def FixOneOver(strin,displaystyle=True):
strout=strin
oi=strout.find('\\over')
if oi>-1:
leftpart=rwkstr(strout[0:oi-1])#the -1 is because the syntax will always be {{num}\\over{den}} and I don't want the } before \\over
linds=leftpart.findall('{{')
linds=reverse(linds)
for ti in linds:
tempnum=leftpart[ti+2:]
if checkonebalance(tempnum)==0:
break
num=tempnum
b4=leftpart[0:ti]
si=oi+len('\\over')+1
rightpart=rwkstr(strout[si:])
rinds=rightpart.findall('}}')
for ri in rinds:
tempden=rightpart[0:ri]
if checkonebalance(tempden)==0:
break
den=tempden
afterpart=rightpart[len(den)+2:]
strout=b4
if displaystyle:
strout+=' \\displaystyle '
strout+='\\frac{'+num+'}{'+den+'}'+afterpart
return strout
def FindEndofEnv(self, matchline=None):
if matchline is None:
matchline = self.matchline
n = -1
match = False
numleft = 0
numright = 0
while (not match) and (n < len(self.list)):
n += 1
curline = rwkstr(self.list[matchline+n])
numleft += len(curline.findall('{'))
numright += len(curline.findall('}'))
if numright >= numleft:
match = True
if match:
self.endline = matchline+n
return self.endline
else:
return None
def CountCurlies(strin):
mystr = rwkstr(strin)
numleft = len(mystr.findall('{'))
numright = len(mystr.findall('}'))
return numleft, numright
def checkonebalance(strin, openp='{',closep='}'):
strin=rwkstr(strin)
no=strin.findall(openp)
nc=strin.findall(closep)
return len(no)-len(nc)
def CleanItems(self, bullet='*'):
self.string = self.string.strip()
if self.string:
while self.string[0] == bullet:
self.string = self.string[1:]
self.string = rwkmisc.rwkstr(self.string.strip())
def __init__(self, stringin, reveallevel=None):
self.string = rwkmisc.rwkstr(stringin)
self.reveal = reveallevel
self.CleanItems()
