self.rules[new_var].add(production[1:] + (new_var, ))
else:
new_prods_i.add(production + (new_var, ))
self.rules[self.variables[i]] = new_prods_i
self.rules[new_var].add(('&', ))
self.CHECK_GRAMMAR()
def remove_unit(self): # NOT CONST
"""
Post-conditions: may return variable with no production
Note:
In this algorithm cyclic productions will be eliminated.
A -> B A ->
B -> C --------> B ->
C -> A C ->
Our algorithm takes care of cyclic productions
"""
def not_unit(production):
return len(production) > 1 or production[0] not in self.variables
# (A, B) is an edge iff A => B is a rule
edges = {var: OrderedSet() for var in self.variables}
for head in self.variables:
for body in self.rules[head]:
if len(body) == 1 and body[0] in self.variables:
edges[head].add(body[0])
graph = Graph(self.variables, edges)
# Expand all reacheable unit productions
# NOTE: Each variable visits itself in bfs
new_rules = {var: OrderedSet() for var in self.variables}
for var in self.variables:
visited = graph.bfs(var)
for contender in self.variables:
if visited[contender]:
for prod in self.rules[contender]:
if not_unit(prod):
new_rules[var].add(prod)
self.rules = new_rules
self.CHECK_GRAMMAR()
def remove_epsilon(self): # NOT CONST
def power_set(i, cuts):
"""Return the all possible cuts obtained by striking out a subset
of the nullable variables in the given production.
"""
if i == len(cuts[0]):
new_ps = OrderedSet()
for c in cuts:
new_c = tuple()
for c2 in c:
if c2 != "ε":
new_c += (c2, )
if len(new_c) > 0:
new_ps.add(new_c)
return new_ps
if cuts[0][i] in nullables:
to_add = OrderedSet()
for s in cuts:
to_add.add(s[:i] + ("ε", ) + s[i + 1:])
cuts.update(to_add)
return power_set(i + 1, cuts)
nullables = OrderedSet()
nullables.add("&")
# Find nullables through Hopcroft's algorithm
changed = True
while changed:
changed = False
for var, prods in self.rules.items():
for prod in prods:
if all([p in nullables
for p in prod]) and var not in nullables:
nullables.add(var)
changed = True
# Strike out nullables
for var in self.variables:
to_add = OrderedSet()
for prod in self.rules[var]:
to_add.update(power_set(0, OrderedSet([prod])))
self.rules[var].update(to_add)
if ("&", ) in self.rules[var]:
self.rules[var].discard(("&", ))
if self.start in nullables:
self.variables.add("❬'{}❭".format(self.start))
self.rules["❬'{}❭".format(self.start)] = OrderedSet([
(self.start, ), ("&", )
])
self.start = "❬'{}❭".format(self.start)
self.CHECK_GRAMMAR()
def remove_unproductives(self): # NOT CONST
"""
Notes
-----
If the grammar generates no words (empty language), then the grammar returned will be
start_symbol -> start_symbol
and it will keep its terminals.
"""
productives = OrderedSet()
for t in self.terminals:
productives.add(t)
productives.add("&")
changed = True
while changed:
changed = False
for var, prods in self.rules.items():
for prod in prods:
if all([p in productives
for p in prod]) and var not in productives:
productives.add(var)
changed = True
new_rules = dict()
for v in self.variables:
new_production = OrderedSet()
for production in self.rules[v]:
if all([p in productives for p in production]):
new_production.add(production)
new_rules[v] = new_production
self.rules = new_rules
to_remove = OrderedSet()
for v in self.variables:
if len(self.rules[v]) == 0:
to_remove.add(v)
for rem in to_remove:
del self.rules[rem]
self.variables.discard(rem)
# if empty language S -> S
if self.start not in self.rules.keys():
self.variables = OrderedSet()
self.rules = dict()
self.variables.add(self.start)
self.rules[self.start] = OrderedSet()
self.rules[self.start].add(self.start)
self.CHECK_GRAMMAR()
def remove_unreachables(self): # NOT CONST
"""
Pre_conditions: None
"""
# (A, B) is an edge iff A => alfa and B is in alfa
# NOTE: doesn't take care of terminals
edges = {var: OrderedSet() for var in self.variables}
for head in self.variables:
for body in self.rules[head]:
for symbol in body:
if symbol in self.variables:
edges[head].add(symbol)
graph = Graph(self.variables, edges)
# Remove both the variables that were not visited and their rules
new_rules = {var: OrderedSet() for var in self.variables}
visited = graph.bfs(self.start)
for rem in OrderedSet([v for v in self.variables if not visited[v]]):
del self.rules[rem]
self.variables.discard(rem)
self.CHECK_GRAMMAR()
def replace_terminals(self): # NOT CONST
"""
Pre_conditions: None
"""
new_v_id = 0
# var_to_terminal checks if variable already exists or if variable has already been created
# var_to_terminal does not consider already duplicated variables
def var_to_terminal(sym):
var = None
for v in self.variables:
if len(self.rules[v]) == 1 and self.rules[v][0] == (sym, ):
var = v
return var
for v in to_add_var:
if len(self.rules[v]) == 1 and self.rules[v][0] == (sym, ):
var = v
return var
return var
# create_new_v creates new variable
def create_new_v(sym):
nonlocal new_v_id
new_v_id += 1
new_v = "❬R{}❭".format(new_v_id)
to_add_var.add(new_v)
self.rules[new_v] = OrderedSet([(sym, )])
new_rules[new_v] = OrderedSet([(sym, )])
return new_v
to_add_var = OrderedSet()
new_rules = dict()
for v in self.variables:
to_add = OrderedSet()
for prod in self.rules[v]:
old_prod = list(prod)
if (len(old_prod) >= 2):
for i in range(len(old_prod)):
symbol = old_prod[i]
if symbol in self.terminals:
new_v = var_to_terminal(symbol)
if new_v is None:
new_v = create_new_v(symbol)
for j in range(i, len(old_prod)):
if old_prod[j] == symbol:
old_prod[j] = new_v
to_add.add(tuple(old_prod))
new_rules[v] = to_add
self.rules = new_rules
for v in to_add_var:
self.variables.add(v)
self.CHECK_GRAMMAR()
def reduce_size(self): # NOT CONST
# reduce_size does not check if new_v was already in the grammar
new_rules = dict()
to_add_var = OrderedSet()
number_v = -1
new_v_id = 0
for v in self.variables:
number_v += 1
new_v_id = 0
new_rules[v] = OrderedSet()
for prod in self.rules[v]:
lp = len(prod)
if lp > 2:
new_v = "❬C({},{})❭".format(number_v, new_v_id)
to_add_var.add(new_v)
new_v_id += 1
new_rules[new_v] = OrderedSet([(prod[lp - 2], prod[lp - 1])
])
for i in range(lp - 3, 0, -1):
old_v = new_v
new_v = "❬C({},{})❭".format(number_v, new_v_id)
to_add_var.add(new_v)
new_rules[new_v] = OrderedSet([(prod[i], old_v)])
new_v_id += 1
new_rules[v].update(OrderedSet([(prod[0], new_v)]))
else:
new_rules[v].add(prod)
self.rules = new_rules
for v in to_add_var:
self.variables.add(v)
self.CHECK_GRAMMAR()
def convert_to_cnf(self): # NOT CONST
self.remove_epsilon()
self.remove_unit()
self.remove_unproductives()
self.remove_unreachables()
self.replace_terminals()
self.reduce_size()
def has_left_recursion(self): # CONST
# (A, B) is an edge iff A => B𝛼 is a rule in rules
edges = {v: OrderedSet() for v in self.variables}
for v in self.variables:
for prod in self.rules[v]:
if prod[0] in self.variables:
edges[v].add(prod[0])
graph = Graph(self.variables, edges)
return any([graph.has_loop(v) for v in self.variables])
def firsts(self): # CONST
"""
Exceptions
--------------
1. The grammar has left recursion.
"""
def first_var(v):
"""Calculate the first of a variable using Dynamic Programming."""
if len(first[v]) != 0:
return first[v]
for prod in self.rules[v]:
for p in prod:
to_add = first_var(p)
first[v].update(to_add)
# Stop when Xi doesn't have epsilon in its first
if "&" not in to_add:
first[v].discard("&")
break
return first[v]
if self.has_left_recursion():
raise RuntimeError(
"A grammar can't contain left recursion in ordered to calculate FIRSTS."
)
first = {
t: OrderedSet([t])
for t in OrderedSet(['&']) | self.terminals
}
first.update({v: OrderedSet() for v in self.variables})
for v in self.variables:
first_var(v)
return first
def first_body(self, body, first=None): # CONST
"""Calculate the first of a syntactical form."""
lb = len(body)
if first is None:
first = self.firsts()
total = OrderedSet()
for body in body:
to_add = first[body]
total.update(to_add)
if "&" not in to_add:
total.discard("&")
break
return total
def follows(self): # CONST
"""Compute the follows."""
first = self.firsts()
follow = {v: OrderedSet() for v in self.variables}
follow[self.start].add("$")
add = True
while (add):
add = False
for head, bodies in self.rules.items():
for body in bodies:
# Add FIRSTS
lb = len(body)
for i in range(lb - 1):
if body[i] in self.variables:
to_add = self.first_body(body[i + 1:], first)
to_add.discard("&")
if not (to_add <= follow[body[i]]):
add = True
follow[body[i]].update(to_add)
# Add FOLLOWS
to_add = follow[head]
to_add.discard("&")
for i in range(lb - 1, -1, -1):
if body[i] in self.variables:
if not to_add.issubset(follow[body[i]]):
add = True
follow[body[i]].update(to_add)
if "&" not in first[body[i]]:
break
else:
break
return follow
def make_LL1_table(self) -> dict(): # CONST
"""Compute LL(1) parsing table.
Exceptions
----------
1. The grammar does not have left recursion.
2. The grammar has Fi/Fi or Fi/Fo conflict.
"""
firsts = self.firsts()
follows = self.follows()
table = dict()
for v in self.variables:
for alpha in self.rules[v]:
first_alpha = self.first_body(alpha, firsts)
# If alpha = &, then skip the loop
for f in first_alpha - {'&'}:
if (v, f) in table.keys():
raise RuntimeError("First/First conflict at {}".format(
(v, f)))
else:
table[(v, f)] = alpha
if "&" in first_alpha:
for f in follows[v]:
if (v, f) in table.keys():
raise RuntimeError(
"First/Follow conflict at {}".format(v, f))
else:
table[(v, f)] = alpha
return table
def make_LL1_parser(self) -> PredictiveParser: # CONST
"""Build LL(1) Predictive Parser for this grammar."""
return PredictiveParser(self.make_LL1_table())
def left_factoring(self) -> bool: # NOT CONST
"""
Returns
-------
True: left factoring succeded
Exceptions
--------------
1. The grammar has left recursion.
"""
if self.has_left_recursion():
raise RuntimeError(
"A grammar can't have left recursion in ordered to be factored"
)
new_var_id = 0
def expose_indirect_ndet(conflict_terminal):
def sub_var(prod):
to_add = OrderedSet()
for prod_var in self.rules[prod[0]]:
if prod_var == ("&", ):
if len(prod[1:]) == 0:
to_add.add(("&", ))
else:
to_add.add(prod[1:])
else:
to_add.add(prod_var + prod[1:])
return to_add
cached_first = self.firsts()
substitution_happened = True
while substitution_happened:
substitution_happened = False
new_rules_v = OrderedSet()
for prod in self.rules[v]:
if prod[0] in self.variables and conflict_terminal in self.first_body(
prod, cached_first):
new_rules_v.update(sub_var(prod))
substitution_happened = True
else:
new_rules_v.add(prod)
self.rules[v] = new_rules_v
def create_new_var_lcp(lcp):
nonlocal new_var_id
new_rules_old_v = OrderedSet()
new_var_id = new_var_id + 1
if len(v) == 1:
new_var = "❬{},{}❭".format(v, new_var_id)
else:
new_var = "❬{},{}❭".format(v[1], new_var_id)
self.rules[new_var] = OrderedSet()
self.variables.add(new_var)
# Factor
ll = len(lcp)
if lcp == ("&", ):
new_rules_old_v.add((new_var, ))
else:
new_rules_old_v.add(lcp + (new_var, ))
# Add prods to factored variable
for prod in self.rules[v]:
if prod[0] == conflict_terminal:
if len(prod[ll:]) != 0:
self.rules[new_var].add(prod[ll:])
else:
self.rules[new_var].add(("&", ))
else:
new_rules_old_v.add(prod)
self.rules[v] = new_rules_old_v
def first_follow():
new_rules_old_v = OrderedSet()
to_discard = None
cached_firsts = self.firsts()
for prod in self.rules[v]:
lp = len(prod)
for i in range(lp - 1):
# Test if any variable Xi appearing in X1X2...Xn has a Fi/Fo conflict
# That is, ε in FIRST(Xi) AND FIRST(Xi) ∩ FIRST(Xi+1...Xn) ≠ Ø
if prod[i] in self.variables:
intersection = cached_firsts[
prod[i]] & self.first_body(prod[i + 1:],
cached_firsts)
intersection.discard("&")
if "&" in cached_firsts[
prod[i]] and len(intersection) != 0:
to_discard = prod
for prod_sub in self.rules[prod[i]]:
if prod_sub == ("&", ):
new_rules_old_v.add(prod[:i] +
prod[i + 1:])
else:
new_rules_old_v.add(prod[:i] + prod_sub +
prod[i + 1:])
break
if not to_discard is None:
break
self.rules[v].discard(to_discard)
self.rules[v].update(new_rules_old_v)
if not to_discard is None:
return True
return False
def first_first():
nonlocal conflict_terminal
cached_first = self.firsts()
# Search for non determinism
total = OrderedSet()
for prod in self.rules[v]:
for ter in self.first_body(prod, cached_first):
if ter in total and conflict_terminal is None:
conflict_terminal = ter
break
total.add(ter)
if conflict_terminal:
has_non_determinism = True
# print("\n\nGRAMMAR Before")
# print(self)
# Expose indirect
expose_indirect_ndet(conflict_terminal)
# print("\n\nGRAMMAR After Substitutions")
# print(self)
# Direct
lcp = os.path.commonprefix([
prod for prod in self.rules[v]
if prod[0] == conflict_terminal
])
create_new_var_lcp(lcp)
# print("\n\nGRAMMAR After Eliminating Direct")
# print(self)
return True
return False
for i in range(20):
has_non_determinism = False
for v in self.variables:
conflict_terminal = None
# Fi/Fo conflict always introduces Fi/Fi conflict
fi_fo = first_follow()
# Start another iteration of non-determinism remains
fi_fi = first_first()
if fi_fi:
has_non_determinism = True
break
if not has_non_determinism:
# print("Finished in {} step(s)".format(i))
self.CHECK_GRAMMAR()
return True
self.CHECK_GRAMMAR()
return False