示例#1
0
def test_uniform():
    l = Symbol('l', real=True)
    w = Symbol('w', positive=True)
    X = Uniform('x', l, l + w)

    assert E(X) == l + w/2
    assert variance(X).expand() == w**2/12

    # With numbers all is well
    X = Uniform('x', 3, 5)
    assert P(X < 3) == 0 and P(X > 5) == 0
    assert P(X < 4) == P(X > 4) == S.Half

    z = Symbol('z')
    p = density(X)(z)
    assert p.subs(z, 3.7) == S.Half
    assert p.subs(z, -1) == 0
    assert p.subs(z, 6) == 0

    c = cdf(X)
    assert c(2) == 0 and c(3) == 0
    assert c(Rational(7, 2)) == Rational(1, 4)
    assert c(5) == 1 and c(6) == 1
示例#2
0
def test_chi_squared():
    k = Symbol("k", integer=True)
    X = ChiSquared('x', k)

    # Tests the characteristic function
    assert characteristic_function(X)(x) == ((-2 * I * x + 1)**(-k / 2))

    assert density(X)(x) == 2**(-k / 2) * x**(k / 2 - 1) * exp(-x / 2) / gamma(
        k / 2)
    assert cdf(X)(x) == Piecewise(
        (lowergamma(k / 2, x / 2) / gamma(k / 2), x >= 0), (0, True))
    assert E(X) == k
    assert variance(X) == 2 * k

    X = ChiSquared('x', 15)
    assert cdf(X)(3) == -14873 * sqrt(6) * exp(Rational(
        -3, 2)) / (5005 * sqrt(pi)) + erf(sqrt(6) / 2)

    k = Symbol("k", integer=True, positive=False)
    raises(ValueError, lambda: ChiSquared('x', k))

    k = Symbol("k", integer=False, positive=True)
    raises(ValueError, lambda: ChiSquared('x', k))
def test_uniform():
    l = Symbol('l', real=True, finite=True)
    w = Symbol('w', positive=True, finite=True)
    X = Uniform('x', l, l + w)

    assert simplify(E(X)) == l + w / 2
    assert simplify(variance(X)) == w**2 / 12

    # With numbers all is well
    X = Uniform('x', 3, 5)
    assert P(X < 3) == 0 and P(X > 5) == 0
    assert P(X < 4) == P(X > 4) == S.Half

    z = Symbol('z')
    p = density(X)(z)
    assert p.subs(z, 3.7) == S(1) / 2
    assert p.subs(z, -1) == 0
    assert p.subs(z, 6) == 0

    c = cdf(X)
    assert c(2) == 0 and c(3) == 0
    assert c(S(7) / 2) == S(1) / 4
    assert c(5) == 1 and c(6) == 1
示例#4
0
def test_unevaluated_CompoundDist():
    # these tests need to be removed once they work with evaluation as they are currently not
    # evaluated completely in sympy.
    R = Rayleigh('R', 4)
    X = Normal('X', 3, R)
    _k = Dummy('k')
    exprd = Piecewise(
        (exp(S(3) / 4 - x / 4) / 8, 2 * Abs(arg(x - 3)) <= pi / 2),
        (sqrt(2) * Integral(exp(-(_k**4 + 16 * (x - 3)**2) / (32 * _k**2)),
                            (_k, 0, oo)) / (32 * sqrt(pi)), True))
    assert (density(X)(x).simplify()).dummy_eq(exprd.simplify())

    expre = Integral(
        _k * Integral(
            sqrt(2) * exp(-_k**2 / 32) * exp(-(_k - 3)**2 / (2 * _k**2)) /
            (32 * sqrt(pi)), (_k, 0, oo)), (_k, -oo, oo))
    with ignore_warnings(
            UserWarning):  ### TODO: Restore tests once warnings are removed
        assert E(X, evaluate=False).rewrite(Integral).dummy_eq(expre)

    X = Poisson('X', 1)
    Y = Poisson('Y', X)
    Z = Poisson('Z', Y)
    exprd = exp(-1) * Sum(
        exp(-Y) * Y**x *
        Sum(exp(-X) * X**Y / (factorial(X) * factorial(Y)),
            (X, 0, oo)), (Y, 0, oo)) / factorial(x)
    assert density(Z)(x).simplify() == exprd

    N = Normal('N', 1, 2)
    M = Normal('M', 3, 4)
    D = Normal('D', M, N)
    exprd = Integral(
        sqrt(2) * exp(-(_k - 1)**2 / 8) * Integral(
            exp(-(-_k + x)**2 / (2 * _k**2)) * exp(-(_k - 3)**2 / 32) /
            (8 * pi * _k), (_k, -oo, oo)) / (4 * sqrt(pi)), (_k, -oo, oo))
    assert density(D, evaluate=False)(x).dummy_eq(exprd)
示例#5
0
def test_PowerFunction():
    alpha = Symbol("alpha", nonpositive=True)
    a, b = symbols('a, b', real=True)
    raises (ValueError, lambda: PowerFunction('x', alpha, a, b))

    a, b = symbols('a, b', real=False)
    raises (ValueError, lambda: PowerFunction('x', alpha, a, b))

    alpha = Symbol("alpha", positive=True)
    a, b = symbols('a, b', real=True)
    raises (ValueError, lambda: PowerFunction('x', alpha, 5, 2))

    X = PowerFunction('X', 2, a, b)
    assert density(X)(z) == (-2*a + 2*z)/(-a + b)**2
    assert cdf(X)(z) == Piecewise((a**2/(a**2 - 2*a*b + b**2) -
        2*a*z/(a**2 - 2*a*b + b**2) + z**2/(a**2 - 2*a*b + b**2), a <= z), (0, True))

    X = PowerFunction('X', 2, 0, 1)
    assert density(X)(z) == 2*z
    assert cdf(X)(z) == Piecewise((z**2, z >= 0), (0,True))
    assert E(X) == Rational(2,3)
    assert P(X < 0) == 0
    assert P(X < 1) == 1
    assert median(X) == FiniteSet(1/sqrt(2))
示例#6
0
def test_robust_soliton():
    raises(ValueError, lambda : RobustSoliton('robSol', -12, 0.1, 0.02))
    raises(ValueError, lambda : RobustSoliton('robSol', 13, 1.89, 0.1))
    raises(ValueError, lambda : RobustSoliton('robSol', 15, 0.6, -2.31))
    f = Function('f')
    raises(ValueError, lambda : density(RobustSoliton('robSol', 15, 0.6, 0.1)).pmf(f))

    k = Symbol('k', integer=True, positive=True)
    delta = Symbol('delta', positive=True)
    c = Symbol('c', positive=True)
    robSol = RobustSoliton('robSol', k, delta, c)
    assert density(robSol).low == 1
    assert density(robSol).high == k

    k_vals = [10, 20, 50]
    delta_vals = [0.2, 0.4, 0.6]
    c_vals = [0.01, 0.03, 0.05]
    for x in k_vals:
        for y in delta_vals:
            for z in c_vals:
                assert E(robSol.subs({k: x, delta: y, c: z})) == moment(robSol.subs({k: x, delta: y, c: z}), 1)
                assert variance(robSol.subs({k: x, delta: y, c: z})) == cmoment(robSol.subs({k: x, delta: y, c: z}), 2)
                assert skewness(robSol.subs({k: x, delta: y, c: z})) == smoment(robSol.subs({k: x, delta: y, c: z}), 3)
                assert kurtosis(robSol.subs({k: x, delta: y, c: z})) == smoment(robSol.subs({k: x, delta: y, c: z}), 4)
示例#7
0
def test_reciprocal():
    a = Symbol("a", real=True)
    b = Symbol("b", real=True)

    X = Reciprocal('x', a, b)
    assert density(X)(x) == 1 / (x * (-log(a) + log(b)))
    assert cdf(X)(x) == Piecewise(
        (log(a) / (log(a) - log(b)) - log(x) / (log(a) - log(b)), a <= x),
        (0, True))
    X = Reciprocal('x', 5, 30)

    assert E(X) == 25 / (log(30) - log(5))
    assert P(X < 4) == S.Zero
    assert P(
        X < 20) == log(20) / (log(30) - log(5)) - log(5) / (log(30) - log(5))
    assert cdf(X)(
        10) == log(10) / (log(30) - log(5)) - log(5) / (log(30) - log(5))

    a = symbols('a', nonpositive=True)
    raises(ValueError, lambda: Reciprocal('x', a, b))

    a = symbols('a', positive=True)
    b = symbols('b', positive=True)
    raises(ValueError, lambda: Reciprocal('x', a + b, a))
示例#8
0
def test_gamma():
    k = Symbol("k", positive=True)
    theta = Symbol("theta", positive=True)
    x = Symbol("x")

    X = Gamma(k, theta, symbol=x)
    assert density(X) == Lambda(
        _x,
        _x**(k - 1) * theta**(-k) * exp(-_x / theta) / gamma(k))
    assert cdf(X, meijerg=True) == Lambda(
        _z,
        Piecewise((0, _z < 0),
                  (-k * lowergamma(k, 0) / gamma(k + 1) +
                   k * lowergamma(k, _z / theta) / gamma(k + 1), True)))
    assert variance(X) == (
        -theta**2 * gamma(k + 1)**2 / gamma(k)**2 +
        theta * theta**(-k) * theta**(k + 1) * gamma(k + 2) / gamma(k))

    k, theta = symbols('k theta', real=True, bounded=True, positive=True)
    X = Gamma(k, theta)

    assert simplify(E(X)) == k * theta
    # can't get things to simplify on this one so we use subs
    assert variance(X).subs(k, 5) == (k * theta**2).subs(k, 5)
示例#9
0
def test_hypergeometric_symbolic():
    N, m, n = symbols('N, m, n')
    H = Hypergeometric('H', N, m, n)
    dens = density(H).dict
    expec = E(H > 2)
    assert dens == Density(HypergeometricDistribution(N, m, n))
    assert dens.subs(N,
                     5).doit() == Density(HypergeometricDistribution(5, m, n))
    assert set(dens.subs({
        N: 3,
        m: 2,
        n: 1
    }).doit().keys()) == set([S(0), S(1)])
    assert set(dens.subs({
        N: 3,
        m: 2,
        n: 1
    }).doit().values()) == set([S(1) / 3, S(2) / 3])
    k = Dummy('k', integer=True)
    assert expec.dummy_eq(
        Sum(
            Piecewise(
                (k * binomial(m, k) * binomial(N - m, -k + n) / binomial(N, n),
                 k > 2), (0, True)), (k, 0, n)))
示例#10
0
def test_PoissonProcess():
    X = PoissonProcess("X", 3)
    assert X.state_space == S.Naturals0
    assert X.index_set == Interval(0, oo)
    assert X.lamda == 3

    t, d, x, y = symbols('t d x y', positive=True)
    assert isinstance(X(t), RandomIndexedSymbol)
    assert X.distribution(t) == PoissonDistribution(3 * t)
    raises(ValueError, lambda: PoissonProcess("X", -1))
    raises(NotImplementedError, lambda: X[t])
    raises(IndexError, lambda: X(-5))

    assert X.joint_distribution(X(2), X(3)) == JointDistributionHandmade(
        Lambda((X(2), X(3)), 6**X(2) * 9**X(3) * exp(-15) /
               (factorial(X(2)) * factorial(X(3)))))

    assert X.joint_distribution(4, 6) == JointDistributionHandmade(
        Lambda((X(4), X(6)), 12**X(4) * 18**X(6) * exp(-30) /
               (factorial(X(4)) * factorial(X(6)))))

    assert P(X(t) < 1) == exp(-3 * t)
    assert P(Eq(X(t), 0),
             Contains(t, Interval.Lopen(3, 5))) == exp(-6)  # exp(-2*lamda)
    res = P(Eq(X(t), 1), Contains(t, Interval.Lopen(3, 4)))
    assert res == 3 * exp(-3)

    # Equivalent to P(Eq(X(t), 1))**4 because of non-overlapping intervals
    assert P(
        Eq(X(t), 1) & Eq(X(d), 1) & Eq(X(x), 1) & Eq(X(y), 1),
        Contains(t, Interval.Lopen(0, 1))
        & Contains(d, Interval.Lopen(1, 2)) & Contains(x, Interval.Lopen(2, 3))
        & Contains(y, Interval.Lopen(3, 4))) == res**4

    # Return Probability because of overlapping intervals
    assert P(Eq(X(t), 2) & Eq(X(d), 3), Contains(t, Interval.Lopen(0, 2))
    & Contains(d, Interval.Ropen(2, 4))) == \
                Probability(Eq(X(d), 3) & Eq(X(t), 2), Contains(t, Interval.Lopen(0, 2))
                & Contains(d, Interval.Ropen(2, 4)))

    raises(ValueError, lambda: P(
        Eq(X(t), 2) & Eq(X(d), 3),
        Contains(t, Interval.Lopen(0, 4)) & Contains(d, Interval.Lopen(3, oo)))
           )  # no bound on d
    assert P(Eq(X(3), 2)) == 81 * exp(-9) / 2
    assert P(Eq(X(t), 2), Contains(t, Interval.Lopen(0,
                                                     5))) == 225 * exp(-15) / 2

    # Check that probability works correctly by adding it to 1
    res1 = P(X(t) <= 3, Contains(t, Interval.Lopen(0, 5)))
    res2 = P(X(t) > 3, Contains(t, Interval.Lopen(0, 5)))
    assert res1 == 691 * exp(-15)
    assert (res1 + res2).simplify() == 1

    # Check Not and  Or
    assert P(Not(Eq(X(t), 2) & (X(d) > 3)), Contains(t, Interval.Ropen(2, 4)) & \
            Contains(d, Interval.Lopen(7, 8))).simplify() == -18*exp(-6) + 234*exp(-9) + 1
    assert P(Eq(X(t), 2) | Ne(X(t), 4),
             Contains(t, Interval.Ropen(2, 4))) == 1 - 36 * exp(-6)
    raises(ValueError, lambda: P(X(t) > 2, X(t) + X(d)))
    assert E(
        X(t)) == 3 * t  # property of the distribution at a given timestamp
    assert E(
        X(t)**2 + X(d) * 2 + X(y)**3,
        Contains(t, Interval.Lopen(0, 1))
        & Contains(d, Interval.Lopen(1, 2))
        & Contains(y, Interval.Ropen(3, 4))) == 75
    assert E(X(t)**2, Contains(t, Interval.Lopen(0, 1))) == 12
    assert E(x*(X(t) + X(d))*(X(t)**2+X(d)**2), Contains(t, Interval.Lopen(0, 1))
    & Contains(d, Interval.Ropen(1, 2))) == \
            Expectation(x*(X(d) + X(t))*(X(d)**2 + X(t)**2), Contains(t, Interval.Lopen(0, 1))
            & Contains(d, Interval.Ropen(1, 2)))

    # Value Error because of infinite time bound
    raises(ValueError, lambda: E(X(t)**3, Contains(t, Interval.Lopen(1, oo))))

    # Equivalent to E(X(t)**2) - E(X(d)**2) == E(X(1)**2) - E(X(1)**2) == 0
    assert E((X(t) + X(d)) * (X(t) - X(d)),
             Contains(t, Interval.Lopen(0, 1))
             & Contains(d, Interval.Lopen(1, 2))) == 0
    assert E(X(2) + x * E(X(5))) == 15 * x + 6
    assert E(x * X(1) + y) == 3 * x + y
    assert P(Eq(X(1), 2) & Eq(X(t), 3),
             Contains(t, Interval.Lopen(1, 2))) == 81 * exp(-6) / 4
    Y = PoissonProcess("Y", 6)
    Z = X + Y
    assert Z.lamda == X.lamda + Y.lamda == 9
    raises(ValueError,
           lambda: X + 5)  # should be added be only PoissonProcess instance
    N, M = Z.split(4, 5)
    assert N.lamda == 4
    assert M.lamda == 5
    raises(ValueError, lambda: Z.split(3, 2))  # 2+3 != 9

    raises(
        ValueError, lambda: P(Eq(X(t), 0),
                              Contains(t, Interval.Lopen(1, 3)) & Eq(X(1), 0)))
    # check if it handles queries with two random variables in one args
    res1 = P(Eq(N(3), N(5)))
    assert res1 == P(Eq(N(t), 0), Contains(t, Interval(3, 5)))
    res2 = P(N(3) > N(1))
    assert res2 == P((N(t) > 0), Contains(t, Interval(1, 3)))
    assert P(N(3) < N(1)) == 0  # condition is not possible
    res3 = P(N(3) <= N(1))  # holds only for Eq(N(3), N(1))
    assert res3 == P(Eq(N(t), 0), Contains(t, Interval(1, 3)))

    # tests from https://www.probabilitycourse.com/chapter11/11_1_2_basic_concepts_of_the_poisson_process.php
    X = PoissonProcess('X', 10)  # 11.1
    assert P(Eq(X(S(1) / 3), 3)
             & Eq(X(1), 10)) == exp(-10) * Rational(8000000000, 11160261)
    assert P(Eq(X(1), 1), Eq(X(S(1) / 3), 3)) == 0
    assert P(Eq(X(1), 10), Eq(X(S(1) / 3), 3)) == P(Eq(X(S(2) / 3), 7))

    X = PoissonProcess('X', 2)  # 11.2
    assert P(X(S(1) / 2) < 1) == exp(-1)
    assert P(X(3) < 1, Eq(X(1), 0)) == exp(-4)
    assert P(Eq(X(4), 3), Eq(X(2), 3)) == exp(-4)

    X = PoissonProcess('X', 3)
    assert P(Eq(X(2), 5) & Eq(X(1), 2)) == Rational(81, 4) * exp(-6)

    # check few properties
    assert P(
        X(2) <= 3,
        X(1) >= 1) == 3 * P(Eq(X(1), 0)) + 2 * P(Eq(X(1), 1)) + P(Eq(X(1), 2))
    assert P(X(2) <= 3, X(1) > 1) == 2 * P(Eq(X(1), 0)) + 1 * P(Eq(X(1), 1))
    assert P(Eq(X(2), 5) & Eq(X(1), 2)) == P(Eq(X(1), 3)) * P(Eq(X(1), 2))
    assert P(Eq(X(3), 4), Eq(X(1), 3)) == P(Eq(X(2), 1))

    #test issue 20078
    assert (2 * X(t) + 3 * X(t)).simplify() == 5 * X(t)
    assert (2 * X(t) - 3 * X(t)).simplify() == -X(t)
    assert (2 * (0.25 * X(t))).simplify() == 0.5 * X(t)
    assert (2 * X(t) * 0.25 * X(t)).simplify() == 0.5 * X(t)**2
    assert (X(t)**2 + X(t)**3).simplify() == (X(t) + 1) * X(t)**2
示例#11
0
def test_BernoulliProcess():

    B = BernoulliProcess("B", p=0.6, success=1, failure=0)
    assert B.state_space == FiniteSet(0, 1)
    assert B.index_set == S.Naturals0
    assert B.success == 1
    assert B.failure == 0

    X = BernoulliProcess("X", p=Rational(1, 3), success='H', failure='T')
    assert X.state_space == FiniteSet('H', 'T')
    H, T = symbols("H,T")
    assert E(X[1] + X[2] * X[3]
             ) == H**2 / 9 + 4 * H * T / 9 + H / 3 + 4 * T**2 / 9 + 2 * T / 3

    t, x = symbols('t, x', positive=True, integer=True)
    assert isinstance(B[t], RandomIndexedSymbol)

    raises(ValueError,
           lambda: BernoulliProcess("X", p=1.1, success=1, failure=0))
    raises(NotImplementedError, lambda: B(t))

    raises(IndexError, lambda: B[-3])
    assert B.joint_distribution(B[3], B[9]) == JointDistributionHandmade(
        Lambda(
            (B[3], B[9]),
            Piecewise((0.6, Eq(B[3], 1)), (0.4, Eq(B[3], 0)),
                      (0, True)) * Piecewise((0.6, Eq(B[9], 1)),
                                             (0.4, Eq(B[9], 0)), (0, True))))

    assert B.joint_distribution(2, B[4]) == JointDistributionHandmade(
        Lambda(
            (B[2], B[4]),
            Piecewise((0.6, Eq(B[2], 1)), (0.4, Eq(B[2], 0)),
                      (0, True)) * Piecewise((0.6, Eq(B[4], 1)),
                                             (0.4, Eq(B[4], 0)), (0, True))))

    # Test for the sum distribution of Bernoulli Process RVs
    Y = B[1] + B[2] + B[3]
    assert P(Eq(Y, 0)).round(2) == Float(0.06, 1)
    assert P(Eq(Y, 2)).round(2) == Float(0.43, 2)
    assert P(Eq(Y, 4)).round(2) == 0
    assert P(Gt(Y, 1)).round(2) == Float(0.65, 2)
    # Test for independency of each Random Indexed variable
    assert P(Eq(B[1], 0) & Eq(B[2], 1) & Eq(B[3], 0)
             & Eq(B[4], 1)).round(2) == Float(0.06, 1)

    assert E(2 * B[1] + B[2]).round(2) == Float(1.80, 3)
    assert E(2 * B[1] + B[2] + 5).round(2) == Float(6.80, 3)
    assert E(B[2] * B[4] + B[10]).round(2) == Float(0.96, 2)
    assert E(B[2] > 0, Eq(B[1], 1) & Eq(B[2], 1)).round(2) == Float(0.60, 2)
    assert E(B[1]) == 0.6
    assert P(B[1] > 0).round(2) == Float(0.60, 2)
    assert P(B[1] < 1).round(2) == Float(0.40, 2)
    assert P(B[1] > 0, B[2] <= 1).round(2) == Float(0.60, 2)
    assert P(B[12] * B[5] > 0).round(2) == Float(0.36, 2)
    assert P(B[12] * B[5] > 0, B[4] < 1).round(2) == Float(0.36, 2)
    assert P(Eq(B[2], 1), B[2] > 0) == 1
    assert P(Eq(B[5], 3)) == 0
    assert P(Eq(B[1], 1), B[1] < 0) == 0
    assert P(B[2] > 0, Eq(B[2], 1)) == 1
    assert P(B[2] < 0, Eq(B[2], 1)) == 0
    assert P(B[2] > 0, B[2] == 7) == 0
    assert P(B[5] > 0, B[5]) == BernoulliDistribution(0.6, 0, 1)
    raises(ValueError, lambda: P(3))
    raises(ValueError, lambda: P(B[3] > 0, 3))

    # test issue 19456
    expr = Sum(B[t], (t, 0, 4))
    expr2 = Sum(B[t], (t, 1, 3))
    expr3 = Sum(B[t]**2, (t, 1, 3))
    assert expr.doit() == B[0] + B[1] + B[2] + B[3] + B[4]
    assert expr2.doit() == Y
    assert expr3.doit() == B[1]**2 + B[2]**2 + B[3]**2
    assert B[2 * t].free_symbols == {B[2 * t], t}
    assert B[4].free_symbols == {B[4]}
    assert B[x * t].free_symbols == {B[x * t], x, t}

    #test issue 20078
    assert (2 * B[t] + 3 * B[t]).simplify() == 5 * B[t]
    assert (2 * B[t] - 3 * B[t]).simplify() == -B[t]
    assert (2 * (0.25 * B[t])).simplify() == 0.5 * B[t]
    assert (2 * B[t] * 0.25 * B[t]).simplify() == 0.5 * B[t]**2
    assert (B[t]**2 + B[t]**3).simplify() == (B[t] + 1) * B[t]**2
示例#12
0
def test_ContinuousMarkovChain():
    T1 = Matrix([[S(-2), S(2), S.Zero], [S.Zero, S.NegativeOne, S.One],
                 [Rational(3, 2), Rational(3, 2),
                  S(-3)]])
    C1 = ContinuousMarkovChain('C', [0, 1, 2], T1)
    assert C1.limiting_distribution() == ImmutableMatrix(
        [[Rational(3, 19), Rational(12, 19),
          Rational(4, 19)]])

    T2 = Matrix([[-S.One, S.One, S.Zero], [S.One, -S.One, S.Zero],
                 [S.Zero, S.One, -S.One]])
    C2 = ContinuousMarkovChain('C', [0, 1, 2], T2)
    A, t = C2.generator_matrix, symbols('t', positive=True)
    assert C2.transition_probabilities(A)(t) == Matrix(
        [[S.Half + exp(-2 * t) / 2, S.Half - exp(-2 * t) / 2, 0],
         [S.Half - exp(-2 * t) / 2, S.Half + exp(-2 * t) / 2, 0],
         [
             S.Half - exp(-t) + exp(-2 * t) / 2, S.Half - exp(-2 * t) / 2,
             exp(-t)
         ]])
    with ignore_warnings(
            UserWarning):  ### TODO: Restore tests once warnings are removed
        assert P(Eq(C2(1), 1), Eq(C2(0), 1),
                 evaluate=False) == Probability(Eq(C2(1), 1), Eq(C2(0), 1))
    assert P(Eq(C2(1), 1), Eq(C2(0), 1)) == exp(-2) / 2 + S.Half
    assert P(
        Eq(C2(1), 0) & Eq(C2(2), 1) & Eq(C2(3), 1),
        Eq(P(Eq(C2(1), 0)),
           S.Half)) == (Rational(1, 4) - exp(-2) / 4) * (exp(-2) / 2 + S.Half)
    assert P(
        Not(Eq(C2(1), 0) & Eq(C2(2), 1) & Eq(C2(3), 2)) |
        (Eq(C2(1), 0) & Eq(C2(2), 1) & Eq(C2(3), 2)),
        Eq(P(Eq(C2(1), 0)), Rational(1, 4))
        & Eq(P(Eq(C2(1), 1)), Rational(1, 4))) is S.One
    assert E(C2(Rational(3, 2)),
             Eq(C2(0), 2)) == -exp(-3) / 2 + 2 * exp(Rational(-3, 2)) + S.Half
    assert variance(C2(Rational(3, 2)), Eq(
        C2(0),
        1)) == ((S.Half - exp(-3) / 2)**2 * (exp(-3) / 2 + S.Half) +
                (Rational(-1, 2) - exp(-3) / 2)**2 * (S.Half - exp(-3) / 2))
    raises(KeyError, lambda: P(Eq(C2(1), 0), Eq(P(Eq(C2(1), 1)), S.Half)))
    assert P(Eq(C2(1), 0), Eq(P(Eq(C2(5), 1)),
                              S.Half)) == Probability(Eq(C2(1), 0))
    TS1 = MatrixSymbol('G', 3, 3)
    CS1 = ContinuousMarkovChain('C', [0, 1, 2], TS1)
    A = CS1.generator_matrix
    assert CS1.transition_probabilities(A)(t) == exp(t * A)

    C3 = ContinuousMarkovChain(
        'C', [Symbol('0'), Symbol('1'), Symbol('2')], T2)
    assert P(Eq(C3(1), 1), Eq(C3(0), 1)) == exp(-2) / 2 + S.Half
    assert P(Eq(C3(1), Symbol('1')), Eq(C3(0),
                                        Symbol('1'))) == exp(-2) / 2 + S.Half

    #test probability queries
    G = Matrix([[-S(1), Rational(1, 10),
                 Rational(9, 10)], [Rational(2, 5), -S(1),
                                    Rational(3, 5)],
                [Rational(1, 2), Rational(1, 2), -S(1)]])
    C = ContinuousMarkovChain('C', state_space=[0, 1, 2], gen_mat=G)
    assert P(Eq(C(7.385), C(3.19)), Eq(C(0.862),
                                       0)).round(5) == Float(0.35469, 5)
    assert P(Gt(C(98.715), C(19.807)), Eq(C(11.314),
                                          2)).round(5) == Float(0.32452, 5)
    assert P(Le(C(5.9), C(10.112)), Eq(C(4), 1)).round(6) == Float(0.675214, 6)
    assert Float(P(Eq(C(7.32), C(2.91)), Eq(C(2.63), 1)),
                 14) == Float(1 - P(Ne(C(7.32), C(2.91)), Eq(C(2.63), 1)), 14)
    assert Float(P(Gt(C(3.36), C(1.101)), Eq(C(0.8), 2)),
                 14) == Float(1 - P(Le(C(3.36), C(1.101)), Eq(C(0.8), 2)), 14)
    assert Float(P(Lt(C(4.9), C(2.79)), Eq(C(1.61), 0)),
                 14) == Float(1 - P(Ge(C(4.9), C(2.79)), Eq(C(1.61), 0)), 14)
    assert P(Eq(C(5.243), C(10.912)), Eq(C(2.174),
                                         1)) == P(Eq(C(10.912), C(5.243)),
                                                  Eq(C(2.174), 1))
    assert P(Gt(C(2.344), C(9.9)), Eq(C(1.102),
                                      1)) == P(Lt(C(9.9), C(2.344)),
                                               Eq(C(1.102), 1))
    assert P(Ge(C(7.87), C(1.008)), Eq(C(0.153),
                                       1)) == P(Le(C(1.008), C(7.87)),
                                                Eq(C(0.153), 1))

    #test symbolic queries
    a, b, c, d = symbols('a b c d')
    query = P(Eq(C(a), b), Eq(C(c), d))
    assert query.subs({
        a: 3.65,
        b: 2,
        c: 1.78,
        d: 1
    }).evalf().round(10) == P(Eq(C(3.65), 2), Eq(C(1.78), 1)).round(10)
    query_gt = P(Gt(C(a), b), Eq(C(c), d))
    query_le = P(Le(C(a), b), Eq(C(c), d))
    assert query_gt.subs({
        a: 13.2,
        b: 0,
        c: 3.29,
        d: 2
    }).evalf() + query_le.subs({
        a: 13.2,
        b: 0,
        c: 3.29,
        d: 2
    }).evalf() == 1
    query_ge = P(Ge(C(a), b), Eq(C(c), d))
    query_lt = P(Lt(C(a), b), Eq(C(c), d))
    assert query_ge.subs({
        a: 7.43,
        b: 1,
        c: 1.45,
        d: 0
    }).evalf() + query_lt.subs({
        a: 7.43,
        b: 1,
        c: 1.45,
        d: 0
    }).evalf() == 1

    #test issue 20078
    assert (2 * C(1) + 3 * C(1)).simplify() == 5 * C(1)
    assert (2 * C(1) - 3 * C(1)).simplify() == -C(1)
    assert (2 * (0.25 * C(1))).simplify() == 0.5 * C(1)
    assert (2 * C(1) * 0.25 * C(1)).simplify() == 0.5 * C(1)**2
    assert (C(1)**2 + C(1)**3).simplify() == (C(1) + 1) * C(1)**2
示例#13
0
def test_DiscreteMarkovChain():

    # pass only the name
    X = DiscreteMarkovChain("X")
    assert isinstance(X.state_space, Range)
    assert X.index_set == S.Naturals0
    assert isinstance(X.transition_probabilities, MatrixSymbol)
    t = symbols('t', positive=True, integer=True)
    assert isinstance(X[t], RandomIndexedSymbol)
    assert E(X[0]) == Expectation(X[0])
    raises(TypeError, lambda: DiscreteMarkovChain(1))
    raises(NotImplementedError, lambda: X(t))
    raises(NotImplementedError, lambda: X.communication_classes())
    raises(NotImplementedError, lambda: X.canonical_form())
    raises(NotImplementedError, lambda: X.decompose())

    nz = Symbol('n', integer=True)
    TZ = MatrixSymbol('M', nz, nz)
    SZ = Range(nz)
    YZ = DiscreteMarkovChain('Y', SZ, TZ)
    assert P(Eq(YZ[2], 1), Eq(YZ[1], 0)) == TZ[0, 1]

    raises(ValueError, lambda: sample_stochastic_process(t))
    raises(ValueError, lambda: next(sample_stochastic_process(X)))
    # pass name and state_space
    # any hashable object should be a valid state
    # states should be valid as a tuple/set/list/Tuple/Range
    sym, rainy, cloudy, sunny = symbols('a Rainy Cloudy Sunny', real=True)
    state_spaces = [(1, 2, 3), [Str('Hello'), sym, DiscreteMarkovChain],
                    Tuple(S(1), exp(sym), Str('World'), sympify=False),
                    Range(-1, 5, 2), [rainy, cloudy, sunny]]
    chains = [
        DiscreteMarkovChain("Y", state_space) for state_space in state_spaces
    ]

    for i, Y in enumerate(chains):
        assert isinstance(Y.transition_probabilities, MatrixSymbol)
        assert Y.state_space == state_spaces[i] or Y.state_space == FiniteSet(
            *state_spaces[i])
        assert Y.number_of_states == 3

        with ignore_warnings(
                UserWarning):  # TODO: Restore tests once warnings are removed
            assert P(Eq(Y[2], 1), Eq(Y[0], 2),
                     evaluate=False) == Probability(Eq(Y[2], 1), Eq(Y[0], 2))
        assert E(Y[0]) == Expectation(Y[0])

        raises(ValueError, lambda: next(sample_stochastic_process(Y)))

    raises(TypeError, lambda: DiscreteMarkovChain("Y", dict((1, 1))))
    Y = DiscreteMarkovChain("Y", Range(1, t, 2))
    assert Y.number_of_states == ceiling((t - 1) / 2)

    # pass name and transition_probabilities
    chains = [
        DiscreteMarkovChain("Y", trans_probs=Matrix([[]])),
        DiscreteMarkovChain("Y", trans_probs=Matrix([[0, 1], [1, 0]])),
        DiscreteMarkovChain("Y",
                            trans_probs=Matrix([[pi, 1 - pi], [sym, 1 - sym]]))
    ]
    for Z in chains:
        assert Z.number_of_states == Z.transition_probabilities.shape[0]
        assert isinstance(Z.transition_probabilities, ImmutableMatrix)

    # pass name, state_space and transition_probabilities
    T = Matrix([[0.5, 0.2, 0.3], [0.2, 0.5, 0.3], [0.2, 0.3, 0.5]])
    TS = MatrixSymbol('T', 3, 3)
    Y = DiscreteMarkovChain("Y", [0, 1, 2], T)
    YS = DiscreteMarkovChain("Y", ['One', 'Two', 3], TS)
    assert Y.joint_distribution(1, Y[2],
                                3) == JointDistribution(Y[1], Y[2], Y[3])
    raises(ValueError, lambda: Y.joint_distribution(Y[1].symbol, Y[2].symbol))
    assert P(Eq(Y[3], 2), Eq(Y[1], 1)).round(2) == Float(0.36, 2)
    assert (P(Eq(YS[3], 2), Eq(YS[1], 1)) -
            (TS[0, 2] * TS[1, 0] + TS[1, 1] * TS[1, 2] +
             TS[1, 2] * TS[2, 2])).simplify() == 0
    assert P(Eq(YS[1], 1), Eq(YS[2], 2)) == Probability(Eq(YS[1], 1))
    assert P(Eq(YS[3], 3), Eq(
        YS[1],
        1)) == TS[0, 2] * TS[1, 0] + TS[1, 1] * TS[1, 2] + TS[1, 2] * TS[2, 2]
    TO = Matrix([[0.25, 0.75, 0], [0, 0.25, 0.75], [0.75, 0, 0.25]])
    assert P(Eq(Y[3], 2),
             Eq(Y[1], 1) & TransitionMatrixOf(Y, TO)).round(3) == Float(
                 0.375, 3)
    with ignore_warnings(
            UserWarning):  ### TODO: Restore tests once warnings are removed
        assert E(Y[3], evaluate=False) == Expectation(Y[3])
        assert E(Y[3], Eq(Y[2], 1)).round(2) == Float(1.1, 3)
    TSO = MatrixSymbol('T', 4, 4)
    raises(
        ValueError,
        lambda: str(P(Eq(YS[3], 2),
                      Eq(YS[1], 1) & TransitionMatrixOf(YS, TSO))))
    raises(TypeError,
           lambda: DiscreteMarkovChain("Z", [0, 1, 2], symbols('M')))
    raises(
        ValueError,
        lambda: DiscreteMarkovChain("Z", [0, 1, 2], MatrixSymbol('T', 3, 4)))
    raises(ValueError, lambda: E(Y[3], Eq(Y[2], 6)))
    raises(ValueError, lambda: E(Y[2], Eq(Y[3], 1)))

    # extended tests for probability queries
    TO1 = Matrix([[Rational(1, 4), Rational(3, 4), 0],
                  [Rational(1, 3),
                   Rational(1, 3),
                   Rational(1, 3)], [0, Rational(1, 4),
                                     Rational(3, 4)]])
    assert P(
        And(Eq(Y[2], 1), Eq(Y[1], 1), Eq(Y[0], 0)),
        Eq(Probability(Eq(Y[0], 0)), Rational(1, 4))
        & TransitionMatrixOf(Y, TO1)) == Rational(1, 16)
    assert P(And(Eq(Y[2], 1), Eq(Y[1], 1), Eq(Y[0], 0)), TransitionMatrixOf(Y, TO1)) == \
            Probability(Eq(Y[0], 0))/4
    assert P(
        Lt(X[1], 2) & Gt(X[1], 0),
        Eq(X[0], 2) & StochasticStateSpaceOf(X, [0, 1, 2])
        & TransitionMatrixOf(X, TO1)) == Rational(1, 4)
    assert P(
        Lt(X[1], 2) & Gt(X[1], 0),
        Eq(X[0], 2) & StochasticStateSpaceOf(X, [None, 'None', 1])
        & TransitionMatrixOf(X, TO1)) == Rational(1, 4)
    assert P(
        Ne(X[1], 2) & Ne(X[1], 1),
        Eq(X[0], 2) & StochasticStateSpaceOf(X, [0, 1, 2])
        & TransitionMatrixOf(X, TO1)) is S.Zero
    assert P(
        Ne(X[1], 2) & Ne(X[1], 1),
        Eq(X[0], 2) & StochasticStateSpaceOf(X, [None, 'None', 1])
        & TransitionMatrixOf(X, TO1)) is S.Zero
    assert P(And(Eq(Y[2], 1), Eq(Y[1], 1), Eq(Y[0], 0)),
             Eq(Y[1], 1)) == 0.1 * Probability(Eq(Y[0], 0))

    # testing properties of Markov chain
    TO2 = Matrix([[S.One, 0, 0],
                  [Rational(1, 3),
                   Rational(1, 3),
                   Rational(1, 3)], [0, Rational(1, 4),
                                     Rational(3, 4)]])
    TO3 = Matrix([[Rational(1, 4), Rational(3, 4), 0],
                  [Rational(1, 3),
                   Rational(1, 3),
                   Rational(1, 3)], [0, Rational(1, 4),
                                     Rational(3, 4)]])
    Y2 = DiscreteMarkovChain('Y', trans_probs=TO2)
    Y3 = DiscreteMarkovChain('Y', trans_probs=TO3)
    assert Y3.fundamental_matrix() == ImmutableMatrix(
        [[176, 81, -132], [36, 141, -52], [-44, -39, 208]]) / 125
    assert Y2.is_absorbing_chain() == True
    assert Y3.is_absorbing_chain() == False
    assert Y2.canonical_form() == ([0, 1, 2], TO2)
    assert Y3.canonical_form() == ([0, 1, 2], TO3)
    assert Y2.decompose() == ([0, 1,
                               2], TO2[0:1, 0:1], TO2[1:3, 0:1], TO2[1:3, 1:3])
    assert Y3.decompose() == ([0, 1, 2], TO3, Matrix(0, 3,
                                                     []), Matrix(0, 0, []))
    TO4 = Matrix([[Rational(1, 5),
                   Rational(2, 5),
                   Rational(2, 5)], [Rational(1, 10), S.Half,
                                     Rational(2, 5)],
                  [Rational(3, 5),
                   Rational(3, 10),
                   Rational(1, 10)]])
    Y4 = DiscreteMarkovChain('Y', trans_probs=TO4)
    w = ImmutableMatrix([[Rational(11, 39),
                          Rational(16, 39),
                          Rational(4, 13)]])
    assert Y4.limiting_distribution == w
    assert Y4.is_regular() == True
    assert Y4.is_ergodic() == True
    TS1 = MatrixSymbol('T', 3, 3)
    Y5 = DiscreteMarkovChain('Y', trans_probs=TS1)
    assert Y5.limiting_distribution(w, TO4).doit() == True
    assert Y5.stationary_distribution(condition_set=True).subs(
        TS1, TO4).contains(w).doit() == S.true
    TO6 = Matrix([[S.One, 0, 0, 0, 0], [S.Half, 0, S.Half, 0, 0],
                  [0, S.Half, 0, S.Half, 0], [0, 0, S.Half, 0, S.Half],
                  [0, 0, 0, 0, 1]])
    Y6 = DiscreteMarkovChain('Y', trans_probs=TO6)
    assert Y6.fundamental_matrix() == ImmutableMatrix(
        [[Rational(3, 2), S.One, S.Half], [S.One, S(2), S.One],
         [S.Half, S.One, Rational(3, 2)]])
    assert Y6.absorbing_probabilities() == ImmutableMatrix(
        [[Rational(3, 4), Rational(1, 4)], [S.Half, S.Half],
         [Rational(1, 4), Rational(3, 4)]])
    TO7 = Matrix([[Rational(1, 2),
                   Rational(1, 4),
                   Rational(1, 4)], [Rational(1, 2), 0,
                                     Rational(1, 2)],
                  [Rational(1, 4),
                   Rational(1, 4),
                   Rational(1, 2)]])
    Y7 = DiscreteMarkovChain('Y', trans_probs=TO7)
    assert Y7.is_absorbing_chain() == False
    assert Y7.fundamental_matrix() == ImmutableMatrix(
        [[Rational(86, 75),
          Rational(1, 25),
          Rational(-14, 75)],
         [Rational(2, 25), Rational(21, 25),
          Rational(2, 25)],
         [Rational(-14, 75),
          Rational(1, 25),
          Rational(86, 75)]])

    # test for zero-sized matrix functionality
    X = DiscreteMarkovChain('X', trans_probs=Matrix([[]]))
    assert X.number_of_states == 0
    assert X.stationary_distribution() == Matrix([[]])
    assert X.communication_classes() == []
    assert X.canonical_form() == ([], Matrix([[]]))
    assert X.decompose() == ([], Matrix([[]]), Matrix([[]]), Matrix([[]]))
    assert X.is_regular() == False
    assert X.is_ergodic() == False

    # test communication_class
    # see https://drive.google.com/drive/folders/1HbxLlwwn2b3U8Lj7eb_ASIUb5vYaNIjg?usp=sharing
    # tutorial 2.pdf
    TO7 = Matrix([[0, 5, 5, 0, 0], [0, 0, 0, 10, 0], [5, 0, 5, 0, 0],
                  [0, 10, 0, 0, 0], [0, 3, 0, 3, 4]]) / 10
    Y7 = DiscreteMarkovChain('Y', trans_probs=TO7)
    tuples = Y7.communication_classes()
    classes, recurrence, periods = list(zip(*tuples))
    assert classes == ([1, 3], [0, 2], [4])
    assert recurrence == (True, False, False)
    assert periods == (2, 1, 1)

    TO8 = Matrix([[0, 0, 0, 10, 0, 0], [5, 0, 5, 0, 0, 0], [0, 4, 0, 0, 0, 6],
                  [10, 0, 0, 0, 0, 0], [0, 10, 0, 0, 0, 0], [0, 0, 0, 5, 5, 0]
                  ]) / 10
    Y8 = DiscreteMarkovChain('Y', trans_probs=TO8)
    tuples = Y8.communication_classes()
    classes, recurrence, periods = list(zip(*tuples))
    assert classes == ([0, 3], [1, 2, 5, 4])
    assert recurrence == (True, False)
    assert periods == (2, 2)

    TO9 = Matrix(
        [[2, 0, 0, 3, 0, 0, 3, 2, 0, 0], [0, 10, 0, 0, 0, 0, 0, 0, 0, 0],
         [0, 2, 2, 0, 0, 0, 0, 0, 3, 3], [0, 0, 0, 3, 0, 0, 6, 1, 0, 0],
         [0, 0, 0, 0, 5, 5, 0, 0, 0, 0], [0, 0, 0, 0, 0, 10, 0, 0, 0, 0],
         [4, 0, 0, 5, 0, 0, 1, 0, 0, 0], [2, 0, 0, 4, 0, 0, 2, 2, 0, 0],
         [3, 0, 1, 0, 0, 0, 0, 0, 4, 2], [0, 0, 4, 0, 0, 0, 0, 0, 3, 3]]) / 10
    Y9 = DiscreteMarkovChain('Y', trans_probs=TO9)
    tuples = Y9.communication_classes()
    classes, recurrence, periods = list(zip(*tuples))
    assert classes == ([0, 3, 6, 7], [1], [2, 8, 9], [5], [4])
    assert recurrence == (True, True, False, True, False)
    assert periods == (1, 1, 1, 1, 1)

    # test canonical form
    # see https://www.dartmouth.edu/~chance/teaching_aids/books_articles/probability_book/Chapter11.pdf
    # example 11.13
    T = Matrix([[1, 0, 0, 0, 0], [S(1) / 2, 0, S(1) / 2, 0, 0],
                [0, S(1) / 2, 0, S(1) / 2, 0], [0, 0,
                                                S(1) / 2, 0,
                                                S(1) / 2], [0, 0, 0, 0,
                                                            S(1)]])
    DW = DiscreteMarkovChain('DW', [0, 1, 2, 3, 4], T)
    states, A, B, C = DW.decompose()
    assert states == [0, 4, 1, 2, 3]
    assert A == Matrix([[1, 0], [0, 1]])
    assert B == Matrix([[S(1) / 2, 0], [0, 0], [0, S(1) / 2]])
    assert C == Matrix([[0, S(1) / 2, 0], [S(1) / 2, 0, S(1) / 2],
                        [0, S(1) / 2, 0]])
    states, new_matrix = DW.canonical_form()
    assert states == [0, 4, 1, 2, 3]
    assert new_matrix == Matrix([[1, 0, 0, 0, 0], [0, 1, 0, 0, 0],
                                 [S(1) / 2, 0, 0, S(1) / 2, 0],
                                 [0, 0, S(1) / 2, 0,
                                  S(1) / 2], [0, S(1) / 2, 0,
                                              S(1) / 2, 0]])

    # test regular and ergodic
    # https://www.dartmouth.edu/~chance/teaching_aids/books_articles/probability_book/Chapter11.pdf
    T = Matrix([[0, 4, 0, 0, 0], [1, 0, 3, 0, 0], [0, 2, 0, 2, 0],
                [0, 0, 3, 0, 1], [0, 0, 0, 4, 0]]) / 4
    X = DiscreteMarkovChain('X', trans_probs=T)
    assert not X.is_regular()
    assert X.is_ergodic()
    T = Matrix([[0, 1], [1, 0]])
    X = DiscreteMarkovChain('X', trans_probs=T)
    assert not X.is_regular()
    assert X.is_ergodic()
    # http://www.math.wisc.edu/~valko/courses/331/MC2.pdf
    T = Matrix([[2, 1, 1], [2, 0, 2], [1, 1, 2]]) / 4
    X = DiscreteMarkovChain('X', trans_probs=T)
    assert X.is_regular()
    assert X.is_ergodic()
    # https://docs.ufpr.br/~lucambio/CE222/1S2014/Kemeny-Snell1976.pdf
    T = Matrix([[1, 1], [1, 1]]) / 2
    X = DiscreteMarkovChain('X', trans_probs=T)
    assert X.is_regular()
    assert X.is_ergodic()

    # test is_absorbing_chain
    T = Matrix([[0, 1, 0], [1, 0, 0], [0, 0, 1]])
    X = DiscreteMarkovChain('X', trans_probs=T)
    assert not X.is_absorbing_chain()
    # https://en.wikipedia.org/wiki/Absorbing_Markov_chain
    T = Matrix([[1, 1, 0, 0], [0, 1, 1, 0], [1, 0, 0, 1], [0, 0, 0, 2]]) / 2
    X = DiscreteMarkovChain('X', trans_probs=T)
    assert X.is_absorbing_chain()
    T = Matrix([[2, 0, 0, 0, 0], [1, 0, 1, 0, 0], [0, 1, 0, 1, 0],
                [0, 0, 1, 0, 1], [0, 0, 0, 0, 2]]) / 2
    X = DiscreteMarkovChain('X', trans_probs=T)
    assert X.is_absorbing_chain()

    # test custom state space
    Y10 = DiscreteMarkovChain('Y', [1, 2, 3], TO2)
    tuples = Y10.communication_classes()
    classes, recurrence, periods = list(zip(*tuples))
    assert classes == ([1], [2, 3])
    assert recurrence == (True, False)
    assert periods == (1, 1)
    assert Y10.canonical_form() == ([1, 2, 3], TO2)
    assert Y10.decompose() == ([1, 2, 3], TO2[0:1, 0:1], TO2[1:3,
                                                             0:1], TO2[1:3,
                                                                       1:3])

    # testing miscellaneous queries
    T = Matrix([[S.Half, Rational(1, 4),
                 Rational(1, 4)], [Rational(1, 3), 0,
                                   Rational(2, 3)], [S.Half, S.Half, 0]])
    X = DiscreteMarkovChain('X', [0, 1, 2], T)
    assert P(
        Eq(X[1], 2) & Eq(X[2], 1) & Eq(X[3], 0),
        Eq(P(Eq(X[1], 0)), Rational(1, 4))
        & Eq(P(Eq(X[1], 1)), Rational(1, 4))) == Rational(1, 12)
    assert P(Eq(X[2], 1) | Eq(X[2], 2), Eq(X[1], 1)) == Rational(2, 3)
    assert P(Eq(X[2], 1) & Eq(X[2], 2), Eq(X[1], 1)) is S.Zero
    assert P(Ne(X[2], 2), Eq(X[1], 1)) == Rational(1, 3)
    assert E(X[1]**2, Eq(X[0], 1)) == Rational(8, 3)
    assert variance(X[1], Eq(X[0], 1)) == Rational(8, 9)
    raises(ValueError, lambda: E(X[1], Eq(X[2], 1)))
    raises(ValueError, lambda: DiscreteMarkovChain('X', [0, 1], T))

    # testing miscellaneous queries with different state space
    X = DiscreteMarkovChain('X', ['A', 'B', 'C'], T)
    assert P(
        Eq(X[1], 2) & Eq(X[2], 1) & Eq(X[3], 0),
        Eq(P(Eq(X[1], 0)), Rational(1, 4))
        & Eq(P(Eq(X[1], 1)), Rational(1, 4))) == Rational(1, 12)
    assert P(Eq(X[2], 1) | Eq(X[2], 2), Eq(X[1], 1)) == Rational(2, 3)
    assert P(Eq(X[2], 1) & Eq(X[2], 2), Eq(X[1], 1)) is S.Zero
    assert P(Ne(X[2], 2), Eq(X[1], 1)) == Rational(1, 3)
    a = X.state_space.args[0]
    c = X.state_space.args[2]
    assert (E(X[1]**2, Eq(X[0], 1)) -
            (a**2 / 3 + 2 * c**2 / 3)).simplify() == 0
    assert (variance(X[1], Eq(X[0], 1)) -
            (2 * (-a / 3 + c / 3)**2 / 3 +
             (2 * a / 3 - 2 * c / 3)**2 / 3)).simplify() == 0
    raises(ValueError, lambda: E(X[1], Eq(X[2], 1)))

    #testing queries with multiple RandomIndexedSymbols
    T = Matrix([[Rational(5, 10),
                 Rational(3, 10),
                 Rational(2, 10)],
                [Rational(2, 10),
                 Rational(7, 10),
                 Rational(1, 10)],
                [Rational(3, 10),
                 Rational(3, 10),
                 Rational(4, 10)]])
    Y = DiscreteMarkovChain("Y", [0, 1, 2], T)
    assert P(Eq(Y[7], Y[5]), Eq(Y[2], 0)).round(5) == Float(0.44428, 5)
    assert P(Gt(Y[3], Y[1]), Eq(Y[0], 0)).round(2) == Float(0.36, 2)
    assert P(Le(Y[5], Y[10]), Eq(Y[4], 2)).round(6) == Float(0.583120, 6)
    assert Float(P(Eq(Y[10], Y[5]), Eq(Y[4], 1)),
                 14) == Float(1 - P(Ne(Y[10], Y[5]), Eq(Y[4], 1)), 14)
    assert Float(P(Gt(Y[8], Y[9]), Eq(Y[3], 2)),
                 14) == Float(1 - P(Le(Y[8], Y[9]), Eq(Y[3], 2)), 14)
    assert Float(P(Lt(Y[1], Y[4]), Eq(Y[0], 0)),
                 14) == Float(1 - P(Ge(Y[1], Y[4]), Eq(Y[0], 0)), 14)
    assert P(Eq(Y[5], Y[10]), Eq(Y[2], 1)) == P(Eq(Y[10], Y[5]), Eq(Y[2], 1))
    assert P(Gt(Y[1], Y[2]), Eq(Y[0], 1)) == P(Lt(Y[2], Y[1]), Eq(Y[0], 1))
    assert P(Ge(Y[7], Y[6]), Eq(Y[4], 1)) == P(Le(Y[6], Y[7]), Eq(Y[4], 1))

    #test symbolic queries
    a, b, c, d = symbols('a b c d')
    T = Matrix([[Rational(1, 10),
                 Rational(4, 10),
                 Rational(5, 10)],
                [Rational(3, 10),
                 Rational(4, 10),
                 Rational(3, 10)],
                [Rational(7, 10),
                 Rational(2, 10),
                 Rational(1, 10)]])
    Y = DiscreteMarkovChain("Y", [0, 1, 2], T)
    query = P(Eq(Y[a], b), Eq(Y[c], d))
    assert query.subs({
        a: 10,
        b: 2,
        c: 5,
        d: 1
    }).evalf().round(4) == P(Eq(Y[10], 2), Eq(Y[5], 1)).round(4)
    assert query.subs({
        a: 15,
        b: 0,
        c: 10,
        d: 1
    }).evalf().round(4) == P(Eq(Y[15], 0), Eq(Y[10], 1)).round(4)
    query_gt = P(Gt(Y[a], b), Eq(Y[c], d))
    query_le = P(Le(Y[a], b), Eq(Y[c], d))
    assert query_gt.subs({
        a: 5,
        b: 2,
        c: 1,
        d: 0
    }).evalf() + query_le.subs({
        a: 5,
        b: 2,
        c: 1,
        d: 0
    }).evalf() == 1
    query_ge = P(Ge(Y[a], b), Eq(Y[c], d))
    query_lt = P(Lt(Y[a], b), Eq(Y[c], d))
    assert query_ge.subs({
        a: 4,
        b: 1,
        c: 0,
        d: 2
    }).evalf() + query_lt.subs({
        a: 4,
        b: 1,
        c: 0,
        d: 2
    }).evalf() == 1

    #test issue 20078
    assert (2 * Y[1] + 3 * Y[1]).simplify() == 5 * Y[1]
    assert (2 * Y[1] - 3 * Y[1]).simplify() == -Y[1]
    assert (2 * (0.25 * Y[1])).simplify() == 0.5 * Y[1]
    assert ((2 * Y[1]) * (0.25 * Y[1])).simplify() == 0.5 * Y[1]**2
    assert (Y[1]**2 + Y[1]**3).simplify() == (Y[1] + 1) * Y[1]**2
示例#14
0
def test_dice():
    # TODO: Make iid method!
    X, Y, Z = Die('X', 6), Die('Y', 6), Die('Z', 6)
    a, b, t, p = symbols('a b t p')

    assert E(X) == 3 + S.Half
    assert variance(X) == S(35) / 12
    assert E(X + Y) == 7
    assert E(X + X) == 7
    assert E(a * X + b) == a * E(X) + b
    assert variance(X + Y) == variance(X) + variance(Y) == cmoment(X + Y, 2)
    assert variance(X + X) == 4 * variance(X) == cmoment(X + X, 2)
    assert cmoment(X, 0) == 1
    assert cmoment(4 * X, 3) == 64 * cmoment(X, 3)
    assert covariance(X, Y) == S.Zero
    assert covariance(X, X + Y) == variance(X)
    assert density(Eq(cos(X * S.Pi), 1))[True] == S.Half
    assert correlation(X, Y) == 0
    assert correlation(X, Y) == correlation(Y, X)
    assert smoment(X + Y, 3) == skewness(X + Y)
    assert smoment(X + Y, 4) == kurtosis(X + Y)
    assert smoment(X, 0) == 1
    assert P(X > 3) == S.Half
    assert P(2 * X > 6) == S.Half
    assert P(X > Y) == S(5) / 12
    assert P(Eq(X, Y)) == P(Eq(X, 1))

    assert E(X, X > 3) == 5 == moment(X, 1, 0, X > 3)
    assert E(X, Y > 3) == E(X) == moment(X, 1, 0, Y > 3)
    assert E(X + Y, Eq(X, Y)) == E(2 * X)
    assert moment(X, 0) == 1
    assert moment(5 * X, 2) == 25 * moment(X, 2)
    assert quantile(X)(p) == Piecewise((nan, (p > S.One) | (p < S(0))),\
        (S.One, p <= S(1)/6), (S(2), p <= S(1)/3), (S(3), p <= S.Half),\
        (S(4), p <= S(2)/3), (S(5), p <= S(5)/6), (S(6), p <= S.One))

    assert P(X > 3, X > 3) == S.One
    assert P(X > Y, Eq(Y, 6)) == S.Zero
    assert P(Eq(X + Y, 12)) == S.One / 36
    assert P(Eq(X + Y, 12), Eq(X, 6)) == S.One / 6

    assert density(X + Y) == density(Y + Z) != density(X + X)
    d = density(2 * X + Y**Z)
    assert d[S(22)] == S.One / 108 and d[S(4100)] == S.One / 216 and S(
        3130) not in d

    assert pspace(X).domain.as_boolean() == Or(
        *[Eq(X.symbol, i) for i in [1, 2, 3, 4, 5, 6]])

    assert where(X > 3).set == FiniteSet(4, 5, 6)

    assert characteristic_function(X)(t) == exp(6 * I * t) / 6 + exp(
        5 * I * t) / 6 + exp(4 * I * t) / 6 + exp(3 * I * t) / 6 + exp(
            2 * I * t) / 6 + exp(I * t) / 6
    assert moment_generating_function(X)(
        t) == exp(6 * t) / 6 + exp(5 * t) / 6 + exp(4 * t) / 6 + exp(
            3 * t) / 6 + exp(2 * t) / 6 + exp(t) / 6

    # Bayes test for die
    BayesTest(X > 3, X + Y < 5)
    BayesTest(Eq(X - Y, Z), Z > Y)
    BayesTest(X > 3, X > 2)

    # arg test for die
    raises(ValueError, lambda: Die('X', -1))  # issue 8105: negative sides.
    raises(ValueError, lambda: Die('X', 0))
    raises(ValueError, lambda: Die('X', 1.5))  # issue 8103: non integer sides.

    # symbolic test for die
    n, k = symbols('n, k', positive=True)
    D = Die('D', n)
    dens = density(D).dict
    assert dens == Density(DieDistribution(n))
    assert set(dens.subs(n, 4).doit().keys()) == set([1, 2, 3, 4])
    assert set(dens.subs(n, 4).doit().values()) == set([S(1) / 4])
    k = Dummy('k', integer=True)
    assert E(D).dummy_eq(Sum(Piecewise((k / n, k <= n), (0, True)), (k, 1, n)))
    assert variance(D).subs(n, 6).doit() == S(35) / 12

    ki = Dummy('ki')
    cumuf = cdf(D)(k)
    assert cumuf.dummy_eq(
        Sum(Piecewise((1 / n, (ki >= 1) & (ki <= n)), (0, True)), (ki, 1, k)))
    assert cumuf.subs({n: 6, k: 2}).doit() == S(1) / 3

    t = Dummy('t')
    cf = characteristic_function(D)(t)
    assert cf.dummy_eq(
        Sum(Piecewise((exp(ki * I * t) / n, (ki >= 1) & (ki <= n)), (0, True)),
            (ki, 1, n)))
    assert cf.subs(
        n,
        3).doit() == exp(3 * I * t) / 3 + exp(2 * I * t) / 3 + exp(I * t) / 3
    mgf = moment_generating_function(D)(t)
    assert mgf.dummy_eq(
        Sum(Piecewise((exp(ki * t) / n, (ki >= 1) & (ki <= n)), (0, True)),
            (ki, 1, n)))
    assert mgf.subs(n,
                    3).doit() == exp(3 * t) / 3 + exp(2 * t) / 3 + exp(t) / 3
示例#15
0
def test_yule_simon():
    rho = S(3)
    x = YuleSimon('x', rho)
    assert simplify(E(x)) == rho / (rho - 1)
    assert simplify(variance(x)) == rho**2 / ((rho - 1)**2 * (rho - 2))
    assert isinstance(E(x, evaluate=False), Sum)
示例#16
0
def test_wignersemicircle():
    R = Symbol("R", positive=True)

    X = WignerSemicircle('x', R)
    assert density(X)(x) == 2*sqrt(-x**2 + R**2)/(pi*R**2)
    assert E(X) == 0
示例#17
0
def test_expectation():
    from sympy import simplify
    from sympy.stats import E
    m = Normal('A', [x, y], [[1, 0], [0, 1]])
    assert simplify(E(m[1])) == y
示例#18
0
def test_dice():
    # TODO: Make iid method!
    X, Y, Z = Die('X', 6), Die('Y', 6), Die('Z', 6)
    a, b = symbols('a b')

    assert E(X) == 3 + S.Half
    assert variance(X) == S(35) / 12
    assert E(X + Y) == 7
    assert E(X + X) == 7
    assert E(a * X + b) == a * E(X) + b
    assert variance(X + Y) == variance(X) + variance(Y)
    assert variance(X + X) == 4 * variance(X)
    assert covariance(X, Y) == S.Zero
    assert covariance(X, X + Y) == variance(X)
    assert density(Eq(cos(X * S.Pi), 1))[True] == S.Half

    assert P(X > 3) == S.Half
    assert P(2 * X > 6) == S.Half
    assert P(X > Y) == S(5) / 12
    assert P(Eq(X, Y)) == P(Eq(X, 1))

    assert E(X, X > 3) == 5
    assert E(X, Y > 3) == E(X)
    assert E(X + Y, Eq(X, Y)) == E(2 * X)
    assert E(X + Y - Z, 2 * X > Y + 1) == S(49) / 12

    assert P(X > 3, X > 3) == S.One
    assert P(X > Y, Eq(Y, 6)) == S.Zero
    assert P(Eq(X + Y, 12)) == S.One / 36
    assert P(Eq(X + Y, 12), Eq(X, 6)) == S.One / 6

    assert density(X + Y) == density(Y + Z) != density(X + X)
    d = density(2 * X + Y**Z)
    assert d[S(22)] == S.One / 108 and d[S(4100)] == S.One / 216 and S(
        3130) not in d

    assert pspace(X).domain.as_boolean() == Or(
        *[Eq(X.symbol, i) for i in [1, 2, 3, 4, 5, 6]])

    assert where(X > 3).set == FiniteSet(4, 5, 6)
示例#19
0
def test_E():
    assert E(5) == 5
示例#20
0
def test_DiscreteMarkovChain():

    # pass only the name
    X = DiscreteMarkovChain("X")
    assert X.state_space == S.Reals
    assert X.index_set == S.Naturals0
    assert X.transition_probabilities == None
    t = symbols("t", positive=True, integer=True)
    assert isinstance(X[t], RandomIndexedSymbol)
    assert E(X[0]) == Expectation(X[0])
    raises(TypeError, lambda: DiscreteMarkovChain(1))
    raises(NotImplementedError, lambda: X(t))

    # pass name and state_space
    Y = DiscreteMarkovChain("Y", [1, 2, 3])
    assert Y.transition_probabilities == None
    assert Y.state_space == FiniteSet(1, 2, 3)
    assert P(Eq(Y[2], 1), Eq(Y[0], 2)) == Probability(Eq(Y[2], 1), Eq(Y[0], 2))
    assert E(X[0]) == Expectation(X[0])
    raises(TypeError, lambda: DiscreteMarkovChain("Y", dict((1, 1))))

    # pass name, state_space and transition_probabilities
    T = Matrix([[0.5, 0.2, 0.3], [0.2, 0.5, 0.3], [0.2, 0.3, 0.5]])
    TS = MatrixSymbol("T", 3, 3)
    Y = DiscreteMarkovChain("Y", [0, 1, 2], T)
    YS = DiscreteMarkovChain("Y", [0, 1, 2], TS)
    assert YS._transient2transient() == None
    assert YS._transient2absorbing() == None
    assert Y.joint_distribution(1, Y[2],
                                3) == JointDistribution(Y[1], Y[2], Y[3])
    raises(ValueError, lambda: Y.joint_distribution(Y[1].symbol, Y[2].symbol))
    assert P(Eq(Y[3], 2), Eq(Y[1], 1)).round(2) == Float(0.36, 2)
    assert (str(P(Eq(YS[3], 2), Eq(
        YS[1], 1))) == "T[0, 2]*T[1, 0] + T[1, 1]*T[1, 2] + T[1, 2]*T[2, 2]")
    assert P(Eq(YS[1], 1), Eq(YS[2], 2)) == Probability(Eq(YS[1], 1))
    assert P(Eq(YS[3], 3), Eq(YS[1], 1)) is S.Zero
    TO = Matrix([[0.25, 0.75, 0], [0, 0.25, 0.75], [0.75, 0, 0.25]])
    assert P(Eq(Y[3], 2),
             Eq(Y[1], 1) & TransitionMatrixOf(Y, TO)).round(3) == Float(
                 0.375, 3)
    assert E(Y[3], evaluate=False) == Expectation(Y[3])
    assert E(Y[3], Eq(Y[2], 1)).round(2) == Float(1.1, 3)
    TSO = MatrixSymbol("T", 4, 4)
    raises(
        ValueError,
        lambda: str(P(Eq(YS[3], 2),
                      Eq(YS[1], 1) & TransitionMatrixOf(YS, TSO))),
    )
    raises(TypeError,
           lambda: DiscreteMarkovChain("Z", [0, 1, 2], symbols("M")))
    raises(
        ValueError,
        lambda: DiscreteMarkovChain("Z", [0, 1, 2], MatrixSymbol("T", 3, 4)))
    raises(ValueError, lambda: E(Y[3], Eq(Y[2], 6)))
    raises(ValueError, lambda: E(Y[2], Eq(Y[3], 1)))

    # extended tests for probability queries
    TO1 = Matrix([
        [Rational(1, 4), Rational(3, 4), 0],
        [Rational(1, 3), Rational(1, 3),
         Rational(1, 3)],
        [0, Rational(1, 4), Rational(3, 4)],
    ])
    assert P(
        And(Eq(Y[2], 1), Eq(Y[1], 1), Eq(Y[0], 0)),
        Eq(Probability(Eq(Y[0], 0)), Rational(1, 4))
        & TransitionMatrixOf(Y, TO1),
    ) == Rational(1, 16)
    assert (P(And(Eq(Y[2], 1), Eq(Y[1], 1), Eq(Y[0], 0)),
              TransitionMatrixOf(Y, TO1)) == Probability(Eq(Y[0], 0)) / 4)
    assert P(
        Lt(X[1], 2) & Gt(X[1], 0),
        Eq(X[0], 2) & StochasticStateSpaceOf(X, [0, 1, 2])
        & TransitionMatrixOf(X, TO1),
    ) == Rational(1, 4)
    assert (P(
        Ne(X[1], 2) & Ne(X[1], 1),
        Eq(X[0], 2)
        & StochasticStateSpaceOf(X, [0, 1, 2])
        & TransitionMatrixOf(X, TO1),
    ) is S.Zero)
    assert P(And(Eq(Y[2], 1), Eq(Y[1], 1), Eq(Y[0], 0)),
             Eq(Y[1], 1)) == 0.1 * Probability(Eq(Y[0], 0))

    # testing properties of Markov chain
    TO2 = Matrix([
        [S.One, 0, 0],
        [Rational(1, 3), Rational(1, 3),
         Rational(1, 3)],
        [0, Rational(1, 4), Rational(3, 4)],
    ])
    TO3 = Matrix([
        [Rational(1, 4), Rational(3, 4), 0],
        [Rational(1, 3), Rational(1, 3),
         Rational(1, 3)],
        [0, Rational(1, 4), Rational(3, 4)],
    ])
    Y2 = DiscreteMarkovChain("Y", trans_probs=TO2)
    Y3 = DiscreteMarkovChain("Y", trans_probs=TO3)
    assert Y3._transient2absorbing() == None
    raises(ValueError, lambda: Y3.fundamental_matrix())
    assert Y2.is_absorbing_chain() == True
    assert Y3.is_absorbing_chain() == False
    TO4 = Matrix([
        [Rational(1, 5), Rational(2, 5),
         Rational(2, 5)],
        [Rational(1, 10), S.Half, Rational(2, 5)],
        [Rational(3, 5), Rational(3, 10),
         Rational(1, 10)],
    ])
    Y4 = DiscreteMarkovChain("Y", trans_probs=TO4)
    w = ImmutableMatrix([[Rational(11, 39),
                          Rational(16, 39),
                          Rational(4, 13)]])
    assert Y4.limiting_distribution == w
    assert Y4.is_regular() == True
    TS1 = MatrixSymbol("T", 3, 3)
    Y5 = DiscreteMarkovChain("Y", trans_probs=TS1)
    assert Y5.limiting_distribution(w, TO4).doit() == True
    TO6 = Matrix([
        [S.One, 0, 0, 0, 0],
        [S.Half, 0, S.Half, 0, 0],
        [0, S.Half, 0, S.Half, 0],
        [0, 0, S.Half, 0, S.Half],
        [0, 0, 0, 0, 1],
    ])
    Y6 = DiscreteMarkovChain("Y", trans_probs=TO6)
    assert Y6._transient2absorbing() == ImmutableMatrix([[S.Half, 0], [0, 0],
                                                         [0, S.Half]])
    assert Y6._transient2transient() == ImmutableMatrix([[0, S.Half, 0],
                                                         [S.Half, 0, S.Half],
                                                         [0, S.Half, 0]])
    assert Y6.fundamental_matrix() == ImmutableMatrix([
        [Rational(3, 2), S.One, S.Half],
        [S.One, S(2), S.One],
        [S.Half, S.One, Rational(3, 2)],
    ])
    assert Y6.absorbing_probabilites() == ImmutableMatrix([
        [Rational(3, 4), Rational(1, 4)],
        [S.Half, S.Half],
        [Rational(1, 4), Rational(3, 4)],
    ])

    # testing miscellaneous queries
    T = Matrix([
        [S.Half, Rational(1, 4), Rational(1, 4)],
        [Rational(1, 3), 0, Rational(2, 3)],
        [S.Half, S.Half, 0],
    ])
    X = DiscreteMarkovChain("X", [0, 1, 2], T)
    assert P(
        Eq(X[1], 2) & Eq(X[2], 1) & Eq(X[3], 0),
        Eq(P(Eq(X[1], 0)), Rational(1, 4))
        & Eq(P(Eq(X[1], 1)), Rational(1, 4)),
    ) == Rational(1, 12)
    assert P(Eq(X[2], 1) | Eq(X[2], 2), Eq(X[1], 1)) == Rational(2, 3)
    assert P(Eq(X[2], 1) & Eq(X[2], 2), Eq(X[1], 1)) is S.Zero
    assert P(Ne(X[2], 2), Eq(X[1], 1)) == Rational(1, 3)
    assert E(X[1]**2, Eq(X[0], 1)) == Rational(8, 3)
    assert variance(X[1], Eq(X[0], 1)) == Rational(8, 9)
    raises(ValueError, lambda: E(X[1], Eq(X[2], 1)))
示例#21
0
def test_BernoulliProcess():

    B = BernoulliProcess("B", p=0.6, success=1, failure=0)
    assert B.state_space == FiniteSet(0, 1)
    assert B.index_set == S.Naturals0
    assert B.success == 1
    assert B.failure == 0

    X = BernoulliProcess("X", p=Rational(1, 3), success="H", failure="T")
    assert X.state_space == FiniteSet("H", "T")
    H, T = symbols("H,T")
    assert (E(X[1] + X[2] * X[3]) == H**2 / 9 + 4 * H * T / 9 + H / 3 +
            4 * T**2 / 9 + 2 * T / 3)

    t = symbols("t", positive=True, integer=True)
    assert isinstance(B[t], RandomIndexedSymbol)

    raises(ValueError,
           lambda: BernoulliProcess("X", p=1.1, success=1, failure=0))
    raises(NotImplementedError, lambda: B(t))

    raises(IndexError, lambda: B[-3])
    assert B.joint_distribution(B[3], B[9]) == JointDistributionHandmade(
        Lambda(
            (B[3], B[9]),
            Piecewise((0.6, Eq(B[3], 1)), (0.4, Eq(B[3], 0)),
                      (0, True)) * Piecewise((0.6, Eq(B[9], 1)),
                                             (0.4, Eq(B[9], 0)), (0, True)),
        ))

    assert B.joint_distribution(2, B[4]) == JointDistributionHandmade(
        Lambda(
            (B[2], B[4]),
            Piecewise((0.6, Eq(B[2], 1)), (0.4, Eq(B[2], 0)),
                      (0, True)) * Piecewise((0.6, Eq(B[4], 1)),
                                             (0.4, Eq(B[4], 0)), (0, True)),
        ))

    # Test for the sum distribution of Bernoulli Process RVs
    Y = B[1] + B[2] + B[3]
    assert P(Eq(Y, 0)).round(2) == Float(0.06, 1)
    assert P(Eq(Y, 2)).round(2) == Float(0.43, 2)
    assert P(Eq(Y, 4)).round(2) == 0
    assert P(Gt(Y, 1)).round(2) == Float(0.65, 2)
    # Test for independency of each Random Indexed variable
    assert P(Eq(B[1], 0) & Eq(B[2], 1) & Eq(B[3], 0)
             & Eq(B[4], 1)).round(2) == Float(0.06, 1)

    assert E(2 * B[1] + B[2]).round(2) == Float(1.80, 3)
    assert E(2 * B[1] + B[2] + 5).round(2) == Float(6.80, 3)
    assert E(B[2] * B[4] + B[10]).round(2) == Float(0.96, 2)
    assert E(B[2] > 0, Eq(B[1], 1) & Eq(B[2], 1)).round(2) == Float(0.60, 2)
    assert E(B[1]) == 0.6
    assert P(B[1] > 0).round(2) == Float(0.60, 2)
    assert P(B[1] < 1).round(2) == Float(0.40, 2)
    assert P(B[1] > 0, B[2] <= 1).round(2) == Float(0.60, 2)
    assert P(B[12] * B[5] > 0).round(2) == Float(0.36, 2)
    assert P(B[12] * B[5] > 0, B[4] < 1).round(2) == Float(0.36, 2)
    assert P(Eq(B[2], 1), B[2] > 0) == 1
    assert P(Eq(B[5], 3)) == 0
    assert P(Eq(B[1], 1), B[1] < 0) == 0
    assert P(B[2] > 0, Eq(B[2], 1)) == 1
    assert P(B[2] < 0, Eq(B[2], 1)) == 0
    assert P(B[2] > 0, B[2] == 7) == 0
    assert P(B[5] > 0, B[5]) == BernoulliDistribution(0.6, 0, 1)
    raises(ValueError, lambda: P(3))
    raises(ValueError, lambda: P(B[3] > 0, 3))
示例#22
0
 def expectation(self, n=1):
     X = BetaBn('X', n, self.a, self.b)
     return E(X).evalf()
示例#23
0
def test_issue_11934():
    density = {0: .5, 1: .5}
    X = FiniteRV('X', density)
    assert E(X) == 0.5
    assert P( X>= 2) == 0
示例#24
0
def test_issue_13324():
    X = Uniform('X', 0, 1)
    assert E(X, X > S.Half) == Rational(3, 4)
    assert E(X, X > 0) == S.Half
示例#25
0
def test_weibull():
    a, b = symbols('a b', positive=True)
    X = Weibull('x', a, b)

    assert simplify(E(X)) == simplify(a * gamma(1 + 1/b))
    assert simplify(variance(X)) == simplify(a**2 * gamma(1 + 2/b) - E(X)**2)
示例#26
0
def test_zeta():
    s = S(5)
    x = Zeta('x', s)
    assert E(x) == zeta(s - 1) / zeta(s)
    assert simplify(
        variance(x)) == (zeta(s) * zeta(s - 2) - zeta(s - 1)**2) / zeta(s)**2
示例#27
0
def test_issue_13324():
    X = Uniform('X', 0, 1)
    assert E(X, X > Rational(1, 2)) == Rational(3, 4)
    assert E(X, X > 0) == Rational(1, 2)
示例#28
0
def test_expectation():
    m = Normal('A', [x, y], [[1, 0], [0, 1]])
    assert simplify(E(m[1])) == y
示例#29
0
def test_joint_vector_expectation():
    from sympy.stats import E
    m = Normal('A', [x, y], [[1, 0], [0, 1]])
    assert E(m) == (x, y)
示例#30
0
def test_joint_vector_expectation():
    m = Normal('A', [x, y], [[1, 0], [0, 1]])
    assert E(m) == (x, y)