def from_binary(cls,binary):
"""
This returns a new `Cell` instance by using a binary representation
either through a *string* representing the a cell in 0's and 1's, or
using a list/tuple with only valid items being again 0's and 1's.
The binary representation will be the size of the `Grid`.In other words
if you wanted to represent **Player 1**'s mark on cell number 2
in a 3x3(2d) Tic Tac Toe game, then you will need a str or list/tuple
like this :
binary = '000000000000000000000010000'
binary = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0]
binary = ['0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','0','1','0','0','0','0']
cell = Cell.from_binary(binary)
"""
verify_binary(binary=binary,mode=GAME_MODES[cls.MODE]['GRID'])
if isinstance(binary,(list,tuple)):
binary = "".join([str(n) for n in binary])
binary = "".join([b for b in reversed(binary)])
cls.validate_binary(binary=binary)
cell, player = cls.decompose_binary(index=binary.index('1'))
return cls(number=cell,player=player)
def from_binary(cls,binary):
verify_binary(binary,mode=GAME_MODES[cls.MODE]['GRID'])
return cls(hash=int(binary, 2))
