Python rule_skcscskcs示例

示例#1

def split_multi_keywords(sentence, keyword):
    """
    如果关键词为一对(e.g. [因为, 所以]), 则调用此方法. 此方法列出各种关键词对对应的分句规则,
    如果符合其一, 则返回该规则分句结果. 都不满足则返回None
    :param sentence: 输入句子
    :param keyword: 关联词对
    :return:
    """
    # ..., ...因为, ..., ...所以, ...
    rst = pattern.rule_scskcscskcs(sentence, keyword, comma2=True, comma4=True)
    if rst:
        return [[rst['left'], rst['right']]]

    # ..., ...因为, ..., ...所以...
    rst = pattern.rule_scskcscskcs(sentence, keyword, comma2=True)
    if rst:
        return [[rst['left'], rst['right']]]

    # ..., ...因为..., ...所以, ...
    rst = pattern.rule_scskcscskcs(sentence, keyword, comma4=True)
    if rst:
        return [[rst['left'], rst['right']]]

    # ..., ...因为..., ...所以 ...
    rst = pattern.rule_scskcscskcs(sentence, keyword)
    if rst:
        return [[rst['left'], rst['right']]]

    # ...因为, ..., ...所以, ...
    rst = pattern.rule_skcscskcs(sentence, keyword, comma1=True, comma3=True)
    if rst:
        return [[rst['left'], rst['right']]]
    # ...因为 ..., ...所以, ...
    rst = pattern.rule_skcscskcs(sentence, keyword, comma3=True)
    if rst:
        return [[rst['left'], rst['right']]]
    # ...因为, ..., ...所以 ...
    rst = pattern.rule_skcscskcs(sentence, keyword, comma1=True)
    if rst:
        return [[rst['left'], rst['right']]]
    # ...因为 ..., ...所以...
    rst = pattern.rule_skcscskcs(sentence, keyword)
    if rst:
        return [[rst['left'], rst['right']]]

    # ...因为...所以...
    rst = pattern.rule_sksks(sentence, keyword)
    if rst:
        return [[rst['left'], rst['right']]]
    return None

示例#2

def rule12(sentence, keyword):
    # 匹配模式: ...因为..., ...所以, ...
    return pattern.rule_skcscskcs(sentence, keyword, comma3=True)

示例#3

def rule21(sentence, keyword):
    # 匹配模式: ...之所以..., ...是因为...
    return pattern.rule_skcscskcs(sentence, keyword, reverse=True)

示例#4

def rule13(sentence, keyword):
    # 匹配模式: ...因为..., ...所以...
    return pattern.rule_skcscskcs(sentence, keyword)

示例#5

def rule101(sentence, keyword):
    # 匹配模式: ...不仅..., ...还...
    return pattern.rule_skcscskcs(sentence, keyword)

示例#6

def rule23(sentence, keyword):
    # 匹配模式: ...只有..., ...才能...
    return pattern.rule_skcscskcs(sentence, keyword)

示例#7

def rule22(sentence, keyword):
    # 匹配模式: ...只有..., ...才能, ...
    return pattern.rule_skcscskcs(sentence, keyword, comma3=True)

示例#8

文件： r_assumption.py 项目： hyren01/qingdao-dev-python

def rule11(sentence, keyword):
    # 匹配模式: ...如果..., ...就...
    return pattern.rule_skcscskcs(sentence, keyword)