def test_combine_num(self):
ab = BaseInfo(
self.ver,
self.combine_num
)
instance_combine_num = ab.grouping().result[0][1]
self.assertEqual(len(instance_combine_num[1:-1][0]), self.combine_num)
def test_empty_info(self):
ab = BaseInfo('', '', '')
with self.assertRaises(AttributeError):
ab.grouping()
def test_schedule_num(self):
schedule_num = 2
ab = BaseInfo(self.ver, self.combine_num, schedule_num)
instance_combine_num = ab.grouping().result[0][1]
self.assertEqual(len(instance_combine_num[0][0].split(',')), schedule_num)
def test_empty_info_version_host_isdict(self):
ab = BaseInfo({}, '', '')
self.assertIsNotNone(ab.grouping())
def test_info_errortype(self):
ab = BaseInfo({}, '1', 'sds')
self.assertIsNotNone(ab.grouping())
@contact:QQ4113291000
@time:2018/5/4.下午2:03
'''
'''
灰度测试用
pip install regal
'''
from regal import BaseInfo
#combine 希望以每组多少台服务器作为一组,进行用户群B的分流
ab = BaseInfo(
version_host={
'version-1.0':'192.168.0.1,192.168.0.2,192.168.0.3,192.168.0.4',
'version-2.0':'192.168.0.5,192.168.0.6,192.168.0.7,192.168.0.8',
}
,combine=2,
schedule=2)
# grouping() 进行分组
# smart_grouping = ab.grouping()
# grouping()方法还提供了priority_name参数，当需要在多版本发布的时候，设置优先级，指定你需要优先发布的'版本名'
smart_grouping = ab.grouping(priority_name='version-2.0')
print smart_grouping.result
for i in smart_grouping.iter_dict():
print i
if __name__ == '__main__':
def test_info_errortype(self):
ab = BaseInfo({}, "1", "sds")
self.assertIsNotNone(ab.grouping())
def test_schedule_num(self):
schedule_num = 2
ab = BaseInfo(self.ver, self.combine_num, schedule_num)
instance_combine_num = ab.grouping().result[0][1]
self.assertEqual(len(instance_combine_num[0][0].split(',')),
schedule_num)
def test_empty_info(self):
ab = BaseInfo('', '', '')
with self.assertRaises(AttributeError):
ab.grouping()
def test_combine_num(self):
ab = BaseInfo(self.ver, self.combine_num)
instance_combine_num = ab.grouping().result[0][1]
self.assertEqual(len(instance_combine_num[1:-1][0]), self.combine_num)
def test_info_errortype(self):
ab = BaseInfo({}, '1', 'sds')
self.assertIsNotNone(ab.grouping())
def test_empty_info_version_host_isdict(self):
ab = BaseInfo({}, '', '')
self.assertIsNotNone(ab.grouping())
# coding: utf-8
# regal v1.0 example
from regal import BaseInfo
ab = BaseInfo(
version_host={
'test-app-1.0.0-SNAPSHOT-201512191829.war':
'1.1.1.1,2.2.2.2,3.3.3.3,4.4.4.4,5.1.1.1,6.2.2.2,7.3.3.3,8.4.4.4'
},
combine=4, # 每组四台
schedule=3 # groupA组 分三台
)
cc = ab.grouping()
print cc.result
for i in cc.iter_dict():
print i
# 多版本支持
ab = BaseInfo(
version_host={
'ver1': '1.1.1.1,2.2.2.2,3.3.3.3,4.4.4.4',
'ver2': '1.1.1.1,2.2.2.2,3.3.3.3,4.4.4.4',
'ver3': '1.1.1.1,2.2.2.2,3.3.3.3,4.4.4.4',
'ver4': '1.1.1.1,2.2.2.2,3.3.3.3,4.4.4.4',
},
combine=3,
# schedule=2 # groupA组 分三台
)
cc = ab.grouping(priority_name='ver2') # priority_name 多版本的情况下可以作为优先级策略
# coding: utf-8
# regal v1.0 example
from regal import BaseInfo
ab = BaseInfo(
version_host={
'test-app-1.0.0-SNAPSHOT-201512191829.war': '1.1.1.1,2.2.2.2,3.3.3.3,4.4.4.4,5.1.1.1,6.2.2.2,7.3.3.3,8.4.4.4'},
combine=4, # 每组四台
schedule=3 # groupA组 分三台
)
cc = ab.grouping()
print cc.result
for i in cc.iter_dict():
print i
# 多版本支持
ab = BaseInfo(
version_host={'ver1': '1.1.1.1,2.2.2.2,3.3.3.3,4.4.4.4',
'ver2': '1.1.1.1,2.2.2.2,3.3.3.3,4.4.4.4',
'ver3': '1.1.1.1,2.2.2.2,3.3.3.3,4.4.4.4',
'ver4': '1.1.1.1,2.2.2.2,3.3.3.3,4.4.4.4',},
combine=3,
# schedule=2 # groupA组 分三台
)
cc = ab.grouping(priority_name='ver2') # priority_name 多版本的情况下可以作为优先级策略
print cc.result
for i in cc.iter_dict():