def hiddenOctave(possibA, possibB):
'''
Returns a list with a (highestPart, lowestPart) pair which represents
a hidden octave between shared outer parts of possibA and possibB. The
outer parts here are the first and last elements of each possibility.
If sopranoPitchA and bassPitchA in possibA move to a sopranoPitchB
and bassPitchB in possibB in similar motion, and the simple interval
between sopranoPitchB and bassPitchB is that of a perfect octave,
then this constitutes a hidden octave between the two possibilities.
>>> from music21 import pitch
>>> from music21.figuredBass import checker
>>> C3 = pitch.Pitch('C3')
>>> D3 = pitch.Pitch('D3')
>>> E3 = pitch.Pitch('E3')
>>> F3 = pitch.Pitch('F3')
>>> A5 = pitch.Pitch('A5')
>>> D6 = pitch.Pitch('D6')
Here, the bass part moves up from C3 to D3 and the soprano part moves
up from A5 to D6. The simple interval between D3 and D6 is a perfect
octave. Therefore, there is a hidden octave between the two possibilities.
>>> possibA1 = (A5, E3, C3)
>>> possibB1 = (D6, F3, D3) #Perfect octave between soprano and bass.
>>> checker.hiddenOctave(possibA1, possibB1)
[(1, 3)]
Here, the bass part moves up from C3 to D3 but the soprano part moves
down from A6 to D6. There is no hidden octave since the parts move in
contrary motion.
>>> A6 = pitch.Pitch('A6')
>>> possibA2 = (A6, E3, C3)
>>> possibB2 = (D6, F3, D3)
>>> checker.hiddenOctave(possibA2, possibB2)
[]
'''
partViolations = []
pairsList = possibility.partPairs(possibA, possibB)
(highestPitchA, highestPitchB) = pairsList[0]
(lowestPitchA, lowestPitchB) = pairsList[-1]
try:
if abs(highestPitchB.ps - lowestPitchB.ps) % 12 == 0:
#Very high probability of hidden octave, but still not certain.
pitchQuartet = (lowestPitchA, lowestPitchB, highestPitchA, highestPitchB)
if pitchQuartet in hiddenOctavesTable:
hasHiddenOctave = hiddenOctavesTable[pitchQuartet]
if hasHiddenOctave:
partViolations.append((1, len(possibB)))
return partViolations
vlq = voiceLeading.VoiceLeadingQuartet(*pitchQuartet)
if vlq.hiddenOctave():
partViolations.append((1, len(possibB)))
hiddenOctavesTable[pitchQuartet] = True
hiddenOctavesTable[pitchQuartet] = False
return partViolations
except AttributeError:
pass
return partViolations
def hiddenFifth(possibA, possibB):
'''
Returns a list with a (highestPart, lowestPart) pair which represents
a hidden fifth between shared outer parts of possibA and possibB. The
outer parts here are the first and last elements of each possibility.
If sopranoPitchA and bassPitchA in possibA move to a sopranoPitchB
and bassPitchB in possibB in similar motion, and the simple interval
between sopranoPitchB and bassPitchB is that of a perfect fifth,
then this constitutes a hidden octave between the two possibilities.
>>> from music21 import pitch
>>> from music21.figuredBass import checker
>>> C3 = pitch.Pitch('C3')
>>> D3 = pitch.Pitch('D3')
>>> E3 = pitch.Pitch('E3')
>>> F3 = pitch.Pitch('F3')
>>> E5 = pitch.Pitch('E5')
>>> A5 = pitch.Pitch('A5')
Here, the bass part moves up from C3 to D3 and the soprano part moves
up from E5 to A5. The simple interval between D3 and A5 is a perfect
fifth. Therefore, there is a hidden fifth between the two possibilities.
>>> possibA1 = (E5, E3, C3)
>>> possibB1 = (A5, F3, D3)
>>> checker.hiddenFifth(possibA1, possibB1)
[(1, 3)]
Here, the soprano and bass parts also move in similar motion, but the
simple interval between D3 and Ab5 is a diminished fifth. Consequently,
there is no hidden fifth.
>>> Ab5 = pitch.Pitch('A-5')
>>> possibA2 = (E5, E3, C3)
>>> possibB2 = (Ab5, F3, D3)
>>> checker.hiddenFifth(possibA2, possibB2)
[]
Now, we have the soprano and bass parts again moving to A5 and D3, whose
simple interval is a perfect fifth. However, the bass moves up while the
soprano moves down. Therefore, there is no hidden fifth.
>>> E6 = pitch.Pitch('E6')
>>> possibA3 = (E6, E3, C3)
>>> possibB3 = (A5, F3, D3)
>>> checker.hiddenFifth(possibA3, possibB3)
[]
'''
partViolations = []
pairsList = possibility.partPairs(possibA, possibB)
(highestPitchA, highestPitchB) = pairsList[0]
(lowestPitchA, lowestPitchB) = pairsList[-1]
try:
if abs(highestPitchB.ps - lowestPitchB.ps) % 12 == 7:
#Very high probability of hidden fifth, but still not certain.
pitchQuartet = (lowestPitchA, lowestPitchB, highestPitchA, highestPitchB)
if pitchQuartet in hiddenFifthsTable:
hasHiddenFifth = hiddenFifthsTable[pitchQuartet]
if hasHiddenFifth:
partViolations.append((1, len(possibB)))
return partViolations
vlq = voiceLeading.VoiceLeadingQuartet(*pitchQuartet)
if vlq.hiddenFifth():
partViolations.append((1, len(possibB)))
hiddenFifthsTable[pitchQuartet] = True
hiddenFifthsTable[pitchQuartet] = False
return partViolations
except AttributeError:
pass
return partViolations
def parallelOctaves(possibA, possibB):
'''
Returns a list of (partNumberA, partNumberB) pairs, each representing
two voices which form parallel octaves.
If pitchA1 and pitchA2 in possibA are separated by
a simple interval of a perfect octave, and they move
to a pitchB1 and pitchB2 in possibB also separated
by the simple interval of a perfect octave, then this
constitutes parallel octaves between these two parts.
>>> from music21 import pitch
>>> from music21.figuredBass import checker
>>> C3 = pitch.Pitch('C3')
>>> D3 = pitch.Pitch('D3')
>>> G3 = pitch.Pitch('G3')
>>> A3 = pitch.Pitch('A3')
>>> C4 = pitch.Pitch('C4')
>>> D4 = pitch.Pitch('D4')
Here, the soprano moves from C4 to D4 and the bass moves
from C3 to D3. The interval between C3 and C4, as well as
between D3 and D4, is a parallel octave. The two parts,
and therefore the two possibilities, have parallel octaves.
>>> possibA1 = (C4, G3, C3)
>>> possibB1 = (D4, A3, D3)
>>> checker.parallelOctaves(possibA1, possibB1)
[(1, 3)]
Now, the soprano moves down to B3. The interval between
D3 and B3 is a major sixth. The soprano and bass parts
no longer have parallel octaves. The tenor part forms
a parallel octave with neither the bass nor soprano,
so the two possibilities do not have parallel octaves.
(Notice, however, the parallel fifth between the bass
and tenor!)
>>> B3 = pitch.Pitch('B3')
>>> possibA2 = (C4, G3, C3)
>>> possibB2 = (B3, A3, D3)
>>> checker.parallelOctaves(possibA2, possibB2)
[]
'''
pairsList = possibility.partPairs(possibA, possibB)
partViolations = []
for pair1Index in range(len(pairsList)):
(higherPitchA, higherPitchB) = pairsList[pair1Index]
for pair2Index in range(pair1Index + 1, len(pairsList)):
(lowerPitchA, lowerPitchB) = pairsList[pair2Index]
try:
if not abs(higherPitchA.ps - lowerPitchA.ps) % 12 == 0:
continue
if not abs(higherPitchB.ps - lowerPitchB.ps) % 12 == 0:
continue
except AttributeError:
continue
#Very high probability of ||8, but still not certain.
pitchQuartet = (lowerPitchA, lowerPitchB, higherPitchA, higherPitchB)
if pitchQuartet in parallelOctavesTable:
hasParallelOctaves = parallelOctavesTable[pitchQuartet]
if hasParallelOctaves:
partViolations.append((pair1Index + 1, pair2Index + 1))
vlq = voiceLeading.VoiceLeadingQuartet(*pitchQuartet)
if vlq.parallelOctave():
partViolations.append((pair1Index + 1, pair2Index + 1))
parallelOctavesTable[pitchQuartet] = True
parallelOctavesTable[pitchQuartet] = False
return partViolations
def parallelFifths(possibA, possibB):
'''
Returns a list of (partNumberA, partNumberB) pairs, each representing
two voices which form parallel fifths.
If pitchA1 and pitchA2 in possibA are separated by
a simple interval of a perfect fifth, and they move
to a pitchB1 and pitchB2 in possibB also separated
by the simple interval of a perfect fifth, then this
constitutes parallel fifths between these two parts.
>>> from music21 import pitch
>>> from music21.figuredBass import checker
>>> C3 = pitch.Pitch('C3')
>>> D3 = pitch.Pitch('D3')
>>> G3 = pitch.Pitch('G3')
>>> A3 = pitch.Pitch('A3')
>>> A4 = pitch.Pitch('A4')
>>> B4 = pitch.Pitch('B4')
Here, the bass moves from C3 to D3 and the tenor moves
from G3 to A3. The interval between C3 and G3, as well
as between D3 and A3, is a perfect fifth. These two
parts, and therefore the two possibilities, have
parallel fifths.
>>> possibA1 = (B4, G3, C3)
>>> possibB1 = (A4, A3, D3)
>>> checker.parallelFifths(possibA1, possibB1)
[(2, 3)]
Now, the tenor moves instead to F3. The interval between
D3 and F3 is a minor third. The bass and tenor parts
don't form parallel fifths. The soprano part forms parallel
fifths with neither the bass nor tenor parts. The
two possibilities, therefore, have no parallel fifths.
>>> F3 = pitch.Pitch('F3')
>>> possibA2 = (B4, G3, C3)
>>> possibB2 = (A4, F3, D3)
>>> checker.parallelFifths(possibA2, possibB2)
[]
'''
pairsList = possibility.partPairs(possibA, possibB)
partViolations = []
for pair1Index in range(len(pairsList)):
(higherPitchA, higherPitchB) = pairsList[pair1Index]
for pair2Index in range(pair1Index + 1, len(pairsList)):
(lowerPitchA, lowerPitchB) = pairsList[pair2Index]
try:
if not abs(higherPitchA.ps - lowerPitchA.ps) % 12 == 7:
continue
if not abs(higherPitchB.ps - lowerPitchB.ps) % 12 == 7:
continue
except AttributeError:
continue
#Very high probability of ||5, but still not certain.
pitchQuartet = (lowerPitchA, lowerPitchB, higherPitchA, higherPitchB)
if pitchQuartet in parallelFifthsTable:
hasParallelFifths = parallelFifthsTable[pitchQuartet]
if hasParallelFifths:
partViolations.append((pair1Index + 1, pair2Index + 1))
vlq = voiceLeading.VoiceLeadingQuartet(*pitchQuartet)
if vlq.parallelFifth():
partViolations.append((pair1Index + 1, pair2Index + 1))
parallelFifthsTable[pitchQuartet] = True
parallelFifthsTable[pitchQuartet] = False
return partViolations
def hiddenOctave(possibA, possibB):
'''
Returns a list with a (highestPart, lowestPart) pair which represents
a hidden octave between shared outer parts of possibA and possibB. The
outer parts here are the first and last elements of each possibility.
If sopranoPitchA and bassPitchA in possibA move to a sopranoPitchB
and bassPitchB in possibB in similar motion, and the simple interval
between sopranoPitchB and bassPitchB is that of a perfect octave,
then this constitutes a hidden octave between the two possibilities.
>>> from music21 import pitch
>>> from music21.figuredBass import checker
>>> C3 = pitch.Pitch('C3')
>>> D3 = pitch.Pitch('D3')
>>> E3 = pitch.Pitch('E3')
>>> F3 = pitch.Pitch('F3')
>>> A5 = pitch.Pitch('A5')
>>> D6 = pitch.Pitch('D6')
Here, the bass part moves up from C3 to D3 and the soprano part moves
up from A5 to D6. The simple interval between D3 and D6 is a perfect
octave. Therefore, there is a hidden octave between the two possibilities.
>>> possibA1 = (A5, E3, C3)
>>> possibB1 = (D6, F3, D3) #Perfect octave between soprano and bass.
>>> checker.hiddenOctave(possibA1, possibB1)
[(1, 3)]
Here, the bass part moves up from C3 to D3 but the soprano part moves
down from A6 to D6. There is no hidden octave since the parts move in
contrary motion.
>>> A6 = pitch.Pitch('A6')
>>> possibA2 = (A6, E3, C3)
>>> possibB2 = (D6, F3, D3)
>>> checker.hiddenOctave(possibA2, possibB2)
[]
'''
partViolations = []
pairsList = possibility.partPairs(possibA, possibB)
(highestPitchA, highestPitchB) = pairsList[0]
(lowestPitchA, lowestPitchB) = pairsList[-1]
try:
if abs(highestPitchB.ps - lowestPitchB.ps) % 12 == 0:
#Very high probability of hidden octave, but still not certain.
pitchQuartet = (lowestPitchA, lowestPitchB, highestPitchA,
highestPitchB)
if pitchQuartet in hiddenOctavesTable:
hasHiddenOctave = hiddenOctavesTable[pitchQuartet]
if hasHiddenOctave:
partViolations.append((1, len(possibB)))
return partViolations
vlq = voiceLeading.VoiceLeadingQuartet(*pitchQuartet)
if vlq.hiddenOctave():
partViolations.append((1, len(possibB)))
hiddenOctavesTable[pitchQuartet] = True
hiddenOctavesTable[pitchQuartet] = False
return partViolations
except AttributeError:
pass
return partViolations
def parallelOctaves(possibA, possibB):
'''
Returns a list of (partNumberA, partNumberB) pairs, each representing
two voices which form parallel octaves.
If pitchA1 and pitchA2 in possibA are separated by
a simple interval of a perfect octave, and they move
to a pitchB1 and pitchB2 in possibB also separated
by the simple interval of a perfect octave, then this
constitutes parallel octaves between these two parts.
>>> from music21 import pitch
>>> from music21.figuredBass import checker
>>> C3 = pitch.Pitch('C3')
>>> D3 = pitch.Pitch('D3')
>>> G3 = pitch.Pitch('G3')
>>> A3 = pitch.Pitch('A3')
>>> C4 = pitch.Pitch('C4')
>>> D4 = pitch.Pitch('D4')
Here, the soprano moves from C4 to D4 and the bass moves
from C3 to D3. The interval between C3 and C4, as well as
between D3 and D4, is a parallel octave. The two parts,
and therefore the two possibilities, have parallel octaves.
>>> possibA1 = (C4, G3, C3)
>>> possibB1 = (D4, A3, D3)
>>> checker.parallelOctaves(possibA1, possibB1)
[(1, 3)]
Now, the soprano moves down to B3. The interval between
D3 and B3 is a major sixth. The soprano and bass parts
no longer have parallel octaves. The tenor part forms
a parallel octave with neither the bass nor soprano,
so the two possibilities do not have parallel octaves.
(Notice, however, the parallel fifth between the bass
and tenor!)
>>> B3 = pitch.Pitch('B3')
>>> possibA2 = (C4, G3, C3)
>>> possibB2 = (B3, A3, D3)
>>> checker.parallelOctaves(possibA2, possibB2)
[]
'''
pairsList = possibility.partPairs(possibA, possibB)
partViolations = []
for pair1Index in range(len(pairsList)):
(higherPitchA, higherPitchB) = pairsList[pair1Index]
for pair2Index in range(pair1Index + 1, len(pairsList)):
(lowerPitchA, lowerPitchB) = pairsList[pair2Index]
try:
if not abs(higherPitchA.ps - lowerPitchA.ps) % 12 == 0:
continue
if not abs(higherPitchB.ps - lowerPitchB.ps) % 12 == 0:
continue
except AttributeError:
continue
#Very high probability of ||8, but still not certain.
pitchQuartet = (lowerPitchA, lowerPitchB, higherPitchA,
higherPitchB)
if pitchQuartet in parallelOctavesTable:
hasParallelOctaves = parallelOctavesTable[pitchQuartet]
if hasParallelOctaves:
partViolations.append((pair1Index + 1, pair2Index + 1))
vlq = voiceLeading.VoiceLeadingQuartet(*pitchQuartet)
if vlq.parallelOctave():
partViolations.append((pair1Index + 1, pair2Index + 1))
parallelOctavesTable[pitchQuartet] = True
parallelOctavesTable[pitchQuartet] = False
return partViolations
def hiddenFifth(possibA, possibB):
'''
Returns a list with a (highestPart, lowestPart) pair which represents
a hidden fifth between shared outer parts of possibA and possibB. The
outer parts here are the first and last elements of each possibility.
If sopranoPitchA and bassPitchA in possibA move to a sopranoPitchB
and bassPitchB in possibB in similar motion, and the simple interval
between sopranoPitchB and bassPitchB is that of a perfect fifth,
then this constitutes a hidden octave between the two possibilities.
>>> from music21 import pitch
>>> from music21.figuredBass import checker
>>> C3 = pitch.Pitch('C3')
>>> D3 = pitch.Pitch('D3')
>>> E3 = pitch.Pitch('E3')
>>> F3 = pitch.Pitch('F3')
>>> E5 = pitch.Pitch('E5')
>>> A5 = pitch.Pitch('A5')
Here, the bass part moves up from C3 to D3 and the soprano part moves
up from E5 to A5. The simple interval between D3 and A5 is a perfect
fifth. Therefore, there is a hidden fifth between the two possibilities.
>>> possibA1 = (E5, E3, C3)
>>> possibB1 = (A5, F3, D3)
>>> checker.hiddenFifth(possibA1, possibB1)
[(1, 3)]
Here, the soprano and bass parts also move in similar motion, but the
simple interval between D3 and Ab5 is a diminished fifth. Consequently,
there is no hidden fifth.
>>> Ab5 = pitch.Pitch('A-5')
>>> possibA2 = (E5, E3, C3)
>>> possibB2 = (Ab5, F3, D3)
>>> checker.hiddenFifth(possibA2, possibB2)
[]
Now, we have the soprano and bass parts again moving to A5 and D3, whose
simple interval is a perfect fifth. However, the bass moves up while the
soprano moves down. Therefore, there is no hidden fifth.
>>> E6 = pitch.Pitch('E6')
>>> possibA3 = (E6, E3, C3)
>>> possibB3 = (A5, F3, D3)
>>> checker.hiddenFifth(possibA3, possibB3)
[]
'''
partViolations = []
pairsList = possibility.partPairs(possibA, possibB)
(highestPitchA, highestPitchB) = pairsList[0]
(lowestPitchA, lowestPitchB) = pairsList[-1]
try:
if abs(highestPitchB.ps - lowestPitchB.ps) % 12 == 7:
#Very high probability of hidden fifth, but still not certain.
pitchQuartet = (lowestPitchA, lowestPitchB, highestPitchA,
highestPitchB)
if pitchQuartet in hiddenFifthsTable:
hasHiddenFifth = hiddenFifthsTable[pitchQuartet]
if hasHiddenFifth:
partViolations.append((1, len(possibB)))
return partViolations
vlq = voiceLeading.VoiceLeadingQuartet(*pitchQuartet)
if vlq.hiddenFifth():
partViolations.append((1, len(possibB)))
hiddenFifthsTable[pitchQuartet] = True
hiddenFifthsTable[pitchQuartet] = False
return partViolations
except AttributeError:
pass
return partViolations
def parallelFifths(possibA, possibB):
'''
Returns a list of (partNumberA, partNumberB) pairs, each representing
two voices which form parallel fifths.
If pitchA1 and pitchA2 in possibA are separated by
a simple interval of a perfect fifth, and they move
to a pitchB1 and pitchB2 in possibB also separated
by the simple interval of a perfect fifth, then this
constitutes parallel fifths between these two parts.
>>> from music21 import pitch
>>> from music21.figuredBass import checker
>>> C3 = pitch.Pitch('C3')
>>> D3 = pitch.Pitch('D3')
>>> G3 = pitch.Pitch('G3')
>>> A3 = pitch.Pitch('A3')
>>> A4 = pitch.Pitch('A4')
>>> B4 = pitch.Pitch('B4')
Here, the bass moves from C3 to D3 and the tenor moves
from G3 to A3. The interval between C3 and G3, as well
as between D3 and A3, is a perfect fifth. These two
parts, and therefore the two possibilities, have
parallel fifths.
>>> possibA1 = (B4, G3, C3)
>>> possibB1 = (A4, A3, D3)
>>> checker.parallelFifths(possibA1, possibB1)
[(2, 3)]
Now, the tenor moves instead to F3. The interval between
D3 and F3 is a minor third. The bass and tenor parts
don't form parallel fifths. The soprano part forms parallel
fifths with neither the bass nor tenor parts. The
two possibilities, therefore, have no parallel fifths.
>>> F3 = pitch.Pitch('F3')
>>> possibA2 = (B4, G3, C3)
>>> possibB2 = (A4, F3, D3)
>>> checker.parallelFifths(possibA2, possibB2)
[]
'''
pairsList = possibility.partPairs(possibA, possibB)
partViolations = []
for pair1Index in range(len(pairsList)):
(higherPitchA, higherPitchB) = pairsList[pair1Index]
for pair2Index in range(pair1Index + 1, len(pairsList)):
(lowerPitchA, lowerPitchB) = pairsList[pair2Index]
try:
if not abs(higherPitchA.ps - lowerPitchA.ps) % 12 == 7:
continue
if not abs(higherPitchB.ps - lowerPitchB.ps) % 12 == 7:
continue
except AttributeError:
continue
#Very high probability of ||5, but still not certain.
pitchQuartet = (lowerPitchA, lowerPitchB, higherPitchA,
higherPitchB)
if pitchQuartet in parallelFifthsTable:
hasParallelFifths = parallelFifthsTable[pitchQuartet]
if hasParallelFifths:
partViolations.append((pair1Index + 1, pair2Index + 1))
vlq = voiceLeading.VoiceLeadingQuartet(*pitchQuartet)
if vlq.parallelFifth():
partViolations.append((pair1Index + 1, pair2Index + 1))
parallelFifthsTable[pitchQuartet] = True
parallelFifthsTable[pitchQuartet] = False
return partViolations
