コード例 #1
0
def solut(theta, D, nmax, N, wold):
    """ Method that sets up the tridiagonal implicitt scheme to be solved with tdma using an iteration process
        Args:
            theta(float): parameter between 0 and 1 seperating different schemes (FTCS, Laasonen, Crank-Nicolson...)
            D(float): Numerical diffusion number
            nmax(int): number of timesteps
            N(int): number of equations
            wold(array): solution from previous iteration

    
        Returns:
            wnew(array): iterated solution at timestep nmax
    """
    
    tmp1 = D*(1. - theta)
    
    for n in range(nmax):
        a = np.zeros(N)
        b = np.zeros(N)
        c = np.zeros(N)
        d = np.zeros(N)

        for j in range(1,N):
            fac = 0.5 / (j + 1)
            a[j] = -D*theta*(1 - fac)
            b[j] = (1 + 2*D*theta)
            c[j] = -D*theta*(1 + fac)
            d[j] = tmp1*((1 - fac)*wold[j - 1] + (1 + fac)*wold[j + 1]) + (1 - 2*tmp1)*wold[j]
        b[0] = 1 + 4*D*theta/3
        c[0] = -4*D*theta/3
        d[0] = (1-4*tmp1/3.)*wold[0] + 4*tmp1*wold[1]/3.
        wnew = tdma(a, b, c, d)
        wold = np.append(wnew, [0])
    
    return wnew
コード例 #2
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def solveAllTimestepsStartup(theta, D, nmax, N, wold):
    """ Method that sets up the tridiagonal theta-scheme for the startup of flow in a pipe (Szymanski's problem).
        The method solves without storing solutions from t0 to t = dt*nmax, using standard tdma solver.
        The Governing equation is:
        dw/dt = w'' + w'/r, w = w(r,t), 0 < r < 1
        where w' denotes dw/dr.
        velocity field: u(r,t) = us(r) -w(r,t)
        where us = 1 - r^2
        Boundary conditions: w^n+1(0) = (1-2D)w^n(1) + 4Du^n(1), w(r) = 0
        Initial condition: w(r,0) = 1- r^2 = us
        Args:
            theta(float): parameter between 0 and 1 seperating different schemes (FTCS, Laasonen, Crank-Nicolson...)
            D(float): Numerical diffusion number
            nmax(int): number of iterations
            N(int): number of equations
            wold(array): solution from previous iteration

    
        Returns:
            wnew(array): solution at time t = dt*nmax
    """

    tmp1 = D * (1. - theta)

    for n in range(nmax):
        a = np.zeros(N)
        b = np.zeros(N)
        c = np.zeros(N)
        d = np.zeros(N)

        for j in range(1, N):
            fac = 0.5 / (j)
            a[j] = -D * theta * (1 - fac)
            b[j] = (1 + 2 * D * theta)
            c[j] = -D * theta * (1 + fac)
            d[j] = tmp1 * ((1 - fac) * wold[j - 1] +
                           (1 + fac) * wold[j + 1]) + (1 - 2 * tmp1) * wold[j]

        b[0] = 1 + 4 * D * theta
        c[0] = -4 * D * theta
        d[0] = wold[0] + 4 * tmp1 * (wold[1] - wold[0])
        wnew = tdma(a, b, c, d)
        wold = np.append(wnew, [0])

    return wold
コード例 #3
0
ファイル: startupPythonic.py プロジェクト: lrhgit/tkt4140
def solveAllTimestepsStartup(theta, D, nmax, N, wold):
    """ Method that sets up the tridiagonal theta-scheme for the startup of flow in a pipe (Szymanski's problem).
        The method solves without storing solutions from t0 to t = dt*nmax, using standard tdma solver.
        The Governing equation is:
        dw/dt = w'' + w'/r, w = w(r,t), 0 < r < 1
        where w' denotes dw/dr.
        velocity field: u(r,t) = us(r) -w(r,t)
        where us = 1 - r^2
        Boundary conditions: w^n+1(0) = (1-2D)w^n(1) + 4Du^n(1), w(r) = 0
        Initial condition: w(r,0) = 1- r^2 = us
        Args:
            theta(float): parameter between 0 and 1 seperating different schemes (FTCS, Laasonen, Crank-Nicolson...)
            D(float): Numerical diffusion number
            nmax(int): number of iterations
            N(int): number of equations
            wold(array): solution from previous iteration

    
        Returns:
            wnew(array): solution at time t = dt*nmax
    """
    
    tmp1 = D*(1. - theta)
    
    for n in range(nmax):
        a = np.zeros(N)
        b = np.zeros(N)
        c = np.zeros(N)
        d = np.zeros(N)

        for j in range(1, N):
            fac = 0.5 / (j)
            a[j] = -D*theta*(1 - fac)
            b[j] = (1 + 2*D*theta)
            c[j] = -D*theta*(1 + fac)
            d[j] = tmp1*((1 - fac)*wold[j - 1] + (1 + fac)*wold[j + 1]) + (1 - 2*tmp1)*wold[j]
            
        b[0] = 1 + 4*D*theta
        c[0] = -4*D*theta
        d[0] = wold[0] + 4*tmp1*(wold[1] - wold[0])
        wnew = tdma(a, b, c, d)
        wold = np.append(wnew, [0])
    
    return wold
コード例 #4
0
def solveNextTimestepStartupV2(theta, D, N, wold):
    """ Method that sets up the tridiagonal theta-scheme for the startup of flow in a pipe (Szymanski's problem).
        The method solves only for the next time-step, using standard tdma solver.
        The Governing equation is:
        dw/dt = w'' + w'/r, w = w(r,t), 0 < r < 1
        where w' denotes dw/dr.
        velocity field: u(r,t) = us(r) -w(r,t)
        where us = 1 - r^2
        Boundary conditions: w(0) = (4w(1)-w(2))/3), w(r) = 0
        Initial condition: w(r,0) = 1- r^2 = us
        Args:
            theta(float): parameter between 0 and 1 seperating different schemes (FTCS, Laasonen, Crank-Nicolson...)
            D(float): Numerical diffusion number
            N(int): number of equations
            wold(array): solution from previous iteration

    
        Returns:
            wnew(array): solution at time t^n+1
    """
    wold = wold[1:]  # in this version of startup w0 is not solved with tdma
    N = N - 1  # this version has one less unknown to be solved with tdma
    tmp1 = D * (1. - theta)

    a = np.zeros(N)
    b = np.zeros(N)
    c = np.zeros(N)
    d = np.zeros(N)

    for j in range(1, N):
        fac = 0.5 / (j + 1)
        a[j] = -D * theta * (1 - fac)
        b[j] = (1 + 2 * D * theta)
        c[j] = -D * theta * (1 + fac)
        d[j] = tmp1 * ((1 - fac) * wold[j - 1] +
                       (1 + fac) * wold[j + 1]) + (1 - 2 * tmp1) * wold[j]
    b[0] = 1 + 4 * D * theta / 3
    c[0] = -4 * D * theta / 3
    d[0] = (1 - 4 * tmp1 / 3.) * wold[0] + 4 * tmp1 * wold[1] / 3.
    wnew = tdma(a, b, c, d)  # solve with tdma
    w0 = (4 * wnew[0] - wnew[1]) / 3
    wnew = np.append(np.append(w0, wnew), [0])  # add BCs

    return wnew
コード例 #5
0
ファイル: startupPythonic.py プロジェクト: lrhgit/tkt4140
def solveNextTimestepStartupV2(theta, D, N, wold):
    """ Method that sets up the tridiagonal theta-scheme for the startup of flow in a pipe (Szymanski's problem).
        The method solves only for the next time-step, using standard tdma solver.
        The Governing equation is:
        dw/dt = w'' + w'/r, w = w(r,t), 0 < r < 1
        where w' denotes dw/dr.
        velocity field: u(r,t) = us(r) -w(r,t)
        where us = 1 - r^2
        Boundary conditions: w(0) = (4w(1)-w(2))/3), w(r) = 0
        Initial condition: w(r,0) = 1- r^2 = us
        Args:
            theta(float): parameter between 0 and 1 seperating different schemes (FTCS, Laasonen, Crank-Nicolson...)
            D(float): Numerical diffusion number
            N(int): number of equations
            wold(array): solution from previous iteration

    
        Returns:
            wnew(array): solution at time t^n+1
    """
    wold = wold[1:] # in this version of startup w0 is not solved with tdma
    N = N - 1 # this version has one less unknown to be solved with tdma
    tmp1 = D*(1. - theta)
    
    a = np.zeros(N)
    b = np.zeros(N)
    c = np.zeros(N)
    d = np.zeros(N)

    for j in range(1,N):
        fac = 0.5 / (j + 1)
        a[j] = -D*theta*(1 - fac)
        b[j] = (1 + 2*D*theta)
        c[j] = -D*theta*(1 + fac)
        d[j] = tmp1*((1 - fac)*wold[j - 1] + (1 + fac)*wold[j + 1]) + (1 - 2*tmp1)*wold[j]
    b[0] = 1 + 4*D*theta/3
    c[0] = -4*D*theta/3
    d[0] = (1-4*tmp1/3.)*wold[0] + 4*tmp1*wold[1]/3.
    wnew = tdma(a, b, c, d) # solve with tdma
    w0 = (4*wnew[0]-wnew[1])/3
    wnew = np.append(np.append(w0, wnew), [0]) # add BCs
    
    return wnew
コード例 #6
0
def solveNextTimestepCouette(theta, D, N, uold):
    """ Method that sets up the tridiagonal theta-scheme for the transient couettflow.
        At time t=t0 the plate starts moving at y=0
        The method solves only for the next time-step, using standard tdma solver.
        The Governing equation is:
        du/dt = d^2(u)/dx^2 , u = u(y,t), 0 < y < 1
        Boundary conditions: u(0, t) = 1, u(1, t) = 0
        Initial condition: u(t, 0) = 0 t<0,  u(t, 0) = 1 t>0
        Args:
            theta(float): parameter between 0 and 1 seperating different schemes (FTCS, Laasonen, Crank-Nicolson...)
            D(float): Numerical diffusion number
            N(int): number of equations
            uold(array): solution from previous iteration

    
        Returns:
            unew(array): solution at time t^n+1
    """
    u0 = uold[0]
    uold = uold[1:]
    N = N - 1
    tmp1 = D * (1. - theta)

    a = np.zeros(N)
    b = np.zeros(N)
    c = np.zeros(N)
    d = np.zeros(N)

    for j in range(1, N):
        a[j] = -D * theta
        b[j] = (1. + 2 * D * theta)
        c[j] = -D * theta
        d[j] = tmp1 * (uold[j - 1] + uold[j + 1]) + (1. - 2 * tmp1) * uold[j]

    b[0] = (1 + 2 * D * theta)
    c[0] = -D * theta
    d[0] = tmp1 * (u0 + uold[1]) + (1. - 2 * tmp1) * uold[0] + D * theta * u0
    unew = tdma(a, b, c, d)  # solve with tdma
    unew = np.append(np.append(1., unew), 0.)  # add BCs

    return unew
コード例 #7
0
ファイル: couette_Flow_tdma.py プロジェクト: lrhgit/tkt4140
def solveNextTimestepCouette(theta, D, N, uold):
    """ Method that sets up the tridiagonal theta-scheme for the transient couettflow.
        At time t=t0 the plate starts moving at y=0
        The method solves only for the next time-step, using standard tdma solver.
        The Governing equation is:
        du/dt = d^2(u)/dx^2 , u = u(y,t), 0 < y < 1
        Boundary conditions: u(0, t) = 1, u(1, t) = 0
        Initial condition: u(t, 0) = 0 t<0,  u(t, 0) = 1 t>0
        Args:
            theta(float): parameter between 0 and 1 seperating different schemes (FTCS, Laasonen, Crank-Nicolson...)
            D(float): Numerical diffusion number
            N(int): number of equations
            uold(array): solution from previous iteration

    
        Returns:
            unew(array): solution at time t^n+1
    """
    u0 = uold[0]
    uold = uold[1:] 
    N = N - 1 
    tmp1 = D*(1. - theta)
    
    a = np.zeros(N)
    b = np.zeros(N)
    c = np.zeros(N)
    d = np.zeros(N)

    for j in range(1,N):
        a[j] = -D*theta
        b[j] = (1. + 2*D*theta)
        c[j] = -D*theta
        d[j] = tmp1*(uold[j - 1] + uold[j + 1]) + (1. - 2*tmp1)*uold[j]
        
    b[0] = (1 + 2*D*theta)
    c[0] = -D*theta
    d[0] = tmp1*(u0 + uold[1]) + (1. - 2*tmp1)*uold[0] + D*theta*u0
    unew = tdma(a, b, c, d) # solve with tdma
    unew = np.append(np.append(1., unew), 0.) # add BCs
    
    return unew
コード例 #8
0
ファイル: taylor34.py プロジェクト: lrhgit/tkt4140
it, itmax, dymax, RelTol = 0, 15, 1., 10**-10
legends=[]
while (dymax > RelTol) and (it < itmax):
    """iteration process of linearized system of equations using taylor 
    """
    plot(x,ym) # plot ym for iteration No. it
    legends.append(str(it))
    it = it + 1
    a = np.ones(n) 
    c = np.ones(n)
    b = -(np.ones(n)*2. + fac*ym)
    d = -(fac*0.5*ym**2)
    d[n-1] = d[n-1]-1
    d[0] = d[0]-4

    ym1 = tdma(a,b,c,d) # solution
    dymax  = np.max(np.abs((ym1-ym)/ym))
    ym = ym1

    print('it = {},  dymax = {} '.format(it, dymax))
    
legend(legends,loc='best',frameon=False)


ya = 4./(1+x)**2
feil = np.abs((ym1-ya)/ya)
print "\n"

for l in range(len(x)):
    print 'x = {},  y = {},  ya = {}'.format(x[l], ym1[l], ya[l])
コード例 #9
0
ファイル: avvikr.py プロジェクト: rachitsingh11/tkt4140
    1 - x
)  # initial guess of y. ym = np.zeros(n) will converge to y1. ym = -20*x*(1-x) for instance will converge to y2

itmax = 15

for it in range(itmax):
    """iteration process of linearized system of equations"""
    # need to set a, b, c and d vector inside for loop since indices are changed in tdma solver
    a = np.ones(n)
    c = np.ones(n)
    b = -(np.ones(n) * 2. + fac * ym)
    d = -(np.ones(n) * fac * 0.5 * ym**2)
    d[n - 1] = -1.
    d[0] = -4.

    ym1 = tdma(a, b, c, d)  # solution
    dy = np.abs(ym1 - ym)
    tr2 = np.max(dy) / np.max(np.abs(ym1))
    tr3 = np.sum(dy) / np.sum(np.abs(ym1))
    ym = ym1

    print 'it = {},  tr2 = {},  tr3 = {} '.format(it, tr2, tr3)

ya = 4. / (1 + x)**2
feil = np.abs((ym1 - ya) / ya)

# plotting:
legends = []  # empty list to append legends as plots are generated
# Add the labels
plot(x, ym1, "b")  # plot numerical solution
legends.append('y2 numerical')