示例#1
0
def print_query(query, families=False, pad=1):
    if type(query) in (sqlite3.Cursor, list):
        longest = ""
        results = []
        for q in query:
            results.append(q)
            longest = max((q[1], longest), key=len)  # to ensure proper padding
        for r in results:
            print_query(r, families=families, pad=len(longest))
        return
    n, p_str, sol = query
    family = ""
    if families:
        _p = Partition(*map(int, p_str.split(",")))
        if _p.is_one_dimensional():
            family = "[1D]"
        if _p.is_hook():
            family = "[HOOK]"
        elif _p.is_self_conjugate():
            family = "[SELF-CONJ]"
    print u"{:{pad}} \u22a2 {:2}: solution {} {}".format("(" + p_str + ")",
                                                         n,
                                                         sol,
                                                         family,
                                                         pad=pad +
                                                         2).encode("utf-8")
示例#2
0
def find_solution(shape,
                  verbose=False,
                  skip_known_families=True,
                  return_matrix=False):
    if type(shape) is Partition:
        shape = shape.vals
    if skip_known_families:
        p = Partition(*shape)
        if p.is_one_dimensional():
            if verbose:
                print "Skipping 1D partition"
            return 1
        elif p.is_self_conjugate():
            if verbose:
                print "Skipping self-conjugate partition"
            return 0
        elif p.is_hook():
            if verbose:
                print "Skipping hook partition"
            i = sum(p.vals)
            r = p.vals[1:].count(1)
            choose = factorial(i - 1) / (factorial(r) * factorial(i - 1 - r))
            if (i % 2, r % 2, choose % 2) == (1, 0, 1):
                return 1
            else:
                return 0
    if shape == (1, ):
        # isolate this case to avoid numpy exception when building matrix
        return 1
    if verbose:
        print "Generating all standard {}-tableaux...\n".format(shape)
    polys = []
    if verbose:
        print "-" * 20
    for t in [t for t in total_order(shape)][::-1]:
        standards = [t]
        #if verbose:
        #    print "Next tableaux:\n{}\n".format(t)
        poly = set([tab for tab in t.polytabloid() if tab != t])
        if len(poly) > 1:
            for s in poly:
                if s.vals != t.vals:
                    print "{} --> {}".format(t.vals, s.vals)
                    standards.append(s)
        polys.append(standards)
    columns = []
    if verbose:
        print "Creating matrix from polytabloids."
    for i, poly in enumerate(polys):
        vec = [0] * len(polys)
        vec[i] = 1
        if len(poly) > 1:
            for s in poly:
                #find the index of the standard tableaux
                x = [l[0] for l in polys].index(s)
                vec[x] = 1
        columns.append(vec)
    matrix = column_stack(columns)
    if return_matrix:
        print matrix
        return matrix
    if verbose:
        print matrix
    solution = map(int, linalg.solve(matrix, [1] * len(polys)))
    if verbose:
        print "Solution vector: {}".format(solution)
        print "Sum of standard coefficients is congruent to {} (mod 2).".format(
            sum(solution) % 2)
    return sum(solution)