示例#1
0
def test_list():
    f = formatting.TermFormatter(Engine(), quoted=False, ignore_ops=False)
    t = parse_query_term("[1, 2, 3, 4, 5 | X].")
    assert f.format(t) == "[1, 2, 3, 4, 5|_G0]"
    t = parse_query_term("[a, b, 'A$%%$$'|[]].")
    assert f.format(t) == "[a, b, A$%%$$]"
    t = parse_query_term("'.'(a, b, c).")
    assert f.format(t) == ".(a, b, c)"

    X = BindingVar()
    a = Callable.build('a')
    t = Callable.build(".", [a, X])
    X.binding = Callable.build(".", [a, Callable.build("[]")])
    assert f.format(t) == "[a, a]"
示例#2
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def test_list():
    f = formatting.TermFormatter(Engine(), quoted=False, ignore_ops=False)
    t = parse_query_term("[1, 2, 3, 4, 5 | X].")
    assert f.format(t) == "[1, 2, 3, 4, 5|_G0]"
    t = parse_query_term("[a, b, 'A$%%$$'|[]].")
    assert f.format(t) == "[a, b, A$%%$$]"
    t = parse_query_term("'.'(a, b, c).")
    assert f.format(t) == ".(a, b, c)"

    X = BindingVar()
    a = Callable.build('a')
    t = Callable.build(".", [a, X])
    X.binding = Callable.build(".", [a, Callable.build("[]")])
    assert f.format(t) == "[a, a]"
示例#3
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def test_copy_dereferences():
    from prolog.interpreter.memo import CopyMemo
    v1 = BindingVar()
    v1.binding = Number(10)
    v2 = v1.copy(None, CopyMemo())
    assert v2.num == 10
示例#4
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def test_copy_dereferences():
    from prolog.interpreter.memo import CopyMemo
    v1 = BindingVar()
    v1.binding = Number(10)
    v2 = v1.copy(None, CopyMemo())
    assert v2.num == 10