示例#1
0
def test_queue():
    class Element(HasDuration):
        def __init__(self, v, d):
            self.val = v
            self.dur = d

        def duration(self) -> int:
            return self.dur

        def __repr__(self):
            return f"Element({self.val})"

    def advance():
        return frozenset(e.val for e in queue.advance())

    queue = Queue()
    queue.extend([Element("a_0", 1), Element("b_0", 2), Element("d_0", 4), Element("c_0", 3)])
    queue.append(Element("a_1", 1))

    assert advance() == {"a_0", "a_1"}
    queue.extend([Element("b_1", 1), Element("e_0", 4)])
    assert advance() == {"b_0", "b_1"}
    assert advance() == {"c_0"}
    assert advance() == {"d_0"}
    assert advance() == {"e_0"}
    assert advance() == set()
    queue.append(Element("f_0", 5))
    for _ in range(4):
        assert advance() == set()
    assert advance() == {"f_0"}
示例#2
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def earliest_ancestor(ancestors, starting_node):
    # create a dictionary
    struct = {}

    # Loop through each pair in the ancestor list
    for pair in ancestors:
        # Parent is the first value of pair
        parent = pair[0]
        # Child is the second value of pair
        child = pair[1]

        # If Child is not in 'struct', add it
        if child not in struct:
            struct[child] = []

        # Then add the parents of each child to their list in the dict
        struct[child].append(parent)

    # Create a queue
    q = Queue()

    # Append the starting node
    q.enqueue([starting_node])

    # Set a default longest node to store the largest distance
    # index 0 and the last node - as it corresponds with the longest distance
    longest_node = [0, -1]

    # Check if the queue is empty
    while len(q) > 0:
        # pop the first path from the queue
        curr_path = q.popleft()

        # get the last node in the path
        last_node = curr_path[-1]

        # Check if the last node is in the dictionary
        if last_node not in struct:
            # if the curr_path is longer than the previous_path, that will be the new longest path
            if len(curr_path
                   ) > longest_node[0] and last_node > longest_node[1]:
                # store the new longest_node
                longest_node = [len(curr_path), last_node]

        # else, if the last_node does have parents
        else:
            # loop through each parent and queue up
            # a path from the current path to each parent
            for x in struct[last_node]:
                q.append(curr_path + [x])

        # if the longest_node is = starting_node, return -1 as the starting_node has no parents
        if longest_node[1] == starting_node:
            return -1

        # Else return the node furthest away, which is longest_node[1]
        else:
            return longest_node[1]
示例#3
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文件: traversal.py 项目: dyno/tree
def breadth_first_traverse(root):
    """breadth-first traversal or "level order traversal"

    algorithm:
      queue.
    """
    if not root:
        return

    q = Queue([root], debug=True)
    while q:
        p = q.pop(0)
        yield p
        if p.left: q.append(p.left)
        if p.right: q.append(p.right)
示例#4
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def breadth_first_traverse(root):
    """breadth-first traversal or "level order traversal"

    algorithm:
      queue.
    """
    if not root:
        return

    q = Queue([root], debug=True)
    while q:
        p = q.pop(0)
        yield p
        if p.left: q.append(p.left)
        if p.right: q.append(p.right)
示例#5
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def print_tree(root):
    """print tree
    """
    if not root:
        return
    if not (root.left or root.right):
        print root.value

    #tree height
    tree_height = 0
    q = Queue([(root, 0)])  #node, layer
    while q:
        p, layer = q.pop(0)
        if p.left or p.right:
            tree_height = layer + 1
        if p.left:
            q.append((p.left, layer + 1))
        if p.right:
            q.append((p.right, layer + 1))

    node_width = 1
    #node_width = 2
    #   *
    #  / \
    # *   *
    tree_width = (2**
                  (tree_height - 1)) * (node_width * 3 + 2) + 2  #2 extra space
    root_node_begin = (tree_width - node_width) / 2

    #initialize line buffer
    count = 0
    for layer in range(1, tree_height + 1):
        count += 2**(tree_height - layer)  #the edge
        count += 1  #the node
    lines = []
    for i in range(0, count + 1):
        lines.append([" "] * tree_width)

    #draw the tree to the buffer
    q = [(root, root_node_begin, 0, 0)]  #(node, node_begin, layer, line_idx)
    while q:
        p, node_begin, layer, line_idx = q.pop(0)
        #print current node to buffer
        line = lines[line_idx]
        for i, c in enumerate("%s" % p.value):
            line[node_begin + i] = c
        if p.left:
            next_line_idx = line_idx + 2**(tree_height - layer - 1) + 1
            #edge to left child
            next_node_begin = node_begin
            for i in range(line_idx + 1, next_line_idx):
                lines[i][next_node_begin - 1] = "/"
                next_node_begin -= 1
            next_node_begin -= node_width
            q.append((p.left, next_node_begin, layer + 1, next_line_idx))

        if p.right:
            next_line_idx = line_idx + 2**(tree_height - layer - 1) + 1
            #edge to right child
            next_node_begin = node_begin + node_width
            for i in range(line_idx + 1, next_line_idx):
                lines[i][next_node_begin] = "\\"
                next_node_begin += 1
            q.append((p.right, next_node_begin, layer + 1, next_line_idx))

    #print out the tree
    for line in lines:
        print "".join(line)
示例#6
0
文件: print_tree.py 项目: dyno/tree
def print_tree(root):
    """print tree
    """
    if not root:
        return
    if not (root.left or root.right):
        print root.value

    #tree height
    tree_height = 0
    q = Queue([(root, 0)]) #node, layer
    while q:
        p, layer = q.pop(0)
        if p.left or p.right:
            tree_height = layer + 1
        if p.left:
            q.append((p.left, layer + 1))
        if p.right:
            q.append((p.right, layer + 1))

    node_width = 1
    #node_width = 2
    #   *
    #  / \
    # *   *
    tree_width = (2 ** (tree_height - 1)) * (node_width * 3 + 2) + 2 #2 extra space
    root_node_begin =  (tree_width - node_width) / 2

    #initialize line buffer
    count = 0
    for layer in range(1, tree_height + 1):
        count += 2 ** (tree_height - layer) #the edge
        count += 1                          #the node
    lines = []
    for i in range(0, count + 1):
        lines.append([" "] * tree_width)

    #draw the tree to the buffer
    q = [(root, root_node_begin, 0, 0)] #(node, node_begin, layer, line_idx)
    while q:
        p, node_begin, layer, line_idx = q.pop(0)
        #print current node to buffer
        line = lines[line_idx]
        for i,c in enumerate("%s" % p.value):
            line[node_begin + i] = c
        if p.left:
            next_line_idx = line_idx + 2 ** (tree_height - layer - 1) + 1
            #edge to left child
            next_node_begin = node_begin
            for i in range(line_idx + 1, next_line_idx):
                lines[i][next_node_begin - 1] = "/"
                next_node_begin -= 1
            next_node_begin -= node_width
            q.append((p.left, next_node_begin, layer + 1, next_line_idx))

        if p.right:
            next_line_idx = line_idx + 2 ** (tree_height - layer - 1) + 1
            #edge to right child
            next_node_begin = node_begin + node_width
            for i in range(line_idx + 1, next_line_idx):
                lines[i][next_node_begin] = "\\"
                next_node_begin += 1
            q.append((p.right, next_node_begin, layer + 1, next_line_idx))

    #print out the tree
    for line in lines:
        print "".join(line)