示例#1
0
def alloc_pty(ctx, f, *args, **kwargs):
    pid, fd = pty.fork()

    if pid == pty.CHILD:
        tty = os.ttyname(0)

        sys.stdin = open(tty, 'r')
        sys.stdout = open(tty, 'w')
        sys.stderr = open(tty, 'w')

        # alternative way of doing ^ is to do:
        # kwargs["stdout"] = open(tty, 'w')
        # kwargs["stderr"] = open(tty, 'w')
        # kwargs["stdin"] = open(tty, 'r')

        # Create a new client for the child process to avoid concurrency issues
        client = get_client()
        f(client, *args, **kwargs)
        sys.exit(0)
    else:
        ctx.pty = fd
        util.set_pty_size(
            ctx.pty,
            (ctx.rows, ctx.cols)
        )
        ctx.pid = pid
        util.wait(ctx.pty, timeout=5)
    time.sleep(1)  # give the terminal some time to print prompt

    # util.exit_code can be called only once
    ctx.exit_code = util.exit_code(ctx.pid, timeout=5)
    if ctx.exit_code != 0:
        raise Exception("child process did not finish correctly")
示例#2
0
def step_impl(ctx):
    pid, fd = pty.fork()

    if pid == pty.CHILD:
        tty = os.ttyname(0)
        sys.stdin = open(tty, 'r')
        sys.stdout = open(tty, 'w')
        sys.stderr = open(tty, 'w')

        try:
            dockerpty.start(ctx.client, ctx.container)
        except Exception as e:
            raise e
            os._exit(1)
        else:
            os._exit(0)
    else:
        try:
            tty = os.ttyname(fd)
        except OSError as ex:
            # Not supported on OS X. But since we're not using this
            # TTY name anyway, let the test pass.
            tty = 'OSX'
        ctx.pty = fd
        util.set_pty_size(
            ctx.pty,
            (ctx.rows, ctx.cols)
        )
        ctx.pid = pid
        util.wait(ctx.pty, timeout=5)
    time.sleep(1) # give the terminal some time to print prompt
示例#3
0
def alloc_pty(ctx, f, *args, **kwargs):
    pid, fd = pty.fork()

    if pid == pty.CHILD:
        tty = os.ttyname(0)

        sys.stdin = open(tty, 'r')
        sys.stdout = open(tty, 'w')
        sys.stderr = open(tty, 'w')

        # alternative way of doing ^ is to do:
        # kwargs["stdout"] = open(tty, 'w')
        # kwargs["stderr"] = open(tty, 'w')
        # kwargs["stdin"] = open(tty, 'r')

        # Create a new client for the child process to avoid concurrency issues
        client = get_client()
        f(client, *args, **kwargs)
        sys.exit(0)
    else:
        ctx.pty = fd
        util.set_pty_size(ctx.pty, (ctx.rows, ctx.cols))
        ctx.pid = pid
        util.wait(ctx.pty, timeout=5)
    time.sleep(1)  # give the terminal some time to print prompt

    # util.exit_code can be called only once
    ctx.exit_code = util.exit_code(ctx.pid, timeout=5)
    if ctx.exit_code != 0:
        raise Exception("child process did not finish correctly")
def step_impl(ctx):
    pid, fd = pty.fork()

    if pid == pty.CHILD:
        tty = os.ttyname(0)
        sys.stdin = open(tty, 'r')
        sys.stdout = open(tty, 'w')
        sys.stderr = open(tty, 'w')

        try:
            dockerpty.start(ctx.client, ctx.container)
        except Exception as e:
            raise e
            os._exit(1)
        else:
            os._exit(0)
    else:
        tty = os.ttyname(fd)
        ctx.pty = fd
        util.set_pty_size(
            ctx.pty,
            (ctx.rows, ctx.cols)
        )
        ctx.pid = pid
        util.wait(ctx.pty, timeout=5)
    time.sleep(1) # give the terminal some time to print prompt
示例#5
0
def step_impl(ctx):
    pid, fd = pty.fork()

    if pid == pty.CHILD:
        tty = os.ttyname(0)
        sys.stdin = open(tty, 'r')
        sys.stdout = open(tty, 'w')
        sys.stderr = open(tty, 'w')

        try:
            dockerpty.start(ctx.client, ctx.container)
        except Exception as e:
            raise e
            os._exit(1)
        else:
            os._exit(0)
    else:
        tty = os.ttyname(fd)
        ctx.pty = fd
        util.set_pty_size(
            ctx.pty,
            (ctx.rows, ctx.cols)
        )
        ctx.pid = pid
        util.wait(ctx.pty, timeout=5)
示例#6
0
def alloc_pty(ctx, f, *args, **kwargs):
    pid, fd = pty.fork()

    if pid == pty.CHILD:
        tty = os.ttyname(0)

        sys.stdin = open(tty, 'r')
        sys.stdout = open(tty, 'w')
        sys.stderr = open(tty, 'w')

        # alternative way of doing ^ is to do:
        # kwargs["stdout"] = open(tty, 'w')
        # kwargs["stderr"] = open(tty, 'w')
        # kwargs["stdin"] = open(tty, 'r')

        # Create a new client for the child process to avoid concurrency issues
        client = get_client()
        f(client, *args, **kwargs)
        sys.exit(0)

    ctx.pty = fd
    util.set_pty_size(
        ctx.pty,
        (ctx.rows, ctx.cols)
    )
    ctx.pid = pid
    ctx.exit_code = -1
    util.wait(ctx.pty, timeout=5)