示例#1
0
文件: util.py 项目: jjmata/otm-core
def detail_link(thing):
    """
    Get a link to a detail view that can be shown for an
    object with this type

    For example, a 'treephoto' instance provides a link to
    the given tree.
    """
    name = thing.__class__.__name__
    nameLower = name.lower()
    if nameLower in MODEL_DETAILS:
        return MODEL_DETAILS[nameLower](thing)
    elif MapFeature.has_subclass(name):
        return MODEL_DETAILS['mapfeature'](thing)
    else:
        return None
示例#2
0
文件: util.py 项目: grafuls/OTM2
def detail_link(thing):
    """
    Get a link to a detail view that can be shown for an
    object with this type

    For example, a 'treephoto' instance provides a link to
    the given tree.
    """
    name = thing.__class__.__name__
    nameLower = name.lower()
    if nameLower in MODEL_DETAILS:
        return MODEL_DETAILS[nameLower](thing)
    elif MapFeature.has_subclass(name):
        return MODEL_DETAILS['mapfeature'](thing)
    else:
        return None
示例#3
0
文件: util.py 项目: atogle/OTM2
def safe_get_model_class(model_string):
    """
    In a couple of cases we want to be able to convert a string
    into a valid django model class. For instance, if we have
    'Plot' we want to get the actual class for 'treemap.models.Plot'
    in a safe way.

    This function returns the class represented by the given model
    if it exists in 'treemap.models'
    """
    from treemap.models import MapFeature

    # All of our models live in 'treemap.models', so
    # we can start with that namespace
    models_module = __import__('treemap.models')

    if hasattr(models_module.models, model_string):
        return getattr(models_module.models, model_string)
    elif MapFeature.has_subclass(model_string):
        return MapFeature.get_subclass(model_string)
    else:
        raise ValidationError(trans('invalid model type'))
示例#4
0
文件: util.py 项目: ctaylo37/OTM2
def safe_get_model_class(model_string):
    """
    In a couple of cases we want to be able to convert a string
    into a valid django model class. For instance, if we have
    'Plot' we want to get the actual class for 'treemap.models.Plot'
    in a safe way.

    This function returns the class represented by the given model
    if it exists in 'treemap.models'
    """
    from treemap.models import MapFeature

    # All of our models live in 'treemap.models', so
    # we can start with that namespace
    models_module = __import__('treemap.models')

    if hasattr(models_module.models, model_string):
        return getattr(models_module.models, model_string)
    elif MapFeature.has_subclass(model_string):
        return MapFeature.get_subclass(model_string)
    else:
        raise ValidationError(trans('invalid model type: "%s"') % model_string)