def split_multi_keywords(sentence, keyword):
"""
如果关键词为一对(e.g. [因为, 所以]), 则调用此方法. 此方法列出各种关键词对对应的分句规则,
如果符合其一, 则返回该规则分句结果. 都不满足则返回None
:param sentence: 输入句子
:param keyword: 关联词对
:return:
"""
# ..., ...因为, ..., ...所以, ...
rst = pattern.rule_scskcscskcs(sentence, keyword, comma2=True, comma4=True)
if rst:
return [[rst['left'], rst['right']]]
# ..., ...因为, ..., ...所以...
rst = pattern.rule_scskcscskcs(sentence, keyword, comma2=True)
if rst:
return [[rst['left'], rst['right']]]
# ..., ...因为..., ...所以, ...
rst = pattern.rule_scskcscskcs(sentence, keyword, comma4=True)
if rst:
return [[rst['left'], rst['right']]]
# ..., ...因为..., ...所以 ...
rst = pattern.rule_scskcscskcs(sentence, keyword)
if rst:
return [[rst['left'], rst['right']]]
# ...因为, ..., ...所以, ...
rst = pattern.rule_skcscskcs(sentence, keyword, comma1=True, comma3=True)
if rst:
return [[rst['left'], rst['right']]]
# ...因为 ..., ...所以, ...
rst = pattern.rule_skcscskcs(sentence, keyword, comma3=True)
if rst:
return [[rst['left'], rst['right']]]
# ...因为, ..., ...所以 ...
rst = pattern.rule_skcscskcs(sentence, keyword, comma1=True)
if rst:
return [[rst['left'], rst['right']]]
# ...因为 ..., ...所以...
rst = pattern.rule_skcscskcs(sentence, keyword)
if rst:
return [[rst['left'], rst['right']]]
# ...因为...所以...
rst = pattern.rule_sksks(sentence, keyword)
if rst:
return [[rst['left'], rst['right']]]
return None
def rule12(sentence, keyword):
# 匹配模式: ...因为..., ...所以, ...
return pattern.rule_skcscskcs(sentence, keyword, comma3=True)
def rule21(sentence, keyword):
# 匹配模式: ...之所以..., ...是因为...
return pattern.rule_skcscskcs(sentence, keyword, reverse=True)
def rule13(sentence, keyword):
# 匹配模式: ...因为..., ...所以...
return pattern.rule_skcscskcs(sentence, keyword)
def rule101(sentence, keyword):
# 匹配模式: ...不仅..., ...还...
return pattern.rule_skcscskcs(sentence, keyword)
def rule23(sentence, keyword):
# 匹配模式: ...只有..., ...才能...
return pattern.rule_skcscskcs(sentence, keyword)
def rule22(sentence, keyword):
# 匹配模式: ...只有..., ...才能, ...
return pattern.rule_skcscskcs(sentence, keyword, comma3=True)
def rule11(sentence, keyword):
# 匹配模式: ...如果..., ...就...
return pattern.rule_skcscskcs(sentence, keyword)
