Python thread_radius_count_intersect示例

示例#1

文件： test_memory.py 项目： eraoul/sdm

 def test_radius_count_intersect(self, qty=10):
     #sdm.initialize()
     for i in range(qty):
         a = Bitstring()
         b = Bitstring()
         cnt1 = sdm.thread_radius_count_intersect(a, b)
         cnt2 = sdm.thread_radius_count_intersect(a, b)
         self.assertEqual(cnt1, cnt2)

示例#2

文件： test_memory.py 项目： xpontus/sdm

 def test_radius_count_intersect(self, qty=10):
     sdm.initialize()
     for i in range(qty):
         a = Bitstring()
         b = Bitstring()
         cnt1 = sdm.thread_radius_count_intersect(a, b)
         cnt2 = sdm.thread_radius_count_intersect(a, b)
         self.assertEqual(cnt1, cnt2)
     sdm.free()

示例#3

文件： sdm_utils.py 项目： agent-lee/sdm

def table_7_1():
    n = sdm.get_dimension()
    a = Bitstring()
    v = []
    for i in range(550):
        b = a.copy()
        b.bitrandomswap(i)
        v.append([ i, sdm.thread_radius_count_intersect(a, b) ])
        print i
        sys.stdout.flush()
    return v

示例#4

文件： sdm_utils.py 项目： xpontus/sdm

def table_7_1():
    n = sdm.get_dimension()
    a = Bitstring()
    v = []
    for i in range(550):
        b = a.copy()
        b.bitrandomswap(i)
        v.append([i, sdm.thread_radius_count_intersect(a, b)])
        print i
        sys.stdout.flush()
    return v