示例#1
0
    def conclude(self, assumptions):
        '''
        Try to automatically conclude this bi-directional implication by
        reducing its operands to true/false.
        '''
        from . import iff_t_t, iff_t_f, iff_f_t, iff_f_f, true_iff_true, false_iff_false
        if self in {true_iff_true, false_iff_false}:
            # should be proven via one of the imported theorems as a simple
            # special case
            try:
                self.evaluation(assumptions)
            except BaseException:
                return self.prove()
        try:
            # try to prove the bi-directional implication via evaluation reduction.
            # if that is possible, it is a relatively straightforward thing to
            # do.
            return Operation.conclude(assumptions)
        except BaseException:
            pass
        try:
            # Use a breadth-first search approach to find the shortest
            # path to get from one end-point to the other.
            return TransitiveRelation.conclude(self, assumptions)
        except BaseException:
            pass

        # the last attempt is to introduce the Iff via implications each way, an
        # essentially direct consequence of the definition.
        return self.conclude_by_definition(assumptions)
示例#2
0
 def conclude(self, assumptions):
     from proveit.logic import FALSE
     if is_irreducible_value(self.lhs) and is_irreducible_value(self.rhs):
         # prove that two irreducible values are not equal
         return self.lhs.not_equal(self.rhs, assumptions)
     if self.lhs == FALSE or self.rhs == FALSE:
         try:
             # prove something is not false by proving it to be true
             return self.conclude_via_double_negation(assumptions)
         except BaseException:
             pass
     if hasattr(self.lhs, 'not_equal') and is_irreducible_value(self.rhs):
         try:
             return self.lhs.not_equal(self.rhs, assumptions)
         except BaseException:
             pass
     if hasattr(self.lhs, 'deduce_not_equal'):
         # If there is a 'deduce_not_equal' method, use that.
         # The responsibility then shifts to that method for
         # determining what strategies should be attempted
         # (with the recommendation that it should not attempt
         # multiple non-trivial automation strategies).
         eq = self.lhs.deduce_not_equal(self, assumptions)
         if eq.expr != self:
             raise ValueError("'deduce_not_equal' not implemented "
                              "correctly; must deduce the 'inequality' "
                              "that it is given if it can: "
                              "'%s' != '%s'" % (eq.expr, self))
         return eq
     try:
         return self.conclude_as_folded(assumptions)
     except BaseException:
         # try the default (reduction)
         return Operation.conclude(assumptions)
示例#3
0
 def conclude(self, assumptions):
     from proveit.logic import FALSE
     if isIrreducibleValue(self.lhs) and isIrreducibleValue(self.rhs):
         # prove that two irreducible values are not equal
         return self.lhs.notEqual(self.rhs)
     if self.lhs == FALSE or self.rhs == FALSE:
         try:
             # prove something is not false by proving it to be true
             return self.concludeViaDoubleNegation(assumptions)
         except:
             pass
     if hasattr(self.lhs, 'notEquals') and isIrreducibleValue(self.rhs):
         try:
             return self.lhs.notEqual(self.rhs, assumptions)
         except:
             pass
     try:
         return self.concludeAsFolded(assumptions)
     except:
         return Operation.conclude(assumptions) # try the default (reduction)