Python TestCommon.eval_coor_expression示例

示例#1

文件： test_msm_symbolic.py 项目： renatocoutinho/sfepy

def rhs(ts, coor, mode=None, expression=None, **kwargs):
    if mode == 'qp':
        if expression is None:
            expression = '0.0 * x'

        val = TestCommon.eval_coor_expression( expression, coor )
        val.shape = (val.shape[0], 1, 1)
        return {'val' : val}

示例#2

文件： test_msm_symbolic.py 项目： marcinch18/sfepy

def rhs(ts, coor, mode=None, expression=None, **kwargs):
    if mode == 'qp':
        if expression is None:
            expression = '0.0 * x'

        val = TestCommon.eval_coor_expression( expression, coor )
        val.shape = (val.shape[0], 1, 1)
        return {'val' : val}

示例#3

def ebc(ts, coor, **kwargs):
    expression = solution[0]
    val = TestCommon.eval_coor_expression(expression, coor)
    return nm.atleast_1d(val)

示例#4

文件： test_msm_symbolic.py 项目： renatocoutinho/sfepy

def ebc(ts, coor, solution=None):
    expression = solution[0]
    val = TestCommon.eval_coor_expression( expression, coor )
    return nm.atleast_1d( val )

示例#5

文件： test_msm_laplace.py 项目： certik/sfepy

def rhs( ts, coor, region, ig, expression = None ):
    if expression is None:
        expression = '0.0 * x'

    val = TestCommon.eval_coor_expression( expression, coor )
    return {'val' : nm.atleast_1d( val )}