def additional_answer(self, Houses: SuperSequence):
(Nat1, Nat2) = n_Vars(2)
for _ in members([
House(nationality=Nat1, pet='zebra'),
House(nationality=Nat2, drink='water')
], Houses):
ans = f'\n\tThe {Nat1} both own a zebra and drink water.' if Nat1 == Nat2 else \
f'\n\tThe {Nat1} own a zebra, and the {Nat2} drink water.'
print(ans)
def zebra_problem(Houses):
for _ in forall([
# 1. The English live in the red house.
lambda: member(House(nationality='English', color='red'), Houses),
# lambda: print_SF(f'After 1: {Houses}', 'Succeed'),
# 2. The Spanish have a dog.
lambda: member(House(nationality='Spanish', pet='dog'), Houses),
# lambda: print_SF(f'After 2: {Houses}', 'Succeed'),
# 3. They drink coffee in the green house.
lambda: member(House(drink='coffee', color='green'), Houses),
# lambda: print_SF(f'After 3: {Houses}', 'Succeed'),
# 4. The Ukrainians drink tea.
lambda: member(House(nationality='Ukrainians', drink='tea'), Houses
),
# lambda: print_SF(f'After 4: {Houses}', 'Succeed'),
# 5. The green house is immediately to the right of the white house.
lambda: is_contiguous_in(
[House(color='white'),
House(color='green')], Houses),
# lambda: print_SF(f'After 5: {Houses}', 'Succeed'),
# 6. The Old Gold smokers have snails.
lambda: member(House(smoke='Old Gold', pet='snails'), Houses),
# lambda: print_SF(f'After 6: {Houses}', 'Succeed'),
# 7. They smoke Kool in the yellow house.
lambda: member(House(smoke='Kool', color='yellow'), Houses),
# lambda: print_SF(f'After 7: {Houses}', 'Succeed'),
# 8. They drink milk in the middle house.
# Note the use of a slice. Houses[2] picks the middle house.
lambda: unify(House(drink='milk'), Houses[2]),
# lambda: print_SF(f'After 8: {Houses}', 'Succeed'),
# 9. The Norwegians live in the first house on the left.
lambda: unify(House(nationality='Norwegians'), Houses.head()),
# lambda: print_SF(f'After 9: {Houses}', 'Succeed'),
# 10. The Chesterfield smokers live next to the fox.
lambda: next_to(House(smoke='Chesterfield'), House(pet='fox'),
Houses),
# lambda: print_SF(f'After 10: {Houses}', 'Succeed'),
# 11. They smoke Kool in the house next to the horse.
lambda: next_to(House(smoke='Kool'), House(pet='horse'), Houses),
# lambda: print_SF(f'After 11: {Houses}', 'Succeed'),
# 12. The Lucky smokers drink juice.
lambda: member(House(drink='juice', smoke='Lucky'), Houses),
# lambda: print_SF(f'After 12: {Houses}', 'Succeed'),
# 13. The Japanese smoke Parliament.
lambda: member(House(nationality='Japanese', smoke='Parliament'),
Houses),
# lambda: print_SF(f'After 13: {Houses}', 'Succeed'),
# 14. The Norwegians live next to the blue house.
lambda: next_to(House(nationality='Norwegians'), House(color='blue'
), Houses),
# lambda: print_SF(f'After 14: {Houses}', 'Succeed'),
# Fill in unmentioned properties.
lambda: members([House(pet='zebra'),
House(drink='water')], Houses),
]):
yield
if __name__ == '__main__':
from timeit import default_timer as timer
(start1, end1, start2, end2) = (timer(), None, None, None)
Houses = LinkedList([House() for _ in range(5)])
inp = None
for _ in zebra_problem(Houses):
print('\nHouses: ')
for (indx, house) in enumerate(Houses.to_python_list()):
print(f'\t{indx+1}. {house}')
(Nat1, Nat2) = n_Vars(2)
for _ in members([
House(nationality=Nat1, pet='zebra'),
House(nationality=Nat2, drink='water')
], Houses):
ans = f'The {Nat1} both own a zebra and drink water.' if Nat1 == Nat2 else \
f'The {Nat1} own a zebra, and the {Nat2} drink water.'
end1 = timer()
print(ans)
inp = input('\nMore? (y, or n)? > ').lower()
start2 = timer()
if inp != 'y':
break
if inp == 'y':
print('No more solutions.')
end2 = timer()
def clue_15(self, Houses: SuperSequence):
""" 15 (implicit) Fill in unmentioned properties. """
yield from members([House(pet='zebra'), House(drink='water')], Houses)