Python open_resourcefile示例

示例#1

文件： loadshortcuts.py 项目： RaphaelRochet/puddletag

def create_file(path, resource):
    text = open_resourcefile(resource).read()
    f = open(path, 'w')
    f.write(text)
    f.close()

示例#2

文件： loadshortcuts.py 项目： korala1968/tago

def create_file(path, resource):
    text = open_resourcefile(resource).read()
    f = open(path, 'w')
    f.write(text)
    f.close()

示例#3

文件： loadshortcuts.py 项目： RaphaelRochet/puddletag

# -*- coding: utf-8 -*-
from puddleobjects import PuddleConfig, get_icon
from PyQt4.QtCore import *
from PyQt4.QtGui import *
import sys, pdb, resource,os
from constants import CONFIGDIR, DATADIR
import StringIO
from util import open_resourcefile
from puddlestuff.translations import translate

__version__ = 29

files = [open_resourcefile(filename)
    for filename in [':/caseconversion.action', ':/standard.action']]

SEPARATOR = 'separator'
ALWAYS = 'always'
menu_path = os.path.join(CONFIGDIR, 'menus')
shortcut_path = os.path.join(CONFIGDIR, 'shortcuts')

def create_file(path, resource):
    text = open_resourcefile(resource).read()
    f = open(path, 'w')
    f.write(text)
    f.close()

def check_file(path, resource):
    if not os.path.exists(path):
        create_file(path, resource)
    else:
        cparser = PuddleConfig(path)

示例#4

文件： loadshortcuts.py 项目： korala1968/tago

# -*- coding: utf-8 -*-
from puddleobjects import PuddleConfig, get_icon
from PyQt4.QtCore import *
from PyQt4.QtGui import *
import sys, pdb, resource, os
from constants import CONFIGDIR, DATADIR
import StringIO
from util import open_resourcefile
from puddlestuff.translations import translate

__version__ = 29

files = [
    open_resourcefile(filename)
    for filename in [':/caseconversion.action', ':/standard.action']
]

SEPARATOR = 'separator'
ALWAYS = 'always'
menu_path = os.path.join(CONFIGDIR, 'menus')
shortcut_path = os.path.join(CONFIGDIR, 'shortcuts')


def create_file(path, resource):
    text = open_resourcefile(resource).read()
    f = open(path, 'w')
    f.write(text)
    f.close()


def check_file(path, resource):