Python splitrelease示例

示例#1

文件： base.py 项目： bjmingyang/spacewalk

 def search(self, searcher):
     myname = self.name
     myversion = self.version
     ratio = 0
     for nameversion, cutoff in searcher.nameversion:
         _, ratio1 = globdistance(nameversion, myname, cutoff)
         _, ratio2 = globdistance(nameversion,
                                  "%s-%s" % (myname, myversion), cutoff)
         _, ratio3 = globdistance(nameversion, "%s-%s" %
                                  (myname, splitrelease(myversion)[0]),
                                  cutoff)
         ratio = max(ratio, ratio1, ratio2, ratio3)
     if ratio:
         searcher.addResult(self, ratio)

示例#2

文件： base.py 项目： larkit-ian/spacewalk

 def search(self, searcher):
     myname = self.name
     myversion = self.version
     ratio = 0
     for nameversion, cutoff in searcher.nameversion:
         _, ratio1 = globdistance(nameversion, myname, cutoff)
         _, ratio2 = globdistance(nameversion,
                                  "%s-%s" % (myname, myversion), cutoff)
         _, ratio3 = globdistance(nameversion, "%s-%s" %
                                  (myname, splitrelease(myversion)[0]),
                                  cutoff)
         ratio = max(ratio, ratio1, ratio2, ratio3)
     if ratio:
         searcher.addResult(self, ratio)

示例#3

 def test_splitrelease(self):
     version, release = splitrelease("1.0-1_0ubuntu0.10.04")
     self.assertEquals(version, "1.0")
     self.assertEquals(release, "1_0ubuntu0.10.04")

示例#4

文件： debbase.py 项目： blackPantherOS/packagemanagement

 def test_splitrelease(self):
     version, release = splitrelease("1.0-1_0ubuntu0.10.04")
     self.assertEquals(version, "1.0")
     self.assertEquals(release, "1_0ubuntu0.10.04")