def alloc_pty(ctx, f, *args, **kwargs):
pid, fd = pty.fork()
if pid == pty.CHILD:
tty = os.ttyname(0)
sys.stdin = open(tty, 'r')
sys.stdout = open(tty, 'w')
sys.stderr = open(tty, 'w')
# alternative way of doing ^ is to do:
# kwargs["stdout"] = open(tty, 'w')
# kwargs["stderr"] = open(tty, 'w')
# kwargs["stdin"] = open(tty, 'r')
# Create a new client for the child process to avoid concurrency issues
client = get_client()
f(client, *args, **kwargs)
sys.exit(0)
else:
ctx.pty = fd
util.set_pty_size(
ctx.pty,
(ctx.rows, ctx.cols)
)
ctx.pid = pid
util.wait(ctx.pty, timeout=5)
time.sleep(1) # give the terminal some time to print prompt
# util.exit_code can be called only once
ctx.exit_code = util.exit_code(ctx.pid, timeout=5)
if ctx.exit_code != 0:
raise Exception("child process did not finish correctly")
def step_impl(ctx):
pid, fd = pty.fork()
if pid == pty.CHILD:
tty = os.ttyname(0)
sys.stdin = open(tty, 'r')
sys.stdout = open(tty, 'w')
sys.stderr = open(tty, 'w')
try:
dockerpty.start(ctx.client, ctx.container)
except Exception as e:
raise e
os._exit(1)
else:
os._exit(0)
else:
try:
tty = os.ttyname(fd)
except OSError as ex:
# Not supported on OS X. But since we're not using this
# TTY name anyway, let the test pass.
tty = 'OSX'
ctx.pty = fd
util.set_pty_size(
ctx.pty,
(ctx.rows, ctx.cols)
)
ctx.pid = pid
util.wait(ctx.pty, timeout=5)
time.sleep(1) # give the terminal some time to print prompt
def alloc_pty(ctx, f, *args, **kwargs):
pid, fd = pty.fork()
if pid == pty.CHILD:
tty = os.ttyname(0)
sys.stdin = open(tty, 'r')
sys.stdout = open(tty, 'w')
sys.stderr = open(tty, 'w')
# alternative way of doing ^ is to do:
# kwargs["stdout"] = open(tty, 'w')
# kwargs["stderr"] = open(tty, 'w')
# kwargs["stdin"] = open(tty, 'r')
# Create a new client for the child process to avoid concurrency issues
client = get_client()
f(client, *args, **kwargs)
sys.exit(0)
else:
ctx.pty = fd
util.set_pty_size(ctx.pty, (ctx.rows, ctx.cols))
ctx.pid = pid
util.wait(ctx.pty, timeout=5)
time.sleep(1) # give the terminal some time to print prompt
# util.exit_code can be called only once
ctx.exit_code = util.exit_code(ctx.pid, timeout=5)
if ctx.exit_code != 0:
raise Exception("child process did not finish correctly")
def step_impl(ctx):
pid, fd = pty.fork()
if pid == pty.CHILD:
tty = os.ttyname(0)
sys.stdin = open(tty, 'r')
sys.stdout = open(tty, 'w')
sys.stderr = open(tty, 'w')
try:
dockerpty.start(ctx.client, ctx.container)
except Exception as e:
raise e
os._exit(1)
else:
os._exit(0)
else:
tty = os.ttyname(fd)
ctx.pty = fd
util.set_pty_size(
ctx.pty,
(ctx.rows, ctx.cols)
)
ctx.pid = pid
util.wait(ctx.pty, timeout=5)
time.sleep(1) # give the terminal some time to print prompt
def step_impl(ctx):
pid, fd = pty.fork()
if pid == pty.CHILD:
tty = os.ttyname(0)
sys.stdin = open(tty, 'r')
sys.stdout = open(tty, 'w')
sys.stderr = open(tty, 'w')
try:
dockerpty.start(ctx.client, ctx.container)
except Exception as e:
raise e
os._exit(1)
else:
os._exit(0)
else:
tty = os.ttyname(fd)
ctx.pty = fd
util.set_pty_size(
ctx.pty,
(ctx.rows, ctx.cols)
)
ctx.pid = pid
util.wait(ctx.pty, timeout=5)
def alloc_pty(ctx, f, *args, **kwargs):
pid, fd = pty.fork()
if pid == pty.CHILD:
tty = os.ttyname(0)
sys.stdin = open(tty, 'r')
sys.stdout = open(tty, 'w')
sys.stderr = open(tty, 'w')
# alternative way of doing ^ is to do:
# kwargs["stdout"] = open(tty, 'w')
# kwargs["stderr"] = open(tty, 'w')
# kwargs["stdin"] = open(tty, 'r')
# Create a new client for the child process to avoid concurrency issues
client = get_client()
f(client, *args, **kwargs)
sys.exit(0)
ctx.pty = fd
util.set_pty_size(
ctx.pty,
(ctx.rows, ctx.cols)
)
ctx.pid = pid
ctx.exit_code = -1
util.wait(ctx.pty, timeout=5)